אאא
اﻟﻤﺆﺳﺴﺔ اﻟﻌﺎﻣﺔ ﻟﻠﺘﻌﻠﻴﻢ اﻟﻔﻨﻲ واﻟﺘﺪرﻳﺐ اﻟﻤﻬﻨﻲ אאאא
א 2 104
104
א
2
א
W،،אא،א
אאאאאאאאאא
אאא،א אאאאא
אאא אא א אאאאאא
K אא
אאאאאאא
א،אאא אאאאאאאא،
א א ،א אא אאאאאאאאאאאא
א אא، א Kאא،א
א ?א?? 2?אא
Kאאאאאא
אאאאאאא
،א،אאאא Kאאאאא
Kאאאאא
אאאא
104
א
2
א
{אאאא
{אKKKKKKKKKKKKKKאאאאא אאאא
א{אאאאאאא
Kאאא
K{אאאאאא
،،،א
אאא
اﻟﻤﺆﺳﺴﺔ اﻟﻌﺎﻣﺔ ﻟﻠﺘﻌﻠﻴﻢ اﻟﻔﻨﻲ واﻟﺘﺪرﻳﺐ اﻟﻤﻬﻨﻲ אאאא
2
א
א
1
אא א
104
א
2
א
אWאא אא
אאאJ ( DATEM ) אJ ( BENCH MARK ) אJ ( BACK SIGHT ) אאאJ (FORE SIGHT ) אאאJ ( INTERME . SIGHT ) אאאJ ( TURNING .POINT T .P ) אJ ( Height of inst H. I ) אאJ אא אאאאאא אא אאאאא א א
אא אאא
אאא٪100א 3אא
Wאא
אא–1 א–2
-1-
אא א
104
א
2
א
1-1 אאא אאא
אא אאא {
א 2-1 א אאאאאאא
א –1אאא{
Kאאאאא
Kאאאאא–2 אאאאאא–3 Kאאאאאאא–4 אאא א3-1 Wאאאא EאאאF–1 א–2 אאאאאאא
אאא{אאאאא{א
א{אאא
אא{אאא
אאאא{אא
אאאאא
Kאא{א
-2-
אא א
104
א
2
א
אאא 1-3-1 E1Fאא
אאאא(1-1) אא Kאא–1 Kא–2
Kא–3
-3-
אא א
104
א
2
א
EאאFאא–1 {אאאאא
אאאאאאE2-1Fאא
אאאE2-1F {W G
אאאאא
Kאאאא
א{אW G אאאא{אא
Kאא
אאW אאG אאאאא{אאא
אאא{אאא
Kא
אאאא{ W G Kאא{אאא -4-
אא א
104
א
2
א
EאאFא–2 אאאא{ { אאא{ א{ א KE3-1Fאאאאא
E3-1F
אאא{ אא אאא E4-1Fאאאא
-5-
אא א
104
א
2
א
EbFEaFאאE4-1Fא
אJ 3 אאא{ אאא Kא
אא–4 אאאאאאאאא Kאאא
אא2-3-1 א אאא{אא
{{{אאא{אא
א{אאא
{אא{א אאאאאאאא -6-
אא א
104
א
2
א
אKאאאאאאא א E5 -1Fא
אאE5-1Fא
א א،אאא Kאא
ﺘﻌﺎﺭﻴﻑ4-1 W{אאאאא אG אאאא{
EאאF
G Kאאאאאא
-7-
אא א
104
א
2
א
אG E6-1Fאאא
אאאE6-1F
B.MאG K ،א
،אאא،א א،א،א
אא ،
E7-1FאאKאא
-8-
אא א
104
א
2
א
אאאE7-1Fא EB.SאFאאאG Kאאאא EF.SאFאאאG Kאאאא EI.SFאאאG אאאאא
-9-
אא א
104
א
2
א
EאאFאG Kאאאאאא KE8-1Fא
KאאאאאאE8-1F אאG Kא،אאא
א 5-1 אא{אא
{אא {א{B .M
אאאא{אאאא {{ א
{א{אאאאא
אאא{א{א WאKאא
-10-
אא א
104
א
2
א
אא אאאאאאא
אאאא{EאFא K
אא אאאאאאאא אאאאא{אא {אאאא {אאא
Kאאאאאא
-11-
אא א
104
א
2
א
EאאFא :א
אאאא
א
אא
א אא א
א BM
BM
Wאא Zא–אא Z–
-12-
אא א
104
א
2
א
EאאFא :א
א א (-)
א (+)
א
אאאא
אא
א
א BM
Wאא Zא–אא Z–
Zא–א
-13-
אא א
104
א
2
א
אאאא1-5-1 אא{אא א
א{{א{אא
א אא{אא Kאאא
KE9-1Fא
KאE9-1F א Wא
Kאאאאא–1
Kאאא{א–2 Kאא{אאא–3
אאא{אאאאאאא–4 Kאאאא
{E אFאאאא א–5 Kאא{אאאא
Kאאאא–6 -14-
אא א
104
א
2
א
אאא {אא{אא א–7 Kא
אאא{א אאאא –8
Kא
-15-
אא א
104
א
2
א
E1F
WאאאאE9-1Fא
אאא{אאאEA,1,2,3,,4,5 ,B F
WאאאאE3F A = 3.2501 = 3.000 2 = 2.850 3 = 2.750,1.820 4 = 2.130 5 = 0.780 B = 0.680 EFאA , B B = 550.810 A = 550.170 1 , 2 , 3 , 4, 5 , אא אא{אא
א
א3א{אא{אא
KB {A אאאאא
Kא1 , 2, 4, 5 ,א
EאאFאאא
EאאFאא
-16-
אא א
104
א
2
א
EאאFא :א
אאאא
א
אא
550.170
א
אא
א 3.250
א
A
3.000
1
2.850
2
3
2.750
1.820
2.130
4
0.780
5
B
0.680
Wאא
=א–אא =–
-17-
אא א
104
א
2
א
EאאFא :א
אאאא
א
אא
550.170 553.420
א
אא
א 3.250
א
A
550.420
3.000
1
550.570
2.850
2
550.670 552.490 2.750
3
550.360
2.130
4
551.710
0.780
5
551.810
B
1.820
0.680
Wאא 1.640 = (0.680+2.750) – (1.820+3.250) = א–אא 1.640 = 550.170- 551.810 = –
-18-
אא א
104
א
2
א
EאאFא :א
א
א א (-)
550.170
550.420
(+)
אאאא
א
אא
א
א
3.250
A
3.000
1
2.850
2
3
4
0.780
5
0.250
550.570
0.150
550.670
0.100 2.750
550.360
0.310
2.130
551.710
1.350
551.810
0.100 0.680
1.820
B
Wאא 1.640Zא–אא 1.640Z–
1.640 Zא–א
-19-
אא א
104
א
2
א
אאא אא Kאאאאאאא אאאא K אא Wא Kאאאא– 1 Kאאאא– 2 Kאאאאא– 3 Kאאאא– 4 Kאאא–5 Kאאאאא– 6 אאאא Kאא– 1 K– 2 Kא– 3
-20-
אא א
104
א
2
א
Wאא KאאאאW1 ؟אאאאW2 K{אאאW3 KאאאאאאאW4 W W5 Kא{אא{א{א{א{א WאאאאאאאW6
B M =2.330 1= 3.212 2= 3.415 3= 3.816 4 = 5.710
5= 3.400
Zאאאא {אא KאאאKא260.310
WאאאאאאאW7 5 = 2.148 4 = 2.153 3 = 2.071 2= 2.068 B M = 1.115
1= 2.116 7 = 2.153
B M = 1.112 6 = 2.056
אאא{אא
א 401.301=א
א(7, 6, 5, 4, 3, 2, 1)אאאאW8 Wא4אא
5 = 2.282 4 = 2.191 3 = 2.145 2= 2.183 B M = 1.508
1= 2.121B M = 1.511
7 = 2.291
6 = 2.315
2.305
520.510אאאאאא א{E10J 1F א{א אאאW9 Wאא
-21-
אא א
104
א
2
א
1.612 , 1.652 , 1.443 , 1.171 , 3.820 , 1.730 , 1.650 , 2.350 ,1.930 , 1.740 2.052 ,2.351 , 0.751 , 1.821 , 0.562 , 1.162 , 2.051 , 2.441 , א א אאאאאא 603.184 = אאאא
E10-1F
-22-
אא א
104
א
2
א
KאאאWEאאFאא Wא
321Wא
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKWאא KKKKKKKKKKKKKKKKKKKKKKKWא
Kא
Kא٪80Wא א KKKKKKKKKWא
Kא٪100Wאא א
א
אא
K1
Kאא
K2
٪100אא
א
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKW
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK KKKKKKKKKKKKKKKKKKKKKKKKKKKKWא
-23-
אא א
104
א
2
א
EאאFאא Kאאאא
אאאאאא
אאE3F { אאאאא
Kאאאא{א
