E PORTFOLIO BUILDING SCIENCE AND SERVICES

Page 1

BACHELOR OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304) E PORTFOLIO NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH
BACHELOR OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304) ASSIGNMENT 1: LIGTHING AND VAC DESIGN FOR COMFORT NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH

1.1 Current Condition

This project's chosen location is the master bedroom of the unit, which also happens to be my bedroom.

My bedroom is divided by 3 area, bed area, study area, and wardrobe. In this bedroom, there is a window that faces north. The sunlight is so bright in the morning and afternoon that I don't need to turn on the lights. According to the picture, the bed area has 644 lux in the afternoon, which is higher than any other area (as shown in figure 1.1). Meanwhile, the study has 439 lux, and the wardrobe has 274 lux (as shown in figures 1.2 and 1.3)

Figure 1.1

Figure 1.2 Figure 1.3

When it's night and the lights are switched on, the bed area has 50 lux (as shown in figure 1.4), the study area has 13 lux (as shown in figure 1.5), and the wardrobe area has 9 lux (as shown in figure 1.6).

Figure 1.4

Figure 1.5

Figure 1.6

The light fixture in this bedroom is surface mounted light (as shown in figure 1.7) and fluorescent tube light that located below the floating shelf at the study area (as shown in figure 1.8)

Figure 1.7

Figure 1.8

The air conditioner in this bedroom is Electrolux ESM09CRD-C1 1.0 HP (as shown in figure 1.9). The air conditioner is often turned on for 10 hours every day.

Figure 1.9

1.2 Dissatisfactory Issues

The first issue with this room is that the lighting is weak, so even when the light is turned on, it does not appear to be very bright (as shown in figure 2.1).

Figure 2.1

The second issue is the lamp is not in the centre of the room, the light is not distributed evenly around the area (as shown in figure 2.2).

Figure 2.2

The third issue is there is no lighting in the wardrobe area, so I can't see clearly in there if it becomes dark (as shown in figure 2 3).

Figure 2.3

The fourth issue is that I rarely use the ceiling fan. Because this room has a window, I don't think a ceiling fan is necessary because I can simply open the window to get some fresh air (as shown in figure 2.4)

Figure 2.4

The fifth issue is the location of the air conditioner. The air conditioner is currently facing the bedroom door, so the wind is blowing there rather than throughout the room (as shown in figure 2.5)

Figure 2.5

1.3 Introduction to New Revised Layout Plan

The change in this room involved adding, removing, and relocating items that had previously been mentioned.

The first one is changing the lighting from surface mounted to LED round downlight. The light that will be used is Philips LED 10W 6” Meson Round Downlight.

Figure 3.1

3.2

Figure
Specification: • Housing: Synthetic • Housing Paint: White • Cut Out Size (mm): 150D • Dimension (mm): 165D x 47H • Wattage: 10W
Lumen Output: 900lm • Voltage: 220-240V • Colour Temperature: 4000K Cool White • Colour Rendering Index: 80Ra • Lifetime: 15,000hrs • Dimmable: No

The second solution is to relocate the lamp to the middle of the room (as shown in figure 3.3). The light that would be emitted will be more equal if the light is moved to the centre.

Figure 3.3

The third solution is adding a LED round downlight at the wardrobe are (as shown in figure 3.4). The addition of a light fixture in the wardrobe area will make it easier for me to see the wardrobe, especially at night. The light that will be used is Pila 12W 5” Round LED Downlight (as shown in figure 3.5)

Figure 3.4

Figure 3.5 Specification:

• Size: 5"
• Wattage: 12W
• Lumen: 900lm
• Shape: Round • Colour: Cool White 4000K
• Input Voltage: AC220-240V 50/60Hz • 80+ CRI • Cut-out size: 125mm/150mm • 12,000 Hours Life • 80% energy saving • Power Factor: 0.5 • No UV&IR radiation

The fourth option is to remove the ceiling fan. As previously stated, I rarely use the ceiling fan, therefore it's best to remove it. Furthermore, instead of a fan, an LED light will be installed in that location (the second solution). The last solution is to move the air conditioner to the opposite wall (as shown in figure 3.6 and figure 3.7). The wind will fill the entire space at that position.

