E PORTFOLIO BUILDING SCIENCE AND SERVICES

BACHELOR OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304)

E PORTFOLIO

NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH

BACHELOR OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304)

ASSIGNMENT 1: LIGTHING AND VAC DESIGN FOR COMFORT

NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH

1.1 Current Condition This project's chosen location is the master bedroom of the unit, which also happens to be my bedroom.

My bedroom is divided by 3 area, bed area, study area, and wardrobe. In this bedroom, there is a window that faces north. The sunlight is so bright in the morning and afternoon that I don't need to turn on the lights. According to the picture, the bed area has 644 lux in the afternoon, which is higher than any other area (as shown in figure 1.1). Meanwhile, the study has 439 lux, and the wardrobe has 274 lux (as shown in figures 1.2 and 1.3).

Figure 1.1

Figure 1.2

Figure 1.3

When it's night and the lights are switched on, the bed area has 50 lux (as shown in figure 1.4), the study area has 13 lux (as shown in figure 1.5), and the wardrobe area has 9 lux (as shown in figure 1.6).

Figure 1.4

Figure 1.5

Figure 1.6

The light fixture in this bedroom is surface mounted light (as shown in figure 1.7) and fluorescent tube light that located below the floating shelf at the study area (as shown in figure 1.8)

Figure 1.7

Figure 1.8

The air conditioner in this bedroom is Electrolux ESM09CRD-C1 1.0 HP (as shown in figure 1.9).

The air conditioner is often turned on for 10 hours every day.

Figure 1.9

1.2 Dissatisfactory Issues The first issue with this room is that the lighting is weak, so even when the light is turned on, it does not appear to be very bright (as shown in figure 2.1).

Figure 2.1 The second issue is the lamp is not in the centre of the room, the light is not distributed evenly around the area (as shown in figure 2.2).

Figure 2.2 The third issue is there is no lighting in the wardrobe area, so I can't see clearly in there if it becomes dark (as shown in figure 2.3).

Figure 2.3

The fourth issue is that I rarely use the ceiling fan. Because this room has a window, I don't think a ceiling fan is necessary because I can simply open the window to get some fresh air (as shown in figure 2.4).

Figure 2.4 The fifth issue is the location of the air conditioner. The air conditioner is currently facing the bedroom door, so the wind is blowing there rather than throughout the room (as shown in figure 2.5).

Figure 2.5

1.3 Introduction to New Revised Layout Plan The change in this room involved adding, removing, and relocating items that had previously been mentioned.

The first one is changing the lighting from surface mounted to LED round downlight. The light that will be used is Philips LED 10W 6” Meson Round Downlight.

Figure 3.1 Specification: •

Housing: Synthetic

•

Housing Paint: White

•

Cut Out Size (mm): 150D

•

Dimension (mm): 165D x 47H

•

Wattage: 10W

•

Lumen Output: 900lm

•

Voltage: 220-240V

•

Colour Temperature: 4000K Cool White

•

Colour Rendering Index: 80Ra

•

Lifetime: 15,000hrs

•

Dimmable: No

Figure 3.2

The second solution is to relocate the lamp to the middle of the room (as shown in figure 3.3). The light that would be emitted will be more equal if the light is moved to the centre.

Figure 3.3 The third solution is adding a LED round downlight at the wardrobe are (as shown in figure 3.4). The addition of a light fixture in the wardrobe area will make it easier for me to see the wardrobe, especially at night. The light that will be used is Pila 12W 5” Round LED Downlight (as shown in figure 3.5).

Figure 3.4 Specification: • • • • • • • • • • • •

Size: 5" Wattage: 12W Lumen: 900lm Shape: Round Colour: Cool White 4000K Input Voltage: AC220-240V 50/60Hz 80+ CRI Cut-out size: 125mm/150mm 12,000 Hours Life 80% energy saving Power Factor: 0.5 No UV&IR radiation

Figure 3.5

The fourth option is to remove the ceiling fan. As previously stated, I rarely use the ceiling fan, therefore it's best to remove it. Furthermore, instead of a fan, an LED light will be installed in that location (the second solution).

