I
L F
C E B
O
D N
K H
A G M
J
√ ON 3 0 = tg30 = ND 3 r = ND = 1 √ √ 3 3 = ON = N D 3 3 √ NC = tg600 = 3 ND √ √ NC = ND 3 = 3 R = OL = (N C − ON ) + LC LC = r = 1 √ √ 3 +1 R= 3− 3 √ 2 3+1 R= 3 x = πR2 − 3πr2 = π(R2 − 1) !2 √ 3 + 1 2 − 3 x = π 3 x=
√ 2 π(2 3 − 1) ≈ 5.16 3