א אאאW אאאאא
א
EאאFאא
א
אאא K1
אאא K2
אאאEאFאאא
אאא? ???א{ Kא
-24-
אאא
اﻟﻤﺆﺳﺴﺔ اﻟﻌﺎﻣﺔ ﻟﻠﺘﻌﻠﻴﻢ اﻟﻔﻨﻲ واﻟﺘﺪرﻳﺐ اﻟﻤﻬﻨﻲ אאאא
2
א
א
2
אא
104
א
א
2
א
אWאא אא (Differential Leveling FאאJ ETrigonometric LevelingFאאJ (Barometric . Leveling ) אאJ אאאJ אא אאאאא אא
אא Kאאאא
אא אאא
אאא٪100א
9אא Wאא
אא– 1 א– 2
-25-
אא
104
א
א
2
א
אא
1J 2
אא {א א
אKאא אא-1
א{אאאא אא{אאא
Kאאאאאאאא אא-2 אאאאאאאא
אאאKא אא-3
אאא{אא אKאאאאאEאF
אאאאאא K
אאאאא-4 אא
אאאא{ אא
-26-
אא
104
א
א
2
א
אא2–2 אאאאאאא
אאאאאאאא{אא
Kא
אאאא 1-2-2 א– 1
EאFאא– 2
Wאא
אאאאאא
אאאאאא
אאא
Kא
אאאאא • Kאאאאאא
אאאEאFאאא • Wא
א א ،אאאא אEאFאא{אא
K א
אאאאאא 2-2-2 Wאאאאאא
אאאא אאאאאאא– 1
Kא
אE Fאאאאאאאאא – 2 KEאFא1.426א
אאאאאאאאאא– 3 Wא
-27-
אא
104
א
א
2
א
א אאא אאאG אאא
אאאאG Kא
Wא ﺍ3-2 א אא א אאFאEאאFא
KEא
אא4-2 {אאאאא
אאאאאאא
K אא5-2
EאאאFא
{אא
Kאאאאאא
-28-
אא
104
א
א
2
א
אאא אא Kאאאאאא אאאא K אא KאאאאJ 1 KאאאאאJ 2 KאאאאJ 3 KאאאאאJ 4 אאאא Kאא–1 K–2 Kא–3
-29-
אא
104
א
א
2
א
א W1 א א−אא−
אאא− אא−
אאאאאW2 K
אאאאאW3 א– 1
EאFאא– 2
-30-
אא
104
א
א
2
א
WEאאFאא Kאאא Wא
321Wא
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKWאא KKKKKKKKKKKKKKKKKKKKKKKWא
Kא
Kא٪80Wא א KKKKKKKKKWא
Kא٪100Wאא א
א אאא
K1
٪100אא
א
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKW
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK KKKKKKKKKKKKKKKKKKKKKKKKKKKKWא
-31-
אא
104
א
א
2
א
WEאאFאא Kאאאא
אא Kאאא
E3F { אאאאאא
Kאאאא{אאא אאWאאאאא
אא
EאאFאא
א
אאא
אאא
אאאEאFאאא
אאא? ???א{ Kא
-32-
אאא
اﻟﻤﺆﺳﺴﺔ اﻟﻌﺎﻣﺔ ﻟﻠﺘﻌﻠﻴﻢ اﻟﻔﻨﻲ واﻟﺘﺪرﻳﺐ اﻟﻤﻬﻨﻲ אאאא
2
א
א
3
אא
104
א
א
2
א
אWאא אאא אאJ
אאאJ אא Kאאא אא אאאא Kא
אא Kאאאא אא Kאא٪100א 3אא Wאא א– 1 K– 2
K– 3 K– 4
-33-
אא
104
א
א
2
א
אא
{ אאאאאא
{ אאאאאא
K א אאאאא אאאאאאאאאאא
אאאא{ אאאא{א Kאאאא
E1F
2.30 = אאאA א
1: 50 אאA 100 B א
א
2.00 = 100C
1 =א 50
0.30 = 2.00 - 2.30=Bאא
אאאאא{ B ∴
0.30
-34-
אא
104
א
א
2
א
אאא אא Kאאא אאאא K אא KKא– 1 K{אא – 2 א{אאאא – 3 Kאאאאא א{אאא{א – 4 Kאאא{אאאאאא אאאא Kאא– 1 K – 2 Kא – 3 -35-
אא
104
א
א
2
א
אא אאאאאא אא אאאאאא אא
אא Kאאאא אא Kאא٪100א
3אא Wאא K– 1 Kאא– 2
K– 3 K– 4 K– 5 -36-
אא
104
א
א
2
א
א2-3 אא Kאאאא
אאאאאאאאא
א{אאאא אאאאא אא
KEFאאEF אא 3-3 אאJ
אאאאאאאא
אאאאאא Kאא Kאאאאא
Wאאא
אאאא-1
אא
Kאאאאאא {E1-3F
אאאאE1-3F
-37-
אא
104
א
א
2
א
אאא א-2
אאאאא
{אאאאאא {אא אאא{E2-3Fא
אאאאאא Kאא
K אאאא
אאאאE2-3F
אאאא-3
אאא אאאא
א{אאא KE3-3F
-38-
אא
104
א
א
2
א
א،אאאאאא
א،אאאאאא،א Kאאאאא
אאאאE3-3F
א-4
{אא
אאא {E4-3Fאאאאאאא אאאאא
Kא
אאאאאאא א{אאאא
Kאא
-39-
אא
104
א
א
2
א
אE4–3F
אא אאאאאאא
{אאאאא{ א
Kאאאא
-40-
אא
104
א
א
2
א
-1
KE5-3Fאאא
E5-3F
J 2
KE6-3F אאאא
E6-3F -41-
אא
104
א
א
2
א
אאאא 4-2 EFא{E7- 3Fא Wאאאאא{א
אאאאאE7-3F
Kאאא :
Kאאאאאאאאא: 1 Kאאאאאאאא : 2 Kאא :
Kא :
אEFאE1Fאאאא : KEFאE2Fאאא =2 = 1W -42-
אא
104
א
א
2
א
Kא21אאאא :
K2{1אאאאאא א:
Kאאאאא :
Kאאאאא : KEFאEFאא :
KEFאEFאא :
אאאאאאאאאאא : KE21Fאאאאאאא
–180Zאאאאאא : ´
אאאאאאאא5–3 אאאאא KEFאאאEFא
אאאאאא
Kאא
{אאאאאאEFאא א{אE 7 – 3Fאאאאאא Wאאאא
אאאאאJ °90Z2אאZ1אא{א
هـZ2אאZ1אא2{1א– 2
21אאZ وZ2Z1אא 2
E7–3Fאאאאא
W
-43-
אא
104
א
א
2
א
EFא 1-5-3
אאאאאZ°360אאאאא
ل هـ
= ﻧﻖ
E1-3FKKKKKKKKKKKK × هـ
× ×ط2 360
ط× ﻧﻖ 180
∴
=
∴
اﻟﻤﻘﺎﺑﻞ اﻟﻤﺠﺎور
EFא2–5–3 =אאE7–3Fא1א
ف ﻧﻖ
= هـ∴ 2
E2–3FKKKKKKKKKKKKKKKK هـ = ∴ 2
EFאא2-5-3
E7–3Fאאא1א
اﻟﻤﻘﺎﺑﻞ اﻟﻮﺗﺮ
=אא و
2
ﻧﻖ
هـ
2
= هـ 2
K = و∴ 2
E3-3FKKKKKKKKKK هـK2=∴ 2
-44-
אא
104
א
א
2
א
EFאאא4–5-3 E7–3Fא
E1FKKKKKKKKKKKKKKKKKKKKKKKK– =
אאא1א ت.م ﻧﻖ
= هـ 2
هـ 2
K = ∴
E1Fא
هـJ =∴ KE4–3FKKKKKKKKKKKKKKKKE
هـ 2
2
J 1F =∴
EFאא5-5-3 E7–3Fא E1FKKKKKKKKKKKKKKKKKKKKK–= 1אאא1א
ﻧﻖ هـ 2
=
E1Fא =J ﻧﻖ هـ 2 -45-
ﺟﺘﺎ
=
אא
104
א
א
2
א
1
KE5-3FKKKKKKKKKKKKKKKKKKE1J هـF = ∴ 2
E1F
א200א
KאאאאK °36 ´48 אאאאEFא
א
°18
´24 = هـ°36 ´48 = 200 = 2
ط× ﻧﻖ × هـ 180
EFא-1
= ∴ E1-3FKKKKKKKKKKKKKKKKKא 128.46 = × ط200 × 36
.o
180
48′
= ∴
EFא–2
هـ =∴ E2J 3FKKKKKKKKKKKKKKKKא 2
א66.53 =°18
-46-
´24 C200 =∴
אא
104
א
א
2
א
EFאא–3
א126.26 =°18
E3–3FKKKKKKKKKKKKKKKKKKKא
هـ 2
KC2=∴
´24 C 200 C 2 =
EFאאא-4 E4–3FKKKKKKKKKKKKKKKKKKKא
E هـ–1F= 2
10.22 =E°18
´24–1F200=∴
EFאא-5
E5 –3FKKKKKKKKKKKKKKKKKKKא 1
E1J هـ
2
10.78 =E1J
F=∴
1 °18
ﺣﺘﺎ
´24
ﺣﺘﺎ
FC200=∴
-47-
אא
104
א
א
2
א
אא א6-3 אא،אאאא אאאאאאאאא
אאאאאKאא Kאאאאאאאאא
אא1-6-3 אKאאאאא
FEFאEFאEFאא
WE8-3
אאאאE8–3F EאF
د 360
=
اﻟﻘﻮس اﻟﺪاﺋﺮة د 360
.ﻃﻮل .ﻣﺤﻴﻂ
=
Q
س × ط × ﻧﻖ2
360C = CCC2 ∴ -48-