The last solution is to move the air conditioner to the opposite wall (as shown in figure 3.6 and figure 3.7). The wind will fill the entire space at that position.

Figure 3.6

Figure 3.7

1.4 Energy Calculation Space Area

Total Btu/hr

18,5m2 x 700 = 12950 Btu/hr

12950 Btu/hr + 1400 Btu/hr + 147 Btu/hr =

Occupant

14,497Btu/hr

2people x 700 = 1400 Btu/hr

Air Conditioner Sizing

Heat From Electrical Equipment

14,497 Btu/hr : 9800 = 1.47 hp = 1.5 hp

LED Downlight: 22 Watt Fluorescent Tube: 20 Watt Total: 42 Watt x 3.5 = 147 Btu/hr

Based on the calculations above, the air conditioner required for this room is a 1.5 hp unit.

As a result, the air conditioner will be replaced with a 1.5 hp unit. Air conditioner that will be used in the room is Samsung 1.5HP S-Essential Air Conditioner (as shown in figure 4.1).

Figure 4.1 Specification: Capacity • Capacity (Cooling, Btu/hr)12000 Btu/hr • Capacity (Cooling, Min - Max, Btu/hr)3,100 ~ 13,000 Btu/hr • Capacity (Cooling, kW)3.52 kW • Capacity (Cooling, Min - Max, kW)0.91 ~ 3.81 kW Energy Efficiency • EER (Cooling, W/W)3.30 W/W • EER (Cooling, Btu/hW)11.27 Btu/hW • CSPF5.1 • Energy Star Rating (Cooling)4 Star Noise Level • Noise Level (Indoor, High/Low, dBA)40 / 20 dBA • Noise Level (Outdoor, High/Low, dBA)48 dBA Electrical Data • Power Source(Φ/V/Hz)1 / 230 / 50 • Power Consumption (Cooling, W)1065 W • Operating Current (Cooling, A)5.2 A Physical specification • Gross Dimension (Indoor, WxHxD)883*261*358 mm • Gross Dimension (Outdoor, WxHxD)778*550*331 mm • Net Dimension (Indoor, WxHxD)820*285*213 mm • Net Dimension (Outdoor, WxHxD)660*475*242 mm • Gross Weight (Indoor, kg)9.6 kg • Gross Weight (Outdoor, kg)21.9 kg • Net Weight (Indoor, kg)8.2 kg • Net Weight (Outdoor, kg)20.2 kg • Loading Quantity (20/40/40Hft without Pipe)123 / 253 / 285 Air Flow • Air Direction Control (Up/Down)Auto • Air Direction Control (Left/Right)Manual • Air Flow Control Step (Cool/Fan)5/4

1.5 Bill of Quantities

List of New Products Item

Description

L1

Philips LED 10W 6” Meson Round Downlight

L2 A1

Pila 12W Downlight

5”

Round

LED

Samsung 1.5HP S-Essential Air Conditioner

Store

Address

Cima Lighting Sdn Bhd

Jalan 215, Seksyen 51, 46050 Petaling Jaya, Selangor

Senheng Electric Sdn Bhd

shorturl.at/cxMTY

Bill of Quantities Item L1 L2 L3

Description Philips LED 10W 6” Meson Round Downlight Pila 12W 5” Round LED Downlight Samsung 1.5HP SEssential Air Conditioner

Unit

Quantity

Rate (RM)

Total (RM)