Figure 3.6

Figure 3.7

1.4 Energy Calculation Space Area Total Btu/hr 18,5m2 x 700 = 12950 Btu/hr 12950 Btu/hr + 1400 Btu/hr + 147
= Occupant 14,497Btu/hr 2people x 700 = 1400 Btu/hr Air Conditioner Sizing Heat From Electrical Equipment 14,497 Btu/hr : 9800 = 1.47 hp = 1.5 hp LED Downlight: 22 Watt Fluorescent Tube: 20 Watt Total: 42 Watt x 3.5 = 147 Btu/hr
Btu/hr

Based on the calculations above, the air conditioner required for this room is a 1.5 hp unit. As a result, the air conditioner will be replaced with a 1.5 hp unit. Air conditioner that will be used in the room is Samsung 1.5HP S-Essential Air Conditioner (as shown in figure 4.1).

Figure 4.1

Specification:

Capacity

• Capacity (Cooling, Btu/hr)12000 Btu/hr

• Capacity (Cooling, Min - Max, Btu/hr)3,100 ~ 13,000 Btu/hr

• Capacity (Cooling, kW)3.52 kW

• Capacity (Cooling, Min - Max, kW)0.91 ~ 3.81 kW

Energy Efficiency

• EER (Cooling, W/W)3.30 W/W

• EER (Cooling, Btu/hW)11.27 Btu/hW

• CSPF5.1

• Energy Star Rating (Cooling)4 Star

Noise Level

• Noise Level (Indoor, High/Low, dBA)40 / 20 dBA

• Noise Level (Outdoor, High/Low, dBA)48 dBA

Electrical Data

• PowerSource(Φ/V/Hz)1 / 230 / 50

• Power Consumption (Cooling, W)1065 W

• Operating Current (Cooling, A)5.2 A

Physical specification

• Gross Dimension (Indoor, WxHxD)883*261*358 mm

• Gross Dimension (Outdoor, WxHxD)778*550*331 mm

• Net Dimension (Indoor, WxHxD)820*285*213 mm

• Net Dimension (Outdoor, WxHxD)660*475*242 mm

• Gross Weight (Indoor, kg)9.6 kg

• Gross Weight (Outdoor, kg)21.9 kg

• Net Weight (Indoor, kg)8.2 kg

• Net Weight (Outdoor, kg)20.2 kg

• Loading Quantity (20/40/40Hft without Pipe)123 / 253 / 285

Air Flow

• Air Direction Control (Up/Down)Auto

• Air Direction Control (Left/Right)Manual

• Air Flow Control Step (Cool/Fan)5/4

List

1.5 Bill of Quantities

of New Products

Item Description Store Address

L1 Philips LED 10W 6” Meson Round Downlight Cima Lighting Sdn Bhd Jalan 215, Seksyen 51, 46050 Petaling Jaya, Selangor L2 Pila 12W 5” Round LED Downlight

A1 Samsung 1.5HP S-Essential Air Conditioner Senheng Electric Sdn Bhd shorturl.at/cxMTY

Bill of Quantities

Item Description Unit Quantity Rate (RM) Total (RM) Note

L1 Philips LED 10W 6” Meson Round Downlight nos 1 19.50 19.50 4000K Cool White L2 Pila 12W5”RoundLED Downlight nos 1 10.90 10.90 4000K Cool White L3 Samsung 1.5HP SEssential Air Conditioner nos 1 1,499.00 1,499.00Total: RM 1,529.40