אא
104
א
א
2
א
180 × سo E6-3FKKKKKKKKKKKKKKKKKK = ط×د
אא2-6-3 אKאאאאא
FEFאEFאEFאא
E 9-3
אאאאE9-3Fא E9-3Fא ر
2
ﻧﻖ
= ر 2
ر 2
-49-
ر 2
=
אא
104
א
א
2
א
E2F Wאא°3 א Kא20 אא– Kא 20 אא– Wא א 20 = א20 = °3 = E6-3Fאא-ﺃ 180 × سo = ط×د
א381.97 =
180 × 20 = 3o × ط
E7– 3Fאא–ﺏ ر 2
א 382.02 =
ر 2
=
20 2 o 3 2
=
-50-
אא
104
א
א
2
א
אאאא Wאאא 7-3 אאאאא אאאאאאא
אאאאאאא{א
Kאא
Wאאאא
EFא1-7-3
WאEF
KאאאאJ
KאאאאJ
KאאאאJ
אאא2-7-3
אאאאא
אאא، אאאא
אאאאא
،אא،אאא ،אא20א
אאאאאא Kא
EFאאאEFא3-7-3
،אאאא -أ אE10-3Fאאאא
-51-
אא
104
א
א
2
א
אאאאאאאא
KאEFא2،1א
אאאאא
אאאאאא،א
4،3{אאאאאא
E43،21FאאEFא
4،3א2،1אא KאEFאא
( ﺗﻮﻗﻴﻊ ﻧﻘﻄﺔ اﻟﺘﻘﺎﻃﻊ )ط( وﻗﻴﺎس زاوﻳﺔ اﻹﻧﺤﺮاف )هـE10-3Fא
אEFאאאEFא-ب אאEFאאאEFא
אאאאאE10-3FE2Fאא אE2Fאאאא
KE´J °180FאEFאאא´א
Wא،EFאא - ﺟـ
E،FאאEFאאJ 1 -52-
KE 11-3F
אא
104
א
א
2
א
KEFJ 2 E،F
س ص
1 2 = هَـ
ط ص
س ص 1J ط ص2
2
WאJ 3
= هَـ
2
∴
KE´J °180FEFאאאJ 4
אאEFאאאE11 –3F
EאאFא 4-7-3 -3FאEFאEFאאאEFא
1אאאאאEFאאאE2
אE12-3F2אאאאאא
אEFא2{1 Kאא
K ( ) هـ12אא1אא 2
-53-
אא
104
א
א
2
א
אאE12-3F
אאאאאאא5-7-3 EFאאאEFאא 1אאאאאא،2{1א
אאא،2אא אאאא
10{א20א K10050אאאאאא
אאאאא
אאאאאא Wאאא
-54-
אא
104
א
א
2
א
Wאאאאא
WאאאאאJ 1
KאאאJ
KאאאאJ
KEאFאאאאאJ 2
KEאFאאאאJ 3
אאאאאאא 8-3 אEFאאא אאאEFאאאא
E1FאאאE14-3FEFאאE13-3F
EFאא -1
E13-3Fא
CC2 2 = =سق هـ
و 2
=
هـ 2
-55-
אא
104
א
א
2
א
= E ﺟﺘﺎJ 1F= 2
E8-3FKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK هـ=EFאא 2
E9-3FKKKKKKKKKKKKKKKKKKKKKKKKKKKKKE هـJ 1F={ 2
{1אאאא -2
E1FאE´1FאאE14 – 3F
אE1FאאE1FאE1F אאאאאE1FאE´1F
Wא
11–1= 1
2
1J 2–= 1 2 2 E10 – 3F 1– –=
≥
אE1FאאEFא אאE´1FE1FEFא
אE1FאE10-3FאE1F אE1FKKKKKKK4{3{2KKKKKKK4{3{2א
4{3{2אKKKKKKKKKK{4{3{2אאEF KאאאאאKKKKK{
אE2Fאאאא א אאאא
Kא
E3F -56-
אא
104
א
א
2
א
א230 Zא
אאאא°40 ´48 Zאאא
20 Zאאאאאא
א
´24 = هـ°40 ´48 =230 =
א20=°20
2
EFא -1 א 85.54 =° 20
80.17 = ° 20
هـ 2
هـ
2
=
´24 C230 =∴
EFאא-2 C=E8 –3FKKKKKKKKKKKKא
´24 C 230 =
E هـ–1F=∴ E9 –3FKKKKKKKKKKKKKKKKKKא 2
14.43 =E° 20
´24–1F230=
{1אאאא–3 E10–3 Fא
E10–3F2–2–= א0.87 =2 20J א3.50 = 2 40J
2
230– 230 = 1
א 20
= 1
230–230= 2
א 40
= 2
א 60
= 3
א 80
= 4
60J
2
א14.36= 2 80J
2
א7.96 =
2
2
230 –230= 3 230– 230 = 4
-57-
אא
104
א
א
2
א
א80.17 אאאא100=
EאאFא
א-4
Wאא EF 0.78 3.50 7.96 14.36 14.43
EF א 20 1 40 2 60 3 80 4 80.17 E4F
،46°אאאא115א
K10אאאאאאא א
א10=23°= 46 = هـ46°=א115= 2
2
EFא-1
E 2 – 3FKKKKKKKKKKKא هـ = 2
א48.81 = 23°C115 = ∴ EFאא -2
E8-3FKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK هـ= 2
א44.93 = 23°C115 =
E9J 3FKKKKKKKKKKKKKKKKKKKKKKKKKKKKKE هـJ 1F= 2
א9.14 = E23°J 1F115=
-58-
אא
104
א
א
2
א
،1אאאא -3 א0.435 = א
1.75 =
E10 – 3Fא
2
10J 2115– 115 = 1
2
20J 2115–115=
א 3.98 = 2 30J א7.18=
2
40J
2
2
115–115= 3
2
115– 115 = 4
א 10
א 20 א 30 א 40
= 1
= 2
= 3
= 4
44.93 אאאא50= 5
אא -4
EF 0.435 1.75 3.98 7.18 9.14
EF א 10 1 20 2 30 3 40 4 44.93
אאאא א1-8-3 אאEFאאא Kא
WאE10-3Fא
2–2 –=
2E–F = E2–2F∴
2J 2H2= 2J 2∴ -59-
אא
104
א
א
2
א 2
–2= 2∴
E–2F = 2∴
EFE2FEFEF
WאאאאE2Fא 2=2
E11-3FKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
ä
2
س
× ﻧﻖ2
= E5F ﻤﺜﺎل
K°42אאאא270א
אאא20אאאאא Kא
א
א20=21°= هـ42°=א270= 2
EFא-1
هـK=E2-3Fא 2
א103.64Z21°C 270=
EFאא-2
E8-3FKKKKKKKKKא هـ= 2
א96.76= 21°270=
E9-3FKKKKKKKKKKKאE هـJ 1F= 2
א 17.93 = E21°J 1 F270= {1אאאא-3
ä
2
س
=E11-3Fא
× ﻧﻖ2 2 א0.74= (20) =1א20=1 270 × 2
א2.96= (40) =2א40=2 2
270 × 2
-60-
אא
104
א
א
2
א
2 א6.67= (60) =3א60=3
270 × 2 2 א11.85= (80) =4א80=4 270 × 2
אא-4
EF E 0.74 2.96 6.67 11.85 17.93
-61-
אא
104
א
א
2
א
EFאאא
אא אאאאאאא אאאא KE2FJ 1
KJ 2
KאאJ 3 KאJ 4
אא אא-1 Kא{א
،EFא-2
אEFא
KEF
Kא EFאאא-3 KEFא-4
E2-3FאEFאE2{1Fא-5
אאאEFאאאE هـ=F 2
E2FאאאאE1F
KE2{1F KE2{1Fא
E8- 3FאE{FEFא-6
EFאE هـJ 1F =F،E هـ=FE9–3F{ 2
2
אEFE´FאE1FאE1Fא
KE15-3FEF
-62-
אא
104
א
א
2
א
EFאאE1Fא-7
E10-3FאEFאEFא KאאאאאE
2
ﻧﻖ− ن2 س
J =F=
אEFE1Fאאאאא-8
3{2´{1´FאE1FאE1FאE4{3{2{1Fא
E´4{
אאאאאE15-3F
FאKE15-3FKE´4{´3{2´{1´Fא
אKE´4{´3{2´{1´FאE4{3{2{1
אאאאאאE4{3{2{1F KEFאאאאאאא
E2FאE´8{´7{´6{´5FאE2Fאאא
אEFEFאE2FאאE4{3{2{1F
{1FאאKאאE4{3{2{1F
E8{7{6{5FאE4{3{2
-63-
אא
104
א
א
2
א
{3{2{1{1FאאאE5{6{7{8{{4{3{2{1Fא
KאאאאE2{5{6{7{8{{4
אאאאאאאא 9-3 Kאאאאא
אאאאאא Kא
EFאאE2{1Fאא א
E{FEFאאE{Fאאא E16-3F
אאאאE16-3F
-64-
אא
104
א
א
2
א
אEFאE1FאאאEFEFא E{FאאEFאא
WאאאE1Fאאאא
1אE16-3Fא
2
E–FH2E وF=2 2
E1FKKKKKKKKKKKKKK 2 E 1