Note

nos

1

19.50

19.50

4000K Cool White

nos

1

10.90

10.90

4000K Cool White

nos

1

1,499.00 1,499.00 Total: RM 1,529.40

-

2.1 Current Layout Plan

2.2 Revised Layout Plan

2.3 Revised Perspective 3D View

3320 1920

2800

OUTSIDE

W1

LEGEND DESCRIPTION

QUANTITY

SWITCH

2

SWITCHED SOCKET

3

CEILING FAN

1

AIR CONDITIONER

1

CEILING MOUNTED LAMP

1

FLUORESCENT TUBE LAMP

1

W1

WINDOW

1

D1

BEDROOM DOOR

1

D2

BATHROOM DOOR

1

SYMBOL

SINGLE BED

1250

DESK

2200

3000

SHELF

TO THE BATHROOM

D2

850

1650

SINGLE BED

D1

C LP

CURRENT LAYOUT PLAN SCALE 1 : 30

ASSIGNMENT 1

CURRENT FLOOR PLAN

MS SHARON TEH

AS SHOWN PUTRI ARDHEA ANNISA 15 OCT 2022

BSSC/ASS1/CLP

3320 1920

2800

OUTSIDE

W1

LEGEND DESCRIPTION

QUANTITY

SWITCH

2

SWITCHED SOCKET

3

AIR CONDITIONER

1

6" MESON LED DOWN LIGHT

1

5" MESON LED DOWN LIGHT

1

FLUORESCENT TUBE LAMP

1

W1

WINDOW

1

D1

BEDROOM DOOR

1

D2

BATHROOM DOOR

1

SYMBOL

SINGLE BED

1250

DESK

2200

3000

SHELF

TO THE BATHROOM

D2

850

1650

SINGLE BED

D1

R LP

REVISED LAYOUT PLAN SCALE 1 : 30

ASSIGNMENT 1

REVISED FLOOR PLAN

MS SHARON TEH

AS SHOWN PUTRI ARDHEA ANNISA 15 OCT 2022

BSSC/ASS1/RLP

BACHELOR OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304)

ASSIGNMENT 2: INDOOR COMFORT DESIGN AND INVENTION

NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH

ASSIGNMENT 2A LAYOUT PLAN

TEMPERATURE CALCULATION

WALL 1

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

ΔT

07.00 am

77°F

78.8°F

1.8°F

12.00 pm

87.8°F

78.8°F

10°F

17.00 pm

82.4°F

78.8°F

3.6°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

Based on the temperature, I believe it all makes sense. The temperature feels cool and shady for 7 a.m. It was hot and humid at 12 p.m. It rained at 5 p.m., making the weather cold and windy.

WALL 2

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

ΔT

07.00 am

73.4°F

78.8°F

5.4°F

12.00 pm

73.4°F

78.8°F

5.4°F

17.00 pm

73.4°F

78.8°F

5.4°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

WALL 3

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

ΔT

07.00 am

69.8°F

78.8°F

9°F

12.00 pm

69.8°F

78.8°F

9°F

17.00 pm

69.8°F

78.8°F

9°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

WALL 4

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

DIFFERENCES TEMPERATURE

07.00 am

72.23°F

78.8°F

6.57°F

12.00 pm

82.22°F

78.8°F

3.42°F

17.00 pm

79.88°F

78.8°F

1.08°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

Based on the recorded temperature above, I feel it all makes sense. My unit is on the 19th level, so it seems cooler than the outside temperature.

WALL 5

TIME

OUTSIDE TEMPERATURE

INSIDE TEMPERATURE

DIFFERENCES TEMPERATURE

07.00 am

73.76°F

78.8°F

5.04°F

12.00 pm

83.48°F

78.8°F

4.68°F

17.00 pm

79.52°F

78.8°F

0.72°F

INDOOR TEMPERATURE

OUTSIDE TEMPERATURE

Based on the temperature recorded above, I feel it all makes sense. The temperature in the bathroom is slightly higher than the other room, which is the ideal temperature for a bathroom.