2.1 Current Layout Plan

2.2 Revised Layout Plan

Revised Perspective 3D View

2.3
3320 3000 2800 1920 1650 850 12502200 DESK SINGLEBED SINGLEBED TOTHE BATHROOM OUTSIDE SHELF LEGEND SYMBOL DESCRIPTION QUANTITY SWITCH 2
3
1
1
LAMP 1
LAMP 1
1
CURRENTFLOORPLAN MSSHARON TEH BSSC/ASS1/CLP ASSHOWN PUTRIARDHEA ANNISA 15OCT2022 ASSIGNMENT1 W1 D1 D2 W1 D2 C LP CURRENTLAYOUTPLAN SCALE1:30 D1
SWITCHEDSOCKET
CEILINGFAN
AIRCONDITIONER
CEILINGMOUNTED
FLUORESCENTTUBE
WINDOW
BEDROOMDOOR 1 BATHROOMDOOR 1
3320 3000 2800 1920 1650 850 12502200 DESK SINGLEBED SINGLEBED TOTHE BATHROOM OUTSIDE SHELF LEGEND SYMBOL DESCRIPTION QUANTITY SWITCH 2 SWITCHEDSOCKET 3 AIRCONDITIONER 1 6"MESONLEDDOWN LIGHT 1 5"MESONLEDDOWN LIGHT 1 FLUORESCENTTUBE LAMP 1 WINDOW 1 BEDROOMDOOR 1 BATHROOMDOOR 1 REVISEDFLOORPLAN MSSHARON TEH BSSC/ASS1/RLP ASSHOWN PUTRIARDHEA ANNISA 15OCT2022 ASSIGNMENT1 W1 D2 R LP REVISEDLAYOUTPLAN SCALE1:30 D1 D1 W1 D2
BACHELOR OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304) ASSIGNMENT 2: INDOOR COMFORT DESIGN AND INVENTION NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH

ASSIGNMENT 2A

LAYOUT PLAN

TEMPERATURE CALCULATION

WALL 1

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

ΔT

07.00 am 77°F 78.8°F 1.8°F

12.00 pm 87.8°F 78.8°F 10°F

17.00 pm 82.4°F 78.8°F 3.6°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

Based on the temperature, I believe it all makes sense. The temperature feels cool and shady for 7 a.m. It was hot and humid at 12 p.m. It rained at 5 p.m., making the weather cold and windy.

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

ΔT

07.00 am 73.4°F 78.8°F 5.4°F

12.00 pm 73.4°F 78.8°F 5.4°F 17.00 pm 73.4°F 78.8°F 5.4°F

INDOOR TEMPERATURE OUTSIDE TEMPERATURE

WALL 3

TIME

OUTSIDE TEMPERATURE INSIDE TEMPERATURE ΔT

07.00 am 69.8°F 78.8°F 9°F 12.00 pm 69.8°F 78.8°F 9°F 17.00 pm 69.8°F 78.8°F 9°F

INDOOR TEMPERATURE OUTSIDE TEMPERATURE

WALL
2

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE DIFFERENCES TEMPERATURE

07.00 am 72.23°F 78.8°F 6.57°F

12.00 pm 82.22°F 78.8°F 3.42°F

17.00 pm 79.88°F 78.8°F 1.08°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

Based on the recorded temperature above, I feel it all makes sense. My unit is on the 19th level, so it seems cooler than the outside temperature.

WALL 4

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

DIFFERENCES TEMPERATURE

07.00 am 73.76°F 78.8°F 5.04°F

12.00 pm 83.48°F 78.8°F 4.68°F

17.00 pm 79.52°F 78.8°F 0.72°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

Based on the temperature recorded above, I feel it all makes sense. The temperature in the bathroom is slightly higher than the other room, which is the ideal temperature for a bathroom.