2
⎛ ⎞و2 ⎜ ⎟ – F= ⎝2⎠
–∴
1´1א
2E´1FH 12= 2
E2FKKKKKKKKKKKKKK2 E1HFH12=2∴ J =
2 E1HJ FH12=2∴
E3FKKKKKKKKKKKKKK2E1HJ FZ 2 E12J 2F 1
WE3FאE1FאEJ F 1H E 1
2 E 1
E11 – 3FKKKKKKKKKKKKK
E
2
⎛⎞و ⎜ ⎟J ⎝2⎠
2
2
⎛⎞و ⎜ ⎟J ⎝2⎠
2F
2
1 2 ⎛ ⎞ و2 ⎜ ⎟ J FZ 2 E1 J ⎝2⎠
2F
2FJ 2 E12J 2FZ1 1
- E2J 2F
= صن
אאאאאאאאא
EFאEFאEFאאE1F
אEFאאE2FE1FאאאEFא
KאאאאאאE11-3F
-65-
אא
104
א
א
2
א
E6F
אEFא140א
אאאא{°84אאא Kאאאאא20א
Wא
א20= °42= هـ
°84=
2
א140 =
EFא -1 هـ = ∴
E2-3FKKKKKKKKKKKKKKKKא
2
א126.06 = °42 C140 =
EFאא-2
E3–3FKKKKKKKKKKKKא هـKC2= 2
א187.36 = °42 אC 140C2=
א93.68= 187.36 = و 2
2
EFאא-3 0.0=
E هـ–1F=∴ 2
א35.96 = E° 42 J 1F140=∴
{1אאאא-4
E11 – 3FKKKKKKKKKKא א34.52= 293.68 J 2140 א
30.12 = 104.04
-
2
20 -
2
140 =1 20
- 2 20–2 140= 2 א 40
א22.45=104.04J 2 20–2 140 = 3 א 60 -66-
= 1
= 2
= 3
אא
104
א
א
2
א
א10.85= 104.04 - 2 20– 2 140 = 4
א 80
= 4
אEFE وF100Z5 2
א93.68 אE وFאא 2
אא-5
EF EF א 35.96 34.52 30.12 22.45 10.85
1 2 3 4
0.0 20 40 60 80
E7F
אEFא100א
K10אאאאאא °64אאא
א
10= °32= هـ
°64=
2
א100 =
EFא-1
א62.49 = °32 C100= هـ =∴ E2-3FKKKKKKKKKKKKKKKKא 2
هـ 2
EFאא-2 KC2= E3–3FKKKKKKKKKKKKא
א105.98 = °32C 100C2=
א 52.99= 105.98 = و 2
-67-
2
אא
104
א
א
2
א
EFאא -3 0.0=
E هـ–1F= 2
א15.195 = E° 32 J 1F100=∴
{1אאאא-4 E11-3Fא
2 E 1
2
⎛⎞و ⎜ ⎟J ⎝2⎠
2FJ 2 E2J 2F= 1
א14.69 = ( 2 52.99 J 2100FJ
1
2
E 210J 2100F =1 א 10
א13.17 = 84.81J 2 E 220J 2100F= 1
א10.58= 84.81J א6.84=84.81 א1.79=84.81J
1 2 1 2 1 2
2
E 230J 2100F= 3
E 240J 2100F= 4
E 250J 2100F = 5
= 1
א 20
= 2
א 30
= 3
א 40
= 4
א 50
= 4
אא
EF EF א 15.195 0.0 14.69 10 1 13.17 20 2 10.58 30 3 6.84 40 4 1.79 50 5
-68-
אא
104
א
א
2
א
EFאאא אא אאאאאאאא
K
אאאא KE2F -1
K -2
Kאא-3 Kא -4
אא
אא-1 Kא
EFא-2
אEFא
KEF
KEFאאא -3
KEFא-4
E2J 3FאEFאE2{1Fא-5
אאאEFאאאE هـ=F 2
E2Fאאאא1
אKE2{1F KE2{1Fא
אEFאאEFאא-6
אאE وFאאE هـ2= FE3-3F 2
2
EFאאאEFאאE وF 2
EFEFאE{FאאאEF
אאEFאE1Fא -69-
אא
104
א
א
2
א
E17–3F
F{E=FEFאEFא -7
אEFE21FאאE هـJ 1F= 2
EFאEFא
E17–3F
אאאאאאאE17–3F אאאEFא ﻴﺘﻡ א-8 אE وFאא 2
WE11-3FאEFאEF
2
(
و 2
) - 2 ﻧﻖ
-
ن
2
س- 2 ﻧﻖ
= صن
Kאאאאא
אאאאא-9
אאEFאאאאאא
2{1אEFאEFא -70-
אא
104
א
א
2
א
א{אא אאEFאEFא אEFE1Fאאא
אE´4{´3{2´{1´FאEFא EFא
E´4{´3{2´{1´FאEFאאE4{3{2{1F E 17-3 F
2{1FאE´4{´3{2´{1´FאE4{3{2{1Fא
א א אאאאE4{3{ אאאE2FאEFא{ {אאE8{7{6{5Fאאא
{{1{2{2{4{1FאאאE8{7{6{5{4{3{2{1Fא
E17-3 FאאאאE2{8{7{6{5
אאאאא 10-3 אאאאאאאא {אאאאאא
א{
אאאאאא{אאא Kא
E18-3Fאאא
-71-
אא
104
א
א
2
א
אאאאאE18-3F E1FאאאאאאאW 1 E1Fא אאאאאאאW´ אE3–2FאE2-1FאE2אFאאE1F Kא{20{10E4-3F E2 FאאאאאאאאW2 E4J 2Fא{E18-3FE4Fאא אאE1Fאאאאאאאאאא= 1 -72-
אא
104
א
א
2
א
אאאאאאE11FאאE11Fא Kאאא אאאאאא= ´ KE413FאאE312FאאE211FאאE1Fאא אאאאאאEאFאאאאא= 2 E214FאאE1Fאאא אאאאאא א1-10-3 E21FאE19–3F E12J 3FKKKKKKKKKKKKK
و′ = ﻧﻖ2
´
אאאאאאאא אאאאKE1Fאא
Kא
-73-
אא
104
א
א
2
א
אאאאאאE19–3F E´FאאאEFאE2-1Fא Wא ( 2-1 ) ﻃﻮل اﻟﻘﻮس ـــــــــــــــــــــــــــــــ ﻧﻖ
( 2-1 ) ﻃﻮل اﻟﻘﻮس ـــــــــــــــــــــــــــــــ ﻧﻖ2
-74-
=EאאF´2
=´
אא
104
א
א
2
א
E2-1FאאאE ﻧﻖF≥E´Fאא 20
אאאE´FאE2-1Fא ( 2-1 ) ﻃﻮل اﻟﻘﻮس ـــــــــــــــــــــــــــــــ ﻧﻖ2
= EאאF´2
360 × ´و ـــــــــــــــــــــــــــــــ و′ ×90 ط2 × ﻧﻖ2 = EF´
ﻧﻖ× ط
´ × و90 E13–3FKKKKKKKKKKK =EF´ ــــــــــــــ ـــ
אE2{1FאאE13J 3Fא E 2{ 1FאאE1Fאאאא -75-
אא
104
א
א
2
א
E8F
אא 200א
אאKא2256.59 EFא°30אאא Kאאאאאא
א
א10= °15= هـ
°30=
2
א200 =
אא-أ
א53.59 = °15 C200= هـ =∴
ط× ﻧﻖ × هـ 180
104.72
=
2
= ∴ EFא 30 × 200 × ط 180
= × هـ
ط× ﻧﻖ 180
= ∴
א{2{1-ب
EFא–EFא=1E1F א2203.00 = 53.59 - 2256.59=
EFא+E1F=2E2F
א2307.72 =104.72 + 2203.00 =
א2010E´FאאאאG ﻧﻖ≥´ 20
10= 200 ﻧﻖ 20
20
=
10=
E´Fא= E1FאאאE3F א2210= אE2203F
2א=אאאE4
F
א2300.00= Eא2307.72F
W21אאE5F
-76-
אא
104
א
א
2
א
2280 , 2270 , 2260 , 2250 , 2240 , 2230 , 2220 , 2210 , 2203.00 F E2307.72 , 2300 , 2290 ,
1–אאא=
אאא- ﺟـ
E1FאאאE1F
א7.00= 2203.00J 2210.00=
E ﻧﻖ≥F10=E´FאאאE2F 20
אאא–E2 F= E2FאאאE3F א7.72= 2300.00 - 2307.72=
אאJ אא ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ ´و
= EFאאאE4F
2210J 2300
9 = = ـــــــــــــــــــــــــــــــــــــــــــــــــــEFאאאE5F 10 1HEFא= אאE6F 10= 1+9=
אאאא-د
אאאאE13–3Fא
1و′ ×90 7×90 = =EF1 ﻧﻖ × ط × ط200 و′ ×90 10×90 °1 ´25 ¨57 = = =EF´ ﻧﻖ× ط × ط200 7.72×90 و′ ×90 °1´06 ¨21= = =EF 2 × ط200 ﻧﻖ× ط
°1 ´00 ¨10 =
-77-
אא
104
א
א
2
א
°15= =
هـ 2