R-VALUES TABLE

WALL 1 (NORTH)

AREA: 3320 mm -> 11 ft

1780 mm -> 5.8 ft

2900 mm -> 9.5 ft

1935 mm -> 6.3 ft

Wall include window: 11 ft x 9.5 ft = 104.5 ft2 Window: 5.8 ft x 6.3 ft =36.54 ft2 W1: 104.5 ft 2 – 36.54 ft 2 = 67.96 ft2

R-VALUE: Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU Single Pane Window: 1 ft2·°F·h/BTU

HEAT TRANSFER OF WALL 07.00 am

12.00 pm

17.00 pm

q = A x T R = 67.96 ft 2 x 1.8°F 0.48 ft2·°F·h/BTU = 254.85 Btu/hr

q = A x T R = 67.96 ft 2 x 10°F 0.48 ft2·°F·h/BTU = 1,415.84 Btu/hr

q = A x T R = 67.96 ft 2 x 3.6°F 0.48 ft2·°F·h/BTU = 509.70 Btu/hr

HEAT TRANSFER OF WINDOW 07.00 am

q = A x T R = 67.96 ft 2 x 1.8°F 1 ft2·°F·h/BTU = 122.33 Btu/hr

12.00 pm

q = A x T R = 67.96 ft 2 x 10°F 1 ft2·°F·h/BTU = 679.60 Btu/hr

17.00 pm

q = A x T R = 67.96 ft 2 x 3.6°F 1ft2·°F·h/BTU = 244.65 Btu/hr

HEAT TRANSFER TOTAL 07.00 am

q = 254.85 Btu/hr + 122.33 Btu/hr = 377.2 Btu/hr

WALL 2 (EAST)

AREA: 3000 mm -> 9.8 ft 2900 mm -> 9.5 ft W2: 9.8 ft x 9.5 ft = 93.1 ft2

12.00 pm

17.00 pm

q = 1,415.84 Btu/hr + 679.60 q = 509.70 Btu/hr + 244.65 Btu/hr Btu/hr = 2,095.44 Btu/hr = 754.35 Btu/hr

R-VALUE: Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU

07.00 am

12.00 pm

17.00 pm

q = A x T R = 93.1 ft 2 x 5.4°F 0.48 ft2·°F·h/BTU = 1,047.40 Btu/hr

q = A x T R = 93.1 ft 2 x 5.4°F 0.48 ft2·°F·h/BTU = 1,047.40 Btu/hr

q = A x T R = 93.1 ft 2 x 5.4°F 0.48 ft2·°F·h/BTU = 1,047.40 Btu/hr

WALL 3 (SOUTH)

AREA: 2800 mm -> 9.2 ft

W3: 9.2 ft x 9.5 ft = 87.4 ft2

2900 mm -> 9.5 ft

2.8 ft x 9.5 ft = 26.6 ft2

850 mm -> 2.8 ft

87.4 ft2 + 26.6 ft2 = 114 ft2

R-VALUE: Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU

07.00 am

12.00 pm

17.00 pm

q = A x T R = 114 ft2x 9°F 0.48 ft2·°F·h/BTU = 2,137.50 Btu/hr

q = A x T R = 114 ft2x 9°F 0.48 ft2·°F·h/BTU = 2,137.50 Btu/hr

q = A x T R = 114 ft2x 9°F 0.48 ft2·°F·h/BTU = 2,137.50 Btu/hr

WALL 4

AREA: 1850 mm -> 6 ft

900 mm -> 3 ft

2900 mm -> 9.5 ft

2100 mm -> 6.9 ft

1392 mm -> 4.5 ft

Right wall: 6 ft x 9.5 ft =57 ft2 Left wall include door: 4.5 ft x 9.5 ft = 42.75 ft2 Door: 3 ft x 6.9 ft = 20.7 ft2 Left wall exclude door: 42.75 ft2 – 20.7 ft2 = 22.05 ft2

W4: 57 ft2 + 22.05 ft2 = 79.05 ft2

R-VALUE: Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU Door: 3.03 ft2·°F·h/BTU