WALL 5

R-VALUES TABLE

AREA:

mm

mm -> 5.8 ft

9.5

mm -> 6.3 ft

= 104.5

67.96

WALL 1 (NORTH)
3320
-> 11 ft 1780
2900 mm ->
ft 1935
Wall include window: 11 ft x 9.5 ft
ft2 Window: 5.8 ft x 6.3 ft =36.54 ft2 W1: 104.5 ft 2 – 36.54 ft 2 =
ft2 R-VALUE: Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU Single Pane Window: 1 ft2·°F·h/BTU HEAT TRANSFER OF WALL 07.00 am 12.00 pm 17.00 pm q = A x T R = 67.96 ft 2 x 1.8°F 0 48 ft2·°F·h/BTU = 254.85 Btu/hr q = A x T R = 67.96 ft 2 x 10°F 0 48 ft2·°F·h/BTU = 1,415.84 Btu/hr q = A x T R = 67.96 ft 2 x 3.6°F 0 48 ft2·°F·h/BTU = 509.70 Btu/hr

HEAT TRANSFER OF WINDOW

07.00 am

12.00 pm 17.00 pm q = A x T R

= 67.96 ft 2 x 1.8°F 1 ft2·°F·h/BTU = 122.33 Btu/hr

HEAT TRANSFER TOTAL

q = A x T R

= 67.96 ft 2 x 10°F 1 ft2·°F·h/BTU = 679.60 Btu/hr

q = A x T R

= 67.96 ft 2 x 3.6°F 1ft2·°F·h/BTU = 244.65 Btu/hr

07.00 am 12.00 pm 17.00 pm q = 254.85 Btu/hr + 122.33 Btu/hr = 377.2 Btu/hr

q = 1,415.84 Btu/hr + 679.60 Btu/hr = 2,095.44 Btu/hr

WALL 2 (EAST)

AREA: 3000 mm -> 9.8 ft 2900 mm -> 9.5 ft W2: 9.8 ft x 9.5 ft = 93.1 ft2

q = 509.70 Btu/hr + 244.65 Btu/hr = 754.35 Btu/hr

R-VALUE:

Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU

07.00 am 12.00 pm 17.00 pm

q = A x T R

= 93.1 ft 2 x 5.4°F 0.48 ft2·°F·h/BTU = 1,047.40 Btu/hr

WALL 3 (SOUTH)

q = A x T R

= 93.1 ft 2 x 5.4°F 0.48 ft2·°F·h/BTU = 1,047.40 Btu/hr

q = A x T R

= 93.1 ft 2 x 5.4°F 0.48 ft2·°F·h/BTU = 1,047.40 Btu/hr

AREA:

2800 mm -> 9.2 ft

W3: 9.2 ft x 9.5 ft = 87.4 ft2

2900 mm -> 9.5 ft 2.8 ft x 9.5 ft = 26.6 ft2

850 mm -> 2.8 ft 87.4 ft2 + 26.6 ft2 = 114 ft2

R-VALUE:

Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU

07.00 am 12.00 pm 17.00 pm

q = A x T R = 114 ft2x 9°F 0.48 ft2·°F·h/BTU = 2,137.50 Btu/hr

WALL 4

q = A x T R

= 114 ft2x 9°F 0.48 ft2·°F·h/BTU = 2,137.50 Btu/hr

q = A x T R = 114 ft2x 9°F 0.48 ft2·°F·h/BTU = 2,137.50 Btu/hr

AREA:

1850 mm -> 6 ft 900 mm -> 3 ft

2900 mm -> 9.5 ft 2100 mm -> 6.9 ft 1392 mm -> 4.5 ft

Right wall: 6 ft x 9.5 ft =57 ft2

Left wall include door: 4.5 ft x 9.5 ft = 42.75 ft2

Door: 3 ft x 6.9 ft = 20 7 ft2

Left wall exclude door: 42.75 ft2 – 20.7 ft2 = 22.05 ft2

W4: 57 ft2 + 22.05 ft2 = 79.05 ft2

R-VALUE:

Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU

Door: 3.03 ft2·°F·h/BTU

HEAT TRANSFER OF WALL

07.00 am 12.00 pm 17.00 pm q = A x T R = 79.05 ft2x 6.57°F 0.48 ft2·°F·h/BTU = 1,082 Btu/hr

q = A x T R = 79.05 ft2x 3.42°F 0.48 ft2·°F·h/BTU = 563.23 Btu/hr

q = A x T R = 79.05 ft2 x 1.08°F 0.48 ft2·°F·h/BTU = 177.86 Btu/hr

HEAT TRANSFER OF DOOR

07.00 am 12.00 pm 17.00 pm q = A x T R = 79.05 ft2x 6.57°F 3.03 ft2·°F·h/BTU = 171.40 Btu/hr

q = A x T R = 79.05 ft2x 3.42°F 3.03 ft2·°F·h/BTU = 89.22 Btu/hr

HEAT TRANSFER TOTAL

q = A x T R = 79.05 ft2 x 1.08°F 3.03 ft2·°F·h/BTU = 28.18 Btu/hr

07.00 am 12.00 pm 17.00 pm q = 1,082 Btu/hr + 171.40 Btu/hr = 1,253.40 Btu/hr

q = 563.23 Btu/hr + 89.22 Btu/hr = 652.45 Btu/hr

q = 177.86 Btu/hr + 28.18 Btu/hr = 206.04 Btu/hr

WALL 5 (WEST)

AREA:

2200 mm -> 7.2 ft 2100 mm -> 6.9 ft

2900 mm -> 9.5 ft 759 mm -> 2.5 ft

1250 mm -> 4.1 ft

Right wall: 7.2 ft x 9.5 ft = 68.40 ft2

Left wall include door: 4.1 ft x 9.5 ft = 38.95 ft2

Door: 2.5 ft x 6.9 ft = 17.25 ft2

Left wall exclude door: 38.95 ft2 – 17.25 ft2 = 22.70 ft2

W5: 68.40 ft2 + 22.70 ft2 = 91.1 ft2

R-VALUE:

Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU Door: 3.03 ft2·°F·h/BTU

HEAT TRANSFER OF WALL

07.00 am 12.00 pm 17.00 pm q = A x T R = 91.1 ft2x 5.04°F 0.48 ft2·°F·h/BTU = 956.55 Btu/hr

HEAT TRANSFER OF DOOR

q = A x T R

= 91.1 ft2x 4.68°F 0.48 ft2·°F·h/BTU = 888.23 Btu/hr

q = A x T R = 91.1 ft2 x 0.72°F 0.48 ft2·°F·h/BTU = 136.65 Btu/hr

07.00 am 12.00 pm 17.00 pm q = A x T R = 91.1 ft2x 5.04°F 3.03 ft2·°F·h/BTU = 151.53 Btu/hr

q = A x T R = 91.1 ft2x 4.68°F 3.03 ft2·°F·h/BTU = 140.70 Btu/hr

q = A x T R = 91.1 ft2 x 0.72°F 3.03 ft2·°F·h/BTU = 21.65 Btu/hr

HEAT TRANSFER TOTAL 07.00 am 12.00 pm 17.00 pm q = 956.55 Btu/hr + 151.53 Btu/hr = 1,108.03 Btu/hr

q = 888.23 Btu/hr + 140.70 Btu/hr = 228.93 Btu/hr

q = 136.65 Btu/hr + 21.65 Btu/hr = 158.3 Btu/hr

CONCLUSION

Wall Number Time Result

Highest Heat Transfer Wall 3 07.00, 12.00, 17.00 2,137.50 Btu/hr Lowest Heat Transfer Wall 5 17.00 158.3 Btu/hr

ASSIGNMENT 2B Product: Magnetic Roman Shade Initial Sketch Materials 1. Cotton Linen
is highly breathable, soft, and a natural insulator.
are
moving air and moisture naturally. It is valued
its
to keep
and trap
colde
2. Magnetic Tape 3. Round Magnet
(Linen
It’s fibers
hollow,
for
ability
cool in the summer months
warmth in
weather.)