אא- هـ E2HCH1F
°1 ´00 ¨10 = E2HCH1F 9C °1 ´25 ¨57 °1´06
H
¨21H
°15 ´ 00 ¨ 04 =
אא{אא4¨
א-و
אאא
א
E1Fא
אאא א אא א Eא °1 ´00 ¨10 °1 ´00 ¨10 7.00 2210 1
2FZZ
°2 ´26 ¨07
°1 ´25 ¨57
10
2220
2
E3FZZ
°3 ´52 ¨04
°1 ´25 ¨57
10
2230
3
E4FZZ
°5 ´18 ¨01
°1 ´25 ¨57
10
2240
4
E5FZZ
°6 ´43 ¨58
°1 ´25 ¨57
10
2250
5
°08 ´09 ¨55 °1 ´25 ¨57
10
2260
6
°09 ´35 ¨52 °1 ´25 ¨57
10
2270
7
°11 ´01 ¨49 °1 ´25 ¨57
10
2280
8
°12 ´27 ¨46 °1 ´25 ¨57
10
2290
9
°13 ´53 ¨43 °1 ´25 ¨57
10
2300
10
7.72
2307.72
2
אאאFא
E
E6FZZ E7FZZ E8FZZ E9FZZ E10FZZ 2א
°15 ´00 ¨04
°1´06 -78-
¨21
אא
104
א
א
2
א
אאאאאאאאאא
אאאאאEFאאאאא
Kאא
E9F
אאאאאאאאאא
956.67 EFא°24אאאא 205א Kאאאאא
א
°12= هـ
°24=
2
205 =
956.67 = EF
Wאא-أ
43.57 = °12 C205= هـ =EFאE1F 2
ط× ﻧﻖ × هـ 180
= EFאE2F
85.87
=
24o ×205 × ط 180
= × هـ
ط× ﻧﻖ 180
= ∴
א{2{1-ب
EFא–EFא=1E1F 913.10 = 43.57 - 956.67=
EFא+E1F=2E2F
998.97=85.87 + 913.10 = 10.25 =
205 = ﻧﻖ 20 20
E ﻧﻖ≥´F10=E´FG 20
E´Fא= E1FאאאE3F 920.00= E913.10F1
2א=אאאE4F
-79-
אא
104
א
א
2
א
990.00= E998.97F
W21אאE5F
E 998.97 , 990 , 980 , 970 ,960 ,950 ,940, 930, 920, 913.10 F 1–אאא=
אאא - ﺟـ
E1FאאאE1F
א6.90= 913.10J 920.00=
E ﻧﻖ≥F10=E´FאאאE2F 2
אאא–E2 F= E2FאאאE3 F 8.97= 990.00 - 998.97=
אאJ אא ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ ´و
أوﺗﺎر7 =
= EFאאאE4F
920J 990 ــــــــــــــــــــــــــــــــ= 10
8 = 7 + 1 =1 HEFא= אאE5F
אאאא-د
אאאאE13–3Fא
1× و90 6.90×90 °00´57 ¨51= = =E1FאאאאאE1F ﻧﻖ × ط × ط205 ´× و90 10×90 °01´23¨51= = =E´FאאאאאE2F ﻧﻖ × ط × ط205
-80-
אא
104
א
א
2
א
8.97×90 2× و90 °01´15¨13 = = =E2FאאאאאE3F × ط205 ﻧﻖ × ط هـ
°12 = 24 = = 2
2
א א- هـ
E2HCH1F
°00 ´57 ¨51 = E2HCH1F 7C °01
´23
°01´15
¨51
H
¨13H
°12 ´ 00 ¨ 01 = Kאא{אא¨1
א -و
אאא
א
אאא א אאא א א א א
E1F א°00´57 ¨51 2FZZ °02 ´21 ¨42
°00´57 ¨51 °01´23¨51
E3FZZ
°03 ´45 ¨33
E4FZZ
א
920
1
10
930
2
°01´23¨51
10
940
3
°05 ´09 ¨24
°01´23¨51
10
950
4
E5FZZ
°06 ´33 ¨15
°01´23¨51
10
960
5
E6FZZ
°07 ´57 ¨06
°01´23¨51
10
970
6
E7FZZ
°09 ´20 ¨57
°01´23¨51
10
980
7
E8FZZ
°10 ´44 ¨48
°01´23¨51
10
990
8
2א
°12 ´00 ¨01
°01´15¨13
8.97
998.97
2
E
-81-
6.90
אא
104
א
א
2
א
W
אאEFאאאEFאא
אאאאא{EF אאאE2{´FאKE´Fא WאאKE2{´F
E10F
אאאאאאאאאא
אאא°24אאא 400א
K
א
°12= هـ
°24=
2
400 =
Wאא-أ
85.02 = °12 C400= هـ =EFאE1F 2
ط× ﻧﻖ × هـ 180
= EFאE2F
167.55
=
24o ×400 × ط 180
= × هـ
ط× ﻧﻖ 180
= ∴
אאא-ب 20 =
400 = ﻧﻖ 20 20
E1F
ﻧﻖ≥´Q 20
20 = ´∴
ل אא=E´FאאE2F و′ -82-
אא
104
א
א
2
א
8.377= 167.55 = لQ و′
20
8= E´Fאא∴
´CE´Fאא=אאאE3F 160 = 20 C8=
אאא–= E2FאאאE4F
7.55= 160 - 167.55= אאאא - ﺟـ WאאאאE13–3Fא
´× وo 90 20×90 °01´25 ¨57= = =E´FאאE´FאאE1F ﻧﻖ × ط × ط400 ´× وo 90 7.55×90 °00´32¨27= = = ( 2 )אאE2FאאE2F ﻧﻖ × ط × ط400
°12 = 24 = = 2
هـ 2
אא- هـ
E2HCH1F
8C °01 ´25 ¨57 =WאאאאE1F °00´32
¨27H
°12 ´ 00 ¨ 03 = אא{אא¨3 °12= هـE2F 2
K
-83-
אא
104
א
א
2
א
א-و
אאאא
א
E1Fא
°01´25 ¨57
אאא אא א °01´25 ¨57 20 1
E2FZZ
°02 ´51 ¨54
°01´25 ¨57
20
2
E3FZZ
°04 ´17 ¨51
°01´25 ¨57
20
3
E4FZZ
°05 ´43 ¨48
°01´25 ¨57
20
4
E5FZZ
°07 ´09 ¨45
°01´25 ¨57
20
5
E6FZZ
°08 ´35 ¨42
°01´25 ¨57
20
6
E7FZZ
°10 ´01 ¨39
°01´25 ¨57
20
7
E8FZZ
°11 ´27 ¨36
°01´25 ¨57
20
8
2א
°12 ´00 ¨03
°00´32¨27
7.55
2
EאאאאF
-84-
אא
104
א
א
2
א
EFאאא אא KEאאאFאאאאאא אאאא -1 -2
א ﺛﻼﺛﻪ-3 -4 אא
אא-1 K،א
אEFא-2
אEF KEF
KEFאאא-3
KEFא-4
E2-3FאEFאE2{1Fא-5
אאאEFאאאE هـ=F 2
אאאEFאאE1Fאא
KE2{1FE2F KE2F
Wאאא-6
אאאאאEFא- أ
KEFאEאFאא
EFאE هـ.ﻧﻖ
180
.ط
=Fא-ب
KE2،1Fא -85-
אא
104
א
א
2
א
א،אאE2،´،1Fאאא- ﺟـ
10אאאאא E1Fאא E ﻧﻖF،אא20 20
אאE´Fאאאא אE ﻧﻖF2010E´Fא 20
אאאE1FאאאE2Fאא
KEFאאE´CF
אאאאאאEFא-د KE1Fא
KאE هـ=E2HCH1Fאא- هـ 2
E20-3Fא-7
E20-3F
אE1Fא-أ KאאאEF
-86-
אא
104
א
א
2
א
אאE1Fאאאאא-ب
E1FאE1Fאא
E1FאאאאE1F KE1Fא
אאאאE´Fאאאאאאא- ﺟـ
אאE1FאE´FאE´H1F KE2Fאאא
אאאאE´Fאאאאא-د
،אאE2FE´FאE´2H1F KE3Fאאא
Kאאאאאא - هـ אא אא
E2Fאאאאאא E2FאאE2Fאאאאא
אא،אE2Fאאאא א10J 5א،אא
E2FאאE2Fאאאאא
Kא
אא
E215FאאE1FE2Fאאאאא
،אE2FאאאאאE20-3F אאאאE2Fא
KE2HCH1F
-87-
אא
104
א
א
2
א
אאאאא 11-3
،1Fאא،E21-3 F
E12F،E11FאאE1FאE2
E3FאE22F{E21FאאE2Fא
אאE32FאE31Fאא אאאאאא
אאאאאאE 21-3F
אאKאאאאאאא
א،،אא
אאאאKE 21-3Fא
KאאאאE2،´،1Fא -88-
אא
104
א
א
2
א
EFאאא Wאא KE2Fא אאאא KE2F-1 K-2
K-3
K-4 אא אא -1 K{א
EFא-2 אEFא
KEF
KEFאאא -3
KEFא-4
E2J 3FאEFאE2{1Fא-5
אאאEFאאאKE هـ=F 2
אאאEFאאE1F
KE2{1F{E2F
KאאאאE2{´{1Fאאאא -6
אאE1Fאאא-7
אא{E2Fא
KאאאאEF