HEAT TRANSFER OF WALL 07.00 am

12.00 pm

17.00 pm

q = A x T R = 79.05 ft2x 6.57°F 0.48 ft2·°F·h/BTU = 1,082 Btu/hr

q = A x T R = 79.05 ft2x 3.42°F 0.48 ft2·°F·h/BTU = 563.23 Btu/hr

q = A x T R = 79.05 ft2 x 1.08°F 0.48 ft2·°F·h/BTU = 177.86 Btu/hr

12.00 pm

17.00 pm

q = A x T R = 79.05 ft2x 3.42°F 3.03 ft2·°F·h/BTU = 89.22 Btu/hr

q = A x T R = 79.05 ft2 x 1.08°F 3.03 ft2·°F·h/BTU = 28.18 Btu/hr

12.00 pm

17.00 pm

HEAT TRANSFER OF DOOR 07.00 am

q = A x T R = 79.05 ft2x 6.57°F 3.03 ft2·°F·h/BTU = 171.40 Btu/hr HEAT TRANSFER TOTAL 07.00 am

q = 1,082 Btu/hr + 171.40 Btu/hr = 1,253.40 Btu/hr

q = 563.23 Btu/hr + 89.22 Btu/hr = 652.45 Btu/hr

q = 177.86 Btu/hr + 28.18 Btu/hr = 206.04 Btu/hr

WALL 5 (WEST)

AREA: 2200 mm -> 7.2 ft

2100 mm -> 6.9 ft

2900 mm -> 9.5 ft

759 mm -> 2.5 ft

1250 mm -> 4.1 ft

Right wall: 7.2 ft x 9.5 ft = 68.40 ft2 Left wall include door: 4.1 ft x 9.5 ft = 38.95 ft2 Door: 2.5 ft x 6.9 ft = 17.25 ft2 Left wall exclude door: 38.95 ft2 – 17.25 ft2 = 22.70 ft2

W5: 68.40 ft2 + 22.70 ft2 = 91.1 ft2

R-VALUE: Reinforced Concrete: 0.08 x 6 inch = 0.48 ft2·°F·h/BTU Door: 3.03 ft2·°F·h/BTU

HEAT TRANSFER OF WALL 07.00 am

12.00 pm

q = A x T R = 91.1 ft2x 5.04°F 0.48 ft2·°F·h/BTU = 956.55 Btu/hr

q = A x T R = 91.1 ft2x 4.68°F 0.48 ft2·°F·h/BTU = 888.23 Btu/hr

17.00 pm

q = A x T R = 91.1 ft2 x 0.72°F 0.48 ft2·°F·h/BTU = 136.65 Btu/hr

HEAT TRANSFER OF DOOR 07.00 am

q = A x T R = 91.1 ft2x 5.04°F 3.03 ft2·°F·h/BTU = 151.53 Btu/hr

12.00 pm

17.00 pm

q = A x T R = 91.1 ft2x 4.68°F 3.03 ft2·°F·h/BTU = 140.70 Btu/hr

q = A x T R = 91.1 ft2 x 0.72°F 3.03 ft2·°F·h/BTU = 21.65 Btu/hr

HEAT TRANSFER TOTAL 07.00 am

12.00 pm

q = 956.55 Btu/hr + 151.53 Btu/hr = 1,108.03 Btu/hr

q = 888.23 Btu/hr + 140.70 Btu/hr = 228.93 Btu/hr

17.00 pm

q = 136.65 Btu/hr + 21.65 Btu/hr = 158.3 Btu/hr

CONCLUSION Highest Heat Transfer Lowest Heat Transfer

Wall Number Wall 3 Wall 5

Time 07.00, 12.00, 17.00 17.00

Result 2,137.50 Btu/hr 158.3 Btu/hr

ASSIGNMENT 2B Product: Magnetic Roman Shade Initial Sketch

Materials

1. Cotton Linen (Linen is highly breathable, soft, and a natural insulator. It’s fibers are hollow, moving air and moisture naturally. It is valued for its ability to keep cool in the summer months and trap warmth in colde weather.)

2. Magnetic Tape 3. Round Magnet

Tools

1.

2.

3.

4.

5.

6.

7.