Size

Unfolded

Width: 50 cm Height: 150 cm

Folded

Width: 50 cm Height: 44.2 cm

Tools 1. Needle 2. Thread 3. Scissor 4. Measuring Tape 5. Iron 6. Sewing Pin 7. Pencil

Construction

2. Fold edges of the fabric to the size (54cm x 155 cm). (horizontal 2 cm, vertical 2.5 cm)

1. Cut the fabric according

2. Iron the folded edges

3. Pin it then sew.

4. Measure the height for the

5. Cut the magnetic tape with folded position, then mark it. of approximately 50 cm.

6. Stick the tape to the cutted fabric

7. Insert round magnet in edges (left and right) and in the middle.

8. Sew the fabric that has been taped 9. Measure and cut fabric by magnetic tape. for pouches.

10. Fold and sew edges of the pouch.

11. Sew the pouch to the shade.

Cost

• Cotton Linen Fabric: RM 20.50

RM 20.50 : 23,250 cm2 = RM 0.0009/cm2)

Used: 10,130 cm2 x RM 0.0009= RM 9.1

• Magnetic Tape: RM 10.50

RM 10.50 : 300 cm = RM 0.035

Used: 50 cm x 3 = 150 cm x RM 0.035 = RM 5.25

• Magnet: RM 7.80/20 pcs

RM 7.80 : 20 pcs = RM 0.39

Used: 13 pcs x RM 0.39 = RM 5.07

Total Cost: RM 9.1 + RM 5.25 + RM 5.07 = RM 19.42

Result

Reflection

Through this assignment, I learned that there are many ways to minimalize heat transfer. A lot of simple materials that can be used, even a bubble wrap. I amaze with all of the prototype that my classmates made because all so cool and out of the box. In my opinion, Janelle prototype is really good. I like the ideas and the visual of the product.

When I made this product, there is an error that made the magnet tape is not attach to each other. After thinking some solution, I put the round magnet in each edges and in the middle. I personally think that this assignment its really useful and fun. Students can share their ideas and skills.

Design Value

Design Value = Market Value – Material Cost

Market Value: 30 + 35 + 25 + 30 + 30 + 35 + 40 + 25 + 40 + 30 + 10 + 15 + 20 + 30 + 35 + 30 + 20 + 25 + 30 + 35 + 50 21 = RM 29.5

Design Value = RM 29.5 – RM 19.42 = RM 10.08

OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304)
NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH
BACHELOR
FINAL PROJECT: DESIGN OF BULDING SERVICES (IAD 3 INTEGRATED)

TASK 1A: SITE SELECTION & QUALITATIVE DESCRIPTION OF INCOPERATED BUILDING SERVICES

This building is located at Tamarind Square, Cyberjaya. The purpose of this building is to sharing awareness about fast fashion There will be several activities to reduce fast fashion, one of which is upcycling clothes from worn clothes.

Selected Area of Site: Level 4 (Thrift Store)

Specific Activities and Building Services of Selected Area:

1. Thrift Store

Thrift store is an area for selling second-hand clothes. As a clothing store, this room need to have a proper lighting and also air conditioner since it’s a indoor area. Inside the thrift store, they also have a toilet and fitting room. The fitting room used for the visitor to try on the clothes that they want to buy.

Lighting

1. LED Downlight

LED downlight will be used at all the area, but with a different specification per room.

For the thrift store and fitting room LED Downlight that will be used is downlight with 900 lumens and with colour temperature 4000k cool white. The reason why I choose white colour is because the space itself is a clothing store, lighting will affect the colour of the clothes. So, it will be better to use the white colour one.