אE1FאאאE1Fאאאא-8 אאאE2Fאאא
-89-
אא
104
א
א
2
א
אאE1H هـJ °360F 2
אאא{אא
E22-3FאאE1Fא
E22-3F
אאאאאE1Fאאא-9 E2FאאאאE´H1Fא
אE´H1H هـJ 360Fאאאאאא 2
E2Fאאאא
KE2F{E22-3F{א
אאאאאא-10 Kאאא
-90-
אא
104
א
א
2
א
אא
E1FאE2Fאאאא
אאאאאאא{אאאאא
אאא{אE1Fאא
אאאאאE2FאאאאKE1Fאא
KE´H1Fאא{
-91-
אא
104
א
א
2
א
א225אW1 KאאאאK°30אאאאEFא א175אW2 KאאאאK°40 ´45אאאאEFא Wאא°4אW3 Kא20אאJ Kא20 אאJ אא245אW4 אאאאאאK°44אאא
Kא20אאאא
אאאא140אW5 אאאאאאאK°48א KE10F אאאא215אW6 א20אאאאאK °50 Kאאא -92-
אא
104
א
א
2
א
אא 150אW7 אאאאK°80אאא אאאאא(20)א אאאא120אW8 KE10FאאאאאאK°56א אאאא185אW9 א20אאאאאאK°62
-93-
אא
104
א
א
2
א
EאאFאא Kאאא Wא
321Wא
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKWאא KKKKKKKKKKKKKKKKKKKKKKKWא
Kא
Kא٪80Wא א KKKKKKKKKWא
Kא٪100Wאא א
א
אאא
٪100אא
א
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKW
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK KKKKKKKKKKKKKKKKKKKKKKKKKKKKWא
-94-
אא
104
א
א
2
א
EאאFאא Kאאאא
אאאאאא
E3F{אאאאאא
אאאא{אאא
K
אאאאWאאאאא
א
EאאFאא
א
א K1
א K2
אאאEאFאאא
אאא? ???א{ Kא
-95-
אאא
اﻟﻤﺆﺳﺴﺔ اﻟﻌﺎﻣﺔ ﻟﻠﺘﻌﻠﻴﻢ اﻟﻔﻨﻲ واﻟﺘﺪرﻳﺐ اﻟﻤﻬﻨﻲ אאאא
2
א
א
4
אאא
104
א
א
2
א
אWאאא אא אאJ אאJ אאJ אא Kאאאאא אא אאאאא Kאא אא Kאאאא אא Kאאאאא٪100א
-96-
אאא
104
א
א
2
א
אא 1-4 ،אאאאאא
،אא{אא א،،אאאא
אא،אאא،
E1-4Fא
E1-4F
אEFאאאא
אאא،אא
א،אא،אא
Kא
-97-
אאא
104
א
א
2
א
אאאא2-4 Wאאאא Kאא-1
Kאא،אאא-2 אא אא א א -3 Kא
אא1-2-4 א،א، אא
א، ،א ،א
، 50 – 10 א א ، א א א א
،אאאא ،30 – 20 אאא ،אאאא Kאא
אא،אאאאא
אא،אאא،אא א א،אאא،א
Kאאא،אאא
-98-
אאא
104
א
א
2
א
א2-2-4 אא، אא
אא،אאא א،אאא،א
Kא
KאאG
Kאא،אאאG
אא،אאאא،אאא אG אא،אאאאאא{אאא،א
אא،אאא
אא ،א ،א Kא،א،א
،אאאא ،אאאG Kאאאא
אא3-4 Wאאאא،אא KאאאאאאE1 KאE2 Wא Kאא،
،א אאאאאא
Kאאאא،
א، אא 100א،٪1אאא،
Kאאאאא
-99-
אאא
104
א
א
2
א
Wאא EאאאCאF±Zא
אאאאאאWאאא אאEHF אאEJ F א 72.20אא אא E 1F
Kאא20א%2 א Wא Wאא{{ 72.20=אא K72.60Z20C0.02 H72.20= אא K73.00Z40C0.02 H72.20= אא K73.40Z60C0.02 H72.20= אאא אאא-3
אאא ،א אאא
Kאאא،אאא،א
אא =א
אא
א א ، א א א ،אא א، א א
-100-
אאא
104
א
א
2
א
1 { 1 { 1 { 1 { 1 { 1 { 1 1000 750 500 300 250 200 100
אא 1 { 1 { 1 { 1 { 1 100 75 25 20 10
אאא -4 ، ،אא אא א،E،،FE2-4FאאK ، ،אאאא، א Wאאא،א
Kא– א
א– א
-101-
אאא
104
א
א
2
א
EFE2-4F
EFE2-4F
EFE2-4F -102-
אאא
104
א
א
2
א
א-5 א ، אא
אאא،א
אאא،אא،א
א3L2،2L1،1L1אאאKא E4-4FE3-4FאאK
א א
א
אE3-4F
אCאZא א C אאZא
א
אאאא א -103-
אאא
104
א
א
2
א
אE4-4F
xEאCאאF±אzCא=א xEאאCאאF±אzCאא=א
א-6 ،אאאאאא א
Kאאאא ،אאאא
،،א
،אא،אא، ،אאאא
KE5-4Fאא
E5-4F
א
אאCZא 2 -104-
אאא
104
א
א
2
א
אאאא ،אאאא
אאK א
،א،א א
E6-4FKאא
1
2 1
2
E6-4FW
אW1 אאW
אW2
C2 C1
אW1
אW2
=E2Fא=E1Fא 2 H1 2 H1
2
H1Zא
-105-
אאא
104
א
א
2
א
2C21C1
ZאZא 2 2
א،אא
Kא
E2F אא ،120 אאא
אא،30
ﺟﺪﻭﻝ ﺃﺭﺻﺎﺩ ﻣﻴﺰﺍﻧﻴﺔ ﶈﻮﺭ ﻃﻮﱄ ﺑﻄﺮﻳﻘﺔ – ﺳﻄﺢ ﺍﳌﻴﺰﺍﻥ ﺍﳌﻨﺴﻮﺏ ﻣﻠﺤﻮﻇﺎﺕ
ﻣﻨﺴﻮﺏ
ﺍﻟﻘﺮﺍﺀﺍﺕ ﻋﻠﻰ ﺍﻟﻘﺎﻣﺔ
ﺳﻄﺢ ﺍﳌﻴﺰﺍﻥ
ﻣﺴﺎﻓﺎت اﻷﻓﻘﻴﺔ
ﺭﻗﻢ
ﺟﺰﺋﻴﺔ ﺗﺮﺍﻛﻤﻴﺔ ﻣﺆﺧﺮﺓ ﻣﺘﻮﺳﻄﺔ ﻣﻘﺪﻣﺔ
ﺍﻟﻮﺗﺪ
1.7
B.M 1 2 3 4 5 B.M
80 2.4 2.03 2.7 2.06 2.3 1.68
:א 80א،אאאאJ 1 K٪1א79.80אא،א-2 K1:25،1: 200 אא-3 Kאאא-4 -106-
אאא
104
א
א
2
א
K1.2אא،-5 Kאא-6 Kאא -7 א Kאאא-1 ﺟﺪﻭﻝ ﺃﺭﺻﺎﺩ ﻣﻴﺰﺍﻧﻴﺔ ﶈﻮﺭ ﻃﻮﱄ ﺑﻄﺮﻳﻘﺔ – ﺳﻄﺢ ﺍﳌﻴﺰﺍﻥ ﺍﳌﻨﺴﻮﺏ ﻣﻠﺤﻮﻇﺎﺕ
ﻣﻨﺴﻮﺏ
ﺍﻟﻘﺮﺍﺀﺍﺕ ﻋﻠﻰ ﺍﻟﻘﺎﻣﺔ
ﺳﻄﺢ
80 79.30 79.67 79.00 79.64 79.40 80.02
ﺍﳌﻴﺰﺍﻥ 81.7
ﺭﻗﻢ
ﻣﺴﺎﻓﺎت اﻷﻓﻘﻴﺔ
ﺟﺰﺋﻴﺔ ﺗﺮﺍﻛﻤﻴﺔ ﻣﺆﺧﺮﺓ ﻣﺘﻮﺳﻄﺔ ﻣﻘﺪﻣﺔ
ﺍﻟﻮﺗﺪ
1.7
B.M 1 2 3 4 5 B.M
2.4 2.03 2.7 2.06 2.3 1.68
Wאא 0.02Zא–אא K1
0.02Z
– K2 א-2
KEאאאCאFHאא= 79.80=אא 80.10=E30C0.01FH 79.80=אא 80.40=E60C0.01 FH 79.80=אא -107-
אאא
104
א
א
2
א
80.70 =E90C0.01FH 79.80=אאא 81=E120C0.01FH 79.80=אא אא-3 -4Fאאא KE7 -108-
אאא
104
א
א
2
א
E7-4F אא-4 אא–א=אא 0.5=79.30–79.80=E 1Fאא 0.43=79.67 –80.10=E2Fאא 1.40= 79.00 –80.40=E3Fאא 0.06 = 79.64–80.70=E 4Fאא K 1.06 = 79.40 –81=E5Fאא Kאא -5 אאCא=א 2
2
0.516=0.43C1.20 =E2Fא
2
2
0.6=0.5C 1.20=E1Fא
1.68=1.40 C1.20=E3Fא
1.272=1.06C1.20=E4Fא 2
1.92=1.60C1.20=E5Fא א -6
א
אאCZא -1092
אאא
104
א
א
2
א
0.516 + 0.60 3 16.74 =30 C=אאאא 2 1.68H0.516 3
3
23.94 =30 C=אאאא 2 1.272H1.68
3
44.28 =30 C=אאאאא 2 1.92H1.272
47.88 =30 C=אאאאא 2
א-7 Kאא=א
3
141.84= 47.88H44.28H32.94H16.74=א -110-
אאא
104
א
א
2
א
-111-
אאא
104
א
א
2
א
E3F א،10אא،40 א،א،אאא
אא–א ﻣﻠﺤﻮﻇﺎﺕ
ﺍﳌﻨﺴﻮﺏ
ﻣﻨﺴﻮﺏ
ﺍﻟﻘﺮﺍﺀﺍﺕ ﻋﻠﻰ ﺍﻟﻘﺎﻣﺔ
ﺳﻄﺢ ﺭﻭﺑﲑ
20
ﺍﳌﻴﺰﺍﻥ 22.30
20
ﺭﻗﻢ
ﺟﺰﺋﻴﺔ ﺗﺮﺍﻛﻤﻴﺔ ﻣﺆﺧﺮﺓ ﻣﺘﻮﺳﻄﺔ ﻣﻘﺪﻣﺔ
ﺍﻟﻮﺗﺪ
2.3
B.M
3.21 3.41 3.81 2.71 3.40 ﺭﻭﺑﲑ
ﻣﺴﺎﻓﺎت اﻷﻓﻘﻴﺔ
2.3
1 2 3 4 5 B.M