Needle Thread Scissor Measuring Tape Iron Sewing Pin Pencil

Size Unfolded Width: 50 cm Height: 150 cm Folded Width: 50 cm Height: 44.2 cm

Construction 1. Cut the fabric according

2. Fold edges of the fabric

to the size (54cm x 155 cm).

(horizontal 2 cm, vertical 2.5 cm)

2. Iron the folded edges.

3. Pin it then sew.

4. Measure the height for the

5. Cut the magnetic tape with

folded position, then mark it.

of approximately 50 cm.

6. Stick the tape to the cutted fabric.

7. Insert round magnet in edges (left and right) and in the middle.

8. Sew the fabric that has been taped

9. Measure and cut fabric

by magnetic tape.

for pouches.

10. Fold and sew edges of the pouch.

11. Sew the pouch to the shade.

Result

Cost

•

Cotton Linen Fabric: RM 20.50

RM 20.50 : 23,250 cm2 = RM 0.0009/cm2) Used: 10,130 cm2 x RM 0.0009= RM 9.1 •

Magnetic Tape: RM 10.50

RM 10.50 : 300 cm = RM 0.035 Used: 50 cm x 3 = 150 cm x RM 0.035 = RM 5.25 •

Magnet: RM 7.80/20 pcs

RM 7.80 : 20 pcs = RM 0.39 Used: 13 pcs x RM 0.39 = RM 5.07 Total Cost: RM 9.1 + RM 5.25 + RM 5.07 = RM 19.42

Reflection Through this assignment, I learned that there are many ways to minimalize heat transfer. A lot of simple materials that can be used, even a bubble wrap. I amaze with all of the prototype that my classmates made because all so cool and out of the box. In my opinion, Janelle prototype is really good. I like the ideas and the visual of the product.

When I made this product, there is an error that made the magnet tape is not attach to each other.

After thinking some solution, I put the round magnet in each edges and in the middle. I personally think that this assignment its really useful and fun. Students can share their ideas and skills.

Design Value Design Value = Market Value – Material Cost

Market Value: 30 + 35 + 25 + 30 + 30 + 35 + 40 + 25 + 40 + 30 + 10 + 15 + 20 + 30 + 35 + 30 + 20 + 25 + 30 + 35 + 50 21 = RM 29.5

Design Value = RM 29.5 – RM 19.42 = RM 10.08

BACHELOR OF INTERIOR ARCHITECTURE BUILDING SCIENCE AND SERVICES (BLD62304)

FINAL PROJECT: DESIGN OF BULDING SERVICES (IAD 3 INTEGRATED)

NAME: PUTRI ARDHEA ANNISA STUDENT ID: 0346459 LECTURER: MS SHARON TEH

TASK 1A: SITE SELECTION & QUALITATIVE DESCRIPTION OF INCOPERATED BUILDING SERVICES

This building is located at Tamarind Square, Cyberjaya. The purpose of this building is to sharing awareness about fast fashion. There will be several activities to reduce fast fashion, one of which is upcycling clothes from worn clothes.

Selected Area of Site: Level 4 (Thrift Store)

Specific Activities and Building Services of Selected Area: 1. Thrift Store

Thrift store is an area for selling second-hand clothes. As a clothing store, this room need to have a proper lighting and also air conditioner since it’s a indoor area. Inside the thrift store, they also have a toilet and fitting room. The fitting room used for the visitor to try on the clothes that they want to buy.

TASK 1B: DESIGNING AND JUSTIFICATION OF BUILDING SERVICES SELECTION & LOCATION

Lighting 1. LED Downlight LED downlight will be used at all the area, but with a different specification per room.

For the thrift store and fitting room. LED Downlight that will be used is downlight with 900 lumens and with colour temperature 4000k cool white. The reason why I choose white colour is because the space itself is a clothing store, lighting will affect the colour of the clothes. So, it will be better to use the white colour one.

For toilet, LED Downlight that will be used is downlight with 940 lumens and with colour temperature 3000k warm white. I decide to use the warm white because warm white lighting is calming and relaxing, it is best for bathrooms.