For toilet, LED Downlight that will be used is downlight with 940 lumens and with colour temperature 3000k warm white. I decide to use the warm white because warm white lighting is calming and relaxing, it is best for bathrooms

Specifications:

1. Philips LED 10W 6” Meson Round Downlight

• Housing: Synthetic • Housing Paint: White • Cut Out Size (mm): 150D • Dimension (mm): 165D x 47H • Wattage: 10W • Lumen Output: 900lm • Voltage: 220-240V

• Colour Temperature: 4000K Cool White

• Lifetime: 15,000hrs

• Dimmable: No

TASK 1B: DESIGNING AND JUSTIFICATION OF BUILDING SERVICES SELECTION & LOCATION
• Colour Rendering Index: 80Ra

2. Philips LED 10W D150 6" Eyecomfort Meson Round Downlight

Specifications:

2. Track Light

To highlight the items visually, track lights are usually applied in the boutiques to make a difference in stimulating the purchase behaviour Track light is mounted to ceiling and the light will be projected to the clothing rack.

IKEA BÄVE LED Ceiling Track

Specifications:

• Built in LED light source.

• The light source has a lifetime of approx. 25,000 hours. This corresponds to about 20 years if the lamp is on for 3 hours per day.

• Light colour: warm white (2700 Kelvin).

• Not dimmable.

• Special waste handling may be required. Please contact your local authorities for more information.

• Wired-in installation

• Luminous flux: 900 lm

• Length: 78 cm

• Width: 3 cm

• Shade diameter: 3 cm

Lighting

• 6 Bulbs: 60 watt

• 2 Track light: 22 watt

Power: 11 W VAC Air Conditioner Calculation:
Space Area 67 3 m2 x 700 = 47,110 Btu/hr
Occupant 15 people x 700 = 10,500 Btu/hr
Heat from electrical equipment

82 watt x 3.5 = 287 Btu/hr

• Total Btu/hr:

47,110 Btu/hr + 10,500 Btu/hr + 287 Btu/hr = 57.897 Btu/hr

• Air conditioner sizing

57.897 Btu/hr / 9800 Btu/hr = 5.9 hp = 6 hp

Daikin Ecoking Prestige Ceiling Exposed Non-Inverter 6.0HP

Specifications:

Lighting Illuminance for Store:

Area: 67.3 m2

Total light: 6 downlight (900 lm each)

E = lm : A = 5400 lm : 67.3 m2 = 802.4 lm/m 2

Lighting Illuminance for Toilet: Area: 2.75 m2 Total light: 940 lm E = lm : A = 940 lm : 2.75 m 2 = 341.82 lm/m 2

Lighting Illuminance for Fitting Room: Area: 2.2 m 2

Total light: 900 lm

E = lm : A =900 lm : 2.2 m 2 = 409.1 lm/m2

Energy Use

Lighting:

Downlight: 10 watt x 9 pcs x 8 hours : 1000 = 0,72 kWh

Track light: 11 watt x 1 pc x 8 hours : 1000 = 0,0088 kWh 0.07288 kWh x 30 days = 21.864 kWh

AC: 6,414 watt x 10 hours : 1000 = 64.14 kWh x 30 days = 1,924.2 kWh

Total: = 21.864 kWh/month + 1,924.2 kWh/month

= 23.788 kWh/month

4TH FLP 4THFLOORLAYOUTPLAN 3250 2470 2920 3058 3565 3365 3494 3245 1757 1735 3021 4523 2821 2000 1540 1634 5980 4987 1925 1572 1119 NOTE: DRAWNBY:PUTRIARDHEA IDNO:0346459 SUBJECT:BScS ASSIGNMENT: SCALE:ASSHOWN DATE: LECTURER:MSSHARON FINALPROJECT 4THFLOORLAYOUTPLAN SCALE1:100
NOTE: DRAWNBY:PUTRIARDHEA IDNO:0346459 SUBJECT:BScS ASSIGNMENT: SCALE:ASSHOWN DATE: LECTURER:MSSHARON FINALPROJECT BATHROOMSECTION

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