J Wא K20אאאא -1 %2 א،19.50אא،א-2 1:20، 1 : 250אא -3 Kאאא-4 K 1.75אא،-5 Kאא-6 Kאא-7
Kאא-8 -112-
אאא
104
א
א
2
א
א אאא -1 אא–א ﻣﻠﺤﻮﻇﺎﺕ
ﺍﳌﻨﺴﻮﺏ
ﻣﻨﺴﻮﺏ ﺳﻄﺢ
ﺍﳌﻴﺰﺍﻥ 22.30
ﺭﻭﺑﲑ
20
ﺭﻭﺑﲑ
19.09 18.89 18.29 19.59 18.90 20
ﺍﻟﻘﺮﺍﺀﺍﺕ ﻋﻠﻰ ﺍﻟﻘﺎﻣﺔ
ﺭﻗﻢ
ﻣﺴﺎﻓﺎت اﻷﻓﻘﻴﺔ
ﺟﺰﺋﻴﺔ ﺗﺮﺍﻛﻤﻴﺔ ﻣﺆﺧﺮﺓ ﻣﺘﻮﺳﻄﺔ ﻣﻘﺪﻣﺔ
ﺍﻟﻮﺗﺪ
2.3
B.M
3.21 3.41 3.81 2.71 3.40
1 2 3 4 5 B.M
2.3
:اﻟﺘﺤﻘﻴﻖ اﻟﺤﺴﺎﺑﻲ
0.0 =
ﳎﻤﻮﻉ ﺍﳌﺆﺧﺮﺍﺕ – ﳎﻤﻮﻉ ﺍﳌﻘﺪﻣﺎﺕ.1
0.0 = ﻣﻨﺴﻮﺏ ﺁﺧﺮ ﻧﻘﻄﺔ – ﻣﻨﺴﻮﺏ ﺃﻭﻝ ﻧﻘﻄﺔ.2 א-2 KEאאאCאFHאא= 19.30=E10C0.02FJ
19.50=אא
19.50=אא
19.10=E20C0.02 FJ 19.50=אא
18.90 =E30C0.02FJ 19.50=אאא
18.70=E40C0.02FJ 19.50=אא אא -3
-4Fאאא KE8 -113-
אאא
104
א
א
2
א
אאE8-4F אאE8-4F -114-
אאא
104
א
א
2
א
אאא-4 אא–א=אא אJ אא=א 0.41 =19.09– 19.50 = ( 1)אא 0.41 = 18.89 –19.30=( 2)אא 0.61 = 18.29–19.10=( 3)אא 0.69 =19.59–18.90=( 4)א 0.20= 18.90 –18.70 = ( 5)א א -5 אאאCא=א 2
0.718= 0.41C1.75=( 1)א
2
2 2
0.718=0.41C1.75 = ( 2)א 1.068=0.61 C1.75=( 3)א
1.208=0.69 C 1.75=( 4)א
20.35= 0. 2C 1.75=( 5)א Wא-6 א
אאCZא 2
-115-
אאא
104
א
א
2
א
0.718 + 0.718 3 E F 7.18 =10 C=אאאא 2 1.068H0.718
EF3 9.93 =10C=אאאא 2 0.35H1.208
EF37.79 =10 C=אאאאא 2
אאE4F{E3Fאאא -7
4.692
10C1.068+3 =
ـــــــــــــــــــــــــــــ
=
ـــــــــــــــــــــــــ
=
1
س
+ 3 10C1.208+4
1.208 +1.0684
5.308
=
ـــــــــــــــــــــــــــــــ
=
ـــــــــــــــــــــــــ
=
2
س
+ 3
1.208 + 1.0684
10= 5.308 + 4.692=
2
سH
1
س
4.692C1.068 1 س×3 3
2.506 =
ــــــــــــــــــــــــــــــــــــــ
2
=
ــــــــــــــــــــــــ
2
=א
-116-
אאא
104
א
א
2
א
5.308 C1.0682×4 3
3.206 =
ـــــــــــــــــــــــــــــــــــــــ
2
=
ـــــــــــــــــــــــــ
2
=א
א-8 Kאא=א
3
18.616 = 2.506H8.93H7.18=א
3
10.996 = 3.206H7.79=א -117-
אאא
104
א
א
2
א
EFאאאא אאא אאא אאאא אא א Kא -1
Kאא{א -2
Kאאא-3 Kאא-4
Kאאא-5 אאא אאא-1 אאאאא-2 אאא{אא-3 Kא Kאא-4 Kאאאאא-5 -118-
אאא
104
א
א
2
א
Wאאא Kאאאא-1 Kא-2 KאאJ 3 KאאאJ 4 Kאאאא- 5 KאאאאJ 6 KאאJ 7
-119-
אאא
104
א
א
2
א
אא
4-4 ،אא א א{אא
א،אא אא
אאאא
E9–4F א،אאאאאK50–10 KE9-4FאאKא
-120-
אאא
104
א
א
2
א
،אא، אאא
אא، אאאאא
א،אאאא،אא Kאאא
אאא1-4-4 אאא ،אאאא אאאאא
א{אא{א
E4F א א ،אא
א אאא ،אא
،אאא،אא אא،אאאא
،א،א
،אאאאאאאאא
אאא ،א Kאא، אא2-4-4
،אאאאאא Kא،א، א3-4-4 אאא،אא Wא Zאאאא
EאאCאFHאא= -121-
אאא
104
א
א
2
א
KאאEJ FאאEHF א،א א א Kא אא 4-4-4 אא ،אא،אא
אא {E2J 4Fא אא
א،،،K Kאא
א
אCZא 2
אCא Zא 2
E10-4F -122-
אאא
104
א
א
2
א
C4C½=E1Fא 4ع+3ع C=E2 Fא 2 3 ع+ 2 ع C = E3 Fא 2 C2 عC½= E4Fא
C2C4 Z{Z
2H15H4
Kא= א
-123-
אאא
104
א
א
2
א
E4F א،5460
אאאא،20 א4
Kאא
Wא 32.111אאאאאא-1
K %2א 32אאאא-2 K1: 25 {1:500אא -3 Kאאא- 4
Kאאא-5
K 1 : 25 ، 1:200 אא -6
Kאא-7 Kאא-8
-124-
אאא
104
א
א
2
א
?אא?אא ﻣﺘﻮﺳﻄﺔ
ﻣﺆﺧﺮﺓ
ﺍﳌﺴﺎﻓﺎﺕ ﻳﺴﺎﺭ
32.111
ﳏﻮﺭ
ﺭﻗﻢ ﺍﻟﻮﺗﺪ ﳝﲔ
0.905 2.196 2.207 2.033 2.028 1.871 1.998 1.916 1.653 1.564 0.973 2.536 1.231 1.610 1.213 1.273 0.789 1.173 1.084 1.201 1.238 0.905
4 4 0.0 4 4 4 4
20 4 4
4 4 40 4 4 4 4
B.M 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
ﺭﻗﻢ
ﺍﻟﻘﻄﺎﻉ
ﺍﻷﻭﻝ
ﺳﻄﺢ ﺍﳌﻴﺰﺍﻥ
ﻣﻘﺪﻣﺔ
ﺍﻟﺜﺎﱐ
ﻣﻨﺴﻮﺏ
ﺍﻟﺜﺎﻟﺚ
ﺍﳌﻨﺴﻮﺏ
16 60 4 4
17 18 19 20 B.M
ﺍﻟﺮﺍﺑﻊ
ﻣﻠﺤﻮﻇﺎﺕ
Wאא
Zא–אא Z–
E1F E2F
-125-
אאא
104
א
א
2
א
א
אאא -1 ?אא?אא
ﺍﳌﻨﺴﻮﺏ
ﻣﺘﻮﺳﻄﺔ
ﻣﻘﺪﻣﺔ
33.016
Wאאא
ﺍﳌﺴﺎﻓﺎﺕ ﻳﺴﺎﺭ
ﺍﳌﻴﺰﺍﻥ
E4FWא
ﻣﺆﺧﺮﺓ
ﺳﻄﺢ
32.111 30.820 30.809 30.983 30.988 31.145 31.018 31.100 31.363 31.452 32.043 30.453 31.785 31.406 31.803 31.743 32.227 31.843 31.932 31.815 31.778 32.111
ﳏﻮﺭ
ﳝﲔ
0.905 2.196 2.207 2.033 2.028 1.871 1.998 1.916 1.653 1.564 0.973 2.536 1.231 1.610 1.213 1.273 0.789 1.173 1.084 1.201 1.238 0.905
4 4 0. 4 4 4 4
20 4 4
4 4 40 4 4 4 4
ﺭﻗﻢ
ﺭﻗﻢ
ﺍﻟﻮﺗﺪ
ﺍﻟﻘﻄﺎﻉ
B.M 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
ﺍﻷﻭﻝ
ﻣﻠﺤﻮﻇﺎﺕ
ﺍﻟﺜﺎﱐ
ﻣﻨﺴﻮﺏ
Wא
ﺍﻟﺜﺎﻟﺚ
16 60 4 4
17 18 19 20 B.M
ﺍﻟﺮﺍﺑﻊ
Wא
:ﺍﻟﺘﺤﻘﻴﻖ ﺍﳊﺴﺎﰊ 0.0= 0.905–0.905= א–אאE1F
0.0= 32.111J 32.111=–E2F
-126-
אאא
104
א
א
2
א
J Wא2J KEאאאCאFJ = KE18،13،8،3Fאא K32=E3Fא 31.600=E20C0.02F–32=E8Fא 31.200= E40C0.02F–32=E13Fא 30. 800=E60C0.02F–32=E18Fא KE9-4FאאJ Wאא-3 אאא-4 1.017= 30.983– 32.00 =אא 0.237=31.363– 31.60=אא K0.206= 31.20–31.406=אא K1.132= 30.80–31.932=אאא
-127-
אאא
104
א
א
2
א
E9-4FאאJ Wאא-3 E9-4F -128-
אאא
104
א
א
2
א
אJ 5
E10-4 Fאאא =E5FE1Fא KEאאCאFJ אא= אאEJ F{אאEHF K30=E½C4F–32.000= 0.820= 30J 30.820= 1W 1.191= 32J 30.809 = 2 1.017= 32J 30.983= 3 1.012= 32J 30.988= 4 1.145= 30J 31.145= 5 {אW 4 × 1.012 ×ل4ع 1.877 = س = ـــــــــــــ = ــــــــــــــــــــــــــ 1.145 + 1.012 5 ع+ 4 ع 4C1.191 C2
