Question 1: A car is traveling at a constant speed of 60 km/h. The car's engine provides a constant power of 40 kW. Calculate the resistive force acting on the car.
Solution: The resistive force acting on the car can be calculated using the equation: Power = Force x Velocity
Given: Power = 40 kW
Velocity = 60 km/h = 60,000 m/3600 s = 16.67 m/s
Therefore, the resistive force can be calculated as follows:
Force = Power / Velocity
Force = 40,000 W / 16.67 m/s
Force ≈ 2,400 N
Question 2: A cylindrical pressure vessel has a diameter of 0.5 meters and a height of 1 meter. It is filled with a gas at a pressure of 2 MPa.
Calculate the total force exerted by the gas on the walls of the vessel.
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Solution:
The total force exerted by the gas on the walls of the vessel can be calculated using the equation:
Force = Pressure x Area
Given:
Pressure = 2 MPa = 2 x 10^6 Pa
Area = π x (diameter/2)^2
Substituting the values, we get:
Area = π x (0.5/2)^2
Area ≈ 0.1963 m^2
Therefore, the total force exerted by the gas can be calculated as follows: Force = 2 x 10^6 Pa x 0.1963 m^2 Force ≈ 392,600 N
Question 3: A beam of length 4 meters is supported at each end and carries a uniformly distributed load of 10 kN/m. Calculate the maximum bending moment experienced by the beam.
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Solution: The maximum bending moment experienced by the beam can be calculated using the formula:
Maximum Bending Moment = (Load x Length^2) / 8
Given:
Load = 10 kN/m = 10,000 N/m
Length = 4 meters
Therefore, the maximum bending moment can be calculated as follows:
Maximum Bending Moment