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I

L F

C E B

O

D N

K H

A G M

J

√ ON 3 0 = tg30 = ND 3 r = ND = 1 √ √ 3 3 = ON = N D 3 3 √ NC = tg600 = 3 ND √ √ NC = ND 3 = 3 R = OL = (N C − ON ) + LC LC = r = 1 √ √ 3 +1 R= 3− 3 √ 2 3+1 R= 3 x = πR2 − 3πr2 = π(R2 − 1)   !2 √ 3 + 1 2 − 3 x = π 3 x=

√ 2 π(2 3 − 1) ≈ 5.16 3

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