2.369 === 1.191H0.8202H1
-129-
אאא
104
א
א
2
א
אW 2
م
4.416
= 4 ×
1.017 + 1.191 = ـــــــــــــــــــــــــــ 2
ل
4H3
1.012 + 1.017 2
م
4.058
= 4 ×
= ـــــــــــــــــــــــــــ 2
ع+2ع × ( = ـــــــــــــــــــــــ3 ) ﻣﺴﺎﺣﺔ اﻟﺸﻜﻞ 2 3
ل
× ( = ـــــــــــــــــــــــ2 ) ﻣﺴﺎﺣﺔ اﻟﺸﻜﻞ 2
20.950 =1.877C1.191 C1/2 =C4 C1/2 =E1 Fא 21.411 =2.369C1.191 C1/2 =C2 C1/2 =E4 Fא אא إﺟﻤﺎﻟﻲ 1.411+ 0.950 + 4.058+ 4.416 = אא∴ 3
10.835 =
E10-4 Fאא
-130-
אאא
104
א
א
2
א
אא-5 אאא אאא E10-4F -131-
אאא
104
א
א
2
א
אאא E11-4 Fאאא =E10F{E6Fא KEאאCאFJ אא= 29.600=E½C4FJ 31.600 = אאאW EFKKKKKKKKK1.418= 29.600J 31.018 = 6W EFKKKKKKKKKKKK0.500= 31.600J 31.100 = 7 EFKKKKKKK0.237= 31.600J 31.363= 8 EFKKKKKKKKKKK0.148=31.600 J 31.452= 9 EFKKKKKKKKKKKK2.443= 29.600J 32.043= 10 {אW 4 × 0.148 ﻣﺘﺮ0.229 = ــــــــــــــــــــــــــ 2.443 + 0.148
×ل9ع = س = ـــــــــــــ 10 ع+ 9 ع
4C0.50 C7
1.043 === 1.418H0.57H6
-132-
אאא
104
א
א
2
א
אW 2
م1.474
=
4 ×
(0.237 + 0.5) = ـــــــــــــــــــــــــــ 2
ع+7ع ( = ـــــــــــــــــــــــ × ل3 ) ﻣﺴﺎﺣﺔ اﻟﺸﻜﻞ 2 8
9H8
(0.148 + 0.237) 2
م
0.77
= 4 ×
= ـــــــــــــــــــــــــــــــــ 2
ل
× ( = ـــــــــــــــــــــــ2 ) ﻣﺴﺎﺣﺔ اﻟﺸﻜﻞ 2
20.017 =0.229C0.148 C1/2 =C9 C1/2 =E1 Fא 20.261 =1.043C0.5 C1/2 =C7 C1/2 =E4 Fא אא إﺟﻤﺎﻟﻲ 0.261+ 0.017 + 0.77+ 1.474 = אא
2
2.522 =
KE11- 4 Fאא -133-
אאא
104
א
א
2
א
אא-5 אאא אאא E11-4F -134-
אאא
104
א
א
2
א
אאא E12-4 Fאאא =E15F{E11Fא KEאאCאFJ אא= K33.20=E½C4F+31.200 = אאאW EF2.747= 33.20 J 30.453 = 11W EF0.585= 31.200J 31.785 = 12 EF0.206= 31.200J 31.406= 13 EF0.603= 31.200J 31.803= 14 EF1.457= 33.200J 31.743= 15 {אW 4 × 0.603 م1.171 = ــــــــــــــــــــــــــ 1.457 + 0.603
× ل14 ع = س = ـــــــــــــ 15 ع+ 14 ع
4C0.585 C12 0.702 = ص = ـــــــــــــــــ = ـــــــــــــــــــــــ 2.747H0.58512H11
-135-
אאא
104
א
א
2
א
אW 2
م
1.582
=
4 ×
(0.206 + 0.585) = ـــــــــــــــــــــــــــــــ 2 (0.603 + 2.206)
2
م
1.618
= 4 ×
= ـــــــــــــــــــــــــــــــــ 2
( 13 ع+ 12 )ع = ـــــــــــــــــــــــــــــ × لE3 Fא 2
E14H13
)
= ـــــــــــــــــــــــــــــ × لE2 Fא 2
20.353 =1.171C0.603 C1/2 =C14 C1/2 =E1 Fא 20.205 =0.702C0.585 C1/2 =C12 C1/2 =E4 Fא אא إﺟﻤﺎﻟﻲ 0.205+ 0.353 + 1.618+ 1.582 = אא 2
3.758 =
KE12- 4 Fאא -136-
אאא
104
א
א
2
א
אאא אאא E12-4F -137-
אאא
104
א
א
2
א
אאאא E13-4 Fאאאא =E20F{E16 Fא KEאאCאFHאא= K32.80=E½C4F+31.200 = אאאW EF0.573J = 32.80 J 32.227 = 16W EF1.043= 30.80J 31.843 = 17 EF1.132= 30.80J 31.932= 18 EF1.015= 30.80J 31.815= 19 EF1.022J = 32.80J 31.778= 20 {אW
4 × 1.015 م1.993 = ــــــــــــــــــــــــــــ 1.022 + 1.015 4 × 1.043 م2.582 = = ــــــــــــــــــــــــــــ 0.573 + 1.043
× ل19 ع = س = ـــــــــــــ 20 ع+ 19 ع × ل17 ع س = ـــــــــــــ 18 ع+ 17 ع
-138-
אאא
104
א
א
2
א
אW 2
م
4.35
= 4 ×
(1.132 + 1.043) = ــــــــــــــــــــــــــــــ 2
× ل
E19H18)
(1.015 + 1.132) 2
م
4.294
= 4 ×
= ـــــــــــــــــــــــــــــــــ 2
(18 ع+ 17 )ع = ـــــــــــــــــــــــE3 Fא 2
ل
× = ـــــــــــــــــــــــE2 Fא 2
21.012 =1.015C1.132 C1/2 =C19 C1/2 =E1 Fא 21.347 =2.582C1.043 C1/2 =C17 C1/2 =E4 Fא אאא إﺟﻤﺎﻟﻲ 1.347+ 1.012 + 4.294+ 4.350 = אא 2
11.003 =
KE13 - 4 Fאא -139-
אאא
104
א
א
2
א
אאאא E13-4F -140-
אאא
104
א
א
2
א
Kאא-7
ﻣﺠﻤﻮع ﻣﺴﺎﺣﺘﻲ اﻟﻘﻄﺎﻋﻴﻦ × = ـــــــــــــــــــــــــــــــــــــــא 3
3
2.522+10.835 133.57 = 20
×
= ـــــــــــــــــــــــــــــــــــــــ
2
EFE8 F{E3Fא
3.758+2.522 62.800 = 20
× = ـــــــــــــــــــــــــــــــــــــــ
EFE18F{E13Fא
2 1{אאE13F{E8Fאאא
K2
ﻣﺘﺮ8.03 =
50.44 ــــــــــــــــــ 6.28
20 × 2.522 = = ــــــــــــــــــــــــــــ 3.758 + 2.522
× ل8 م = ـــــــــــــ1 س 13 م+ 8 م
ﻣﺘﺮ11.97 =
75.16 ــــــــــــــــــ 6.28
20 × 3.758 = = ــــــــــــــــــــــــــــ 3.758 + 2.522
× ل13 م = ـــــــــــــ2 س 13 م+ 8 م
2.522 × 8.03 1×س8م م10.128 = = ــــــــــــــــــــــــ = ـــــــــــــא 2 2 3.758 × 11.97 2 × س13 م 3 م22.47 = = ــــــــــــــــــــــــــــ = ــــــــــــــــــא 2 2 Kאא-8 3 145.698=10.128H133.57=א إﺟﻤﺎﻟﻲ 3
3
85.27= 22.47 H62.800 =א -141-
אאא
104
א
א
2
א
EFאאאא K،אא، אאאא אא Wא Kא-1 Kאאאא-2 Kא-3 Kאא-4 Kאאאא-5 אאא אאאאאא -142-
אאא
104
א
א
2
א
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