Specifications: 1. Philips LED 10W 6” Meson Round Downlight.

•

Housing: Synthetic

•

Housing Paint: White

•

Cut Out Size (mm): 150D

•

Dimension (mm): 165D x 47H

•

Wattage: 10W

•

Lumen Output: 900lm

•

Voltage: 220-240V

•

Colour Temperature: 4000K Cool White

•

Colour Rendering Index: 80Ra

•

Lifetime: 15,000hrs

•

Dimmable: No

2. Philips LED 10W D150 6" Eyecomfort Meson Round Downlight.

Specifications:

2. Track Light To highlight the items visually, track lights are usually applied in the boutiques to make a difference in stimulating the purchase behaviour. Track light is mounted to ceiling and the light will be projected to the clothing rack.

IKEA BÄVE LED Ceiling Track

Specifications: •

Built in LED light source.

•

The light source has a lifetime of approx. 25,000 hours. This corresponds to about 20 years if the lamp is on for 3 hours per day.

•

Light colour: warm white (2700 Kelvin).

•

Not dimmable.

•

Special waste handling may be required. Please contact your local authorities for more information.

•

Wired-in installation

•

Luminous flux: 900 lm

•

Length: 78 cm

•

Width: 3 cm

•

Shade diameter: 3 cm

•

Power: 11 W

VAC Air Conditioner Calculation: •

Space Area

67.3 m2 x 700 = 47,110 Btu/hr •

Occupant

15 people x 700 = 10,500 Btu/hr •

Heat from electrical equipment

Lighting •

6 Bulbs: 60 watt

•

2 Track light: 22 watt

82 watt x 3.5 = 287 Btu/hr •

Total Btu/hr:

47,110 Btu/hr + 10,500 Btu/hr + 287 Btu/hr = 57.897 Btu/hr •

Air conditioner sizing

57.897 Btu/hr / 9800 Btu/hr = 5.9 hp = 6 hp

Daikin Ecoking Prestige Ceiling Exposed Non-Inverter 6.0HP

Specifications:

Lighting Illuminance for Store: Area: 67.3 m2 Total light: 6 downlight (900 lm each) E = lm : A = 5400 lm : 67.3 m2 =

802.4 lm/m 2

Lighting Illuminance for Toilet: Area: 2.75 m2 Total light: 940 lm E = lm : A = 940 lm : 2.75 m 2 = 341.82 lm/m 2

Lighting Illuminance for Fitting Room: Area: 2.2 m 2 Total light: 900 lm E = lm : A =900 lm : 2.2 m 2 = 409.1 lm/m2

Energy Use Lighting: Downlight: 10 watt x 9 pcs x 8 hours : 1000 = 0,72 kWh Track light: 11 watt x 1 pc x 8 hours : 1000 = 0,0088 kWh 0.07288 kWh x 30 days = 21.864 kWh

AC: 6,414 watt x 10 hours : 1000 = 64.14 kWh x 30 days = 1,924.2 kWh

Total: = 21.864 kWh/month + 1,924.2 kWh/month = 23.788 kWh/month

4987 3565

3365 5980

94

34 45

32

8

19

25

5 30

40

15 34

15

16

72

2000

4523

2920

30

1613

21

28

21

0

325

1119

24

70

1735

1757

4TH 4TH FLOOR LAYOUT PLAN FLP SCALE 1:100

NOTE:

DRAWN BY: PUTRI ARDHEA ASSIGNMENT: ID NO: 0346459 FINAL PROJECT 4TH FLOOR LAYOUT PLAN SUBJECT: BScS

SCALE: AS SHOWN DATE: LECTURER: MS SHARON

NOTE:

DRAWN BY: PUTRI ARDHEA ASSIGNMENT: ID NO: 0346459 FINAL PROJECT BATHROOM SECTION SUBJECT: BScS

SCALE: AS SHOWN DATE: LECTURER: MS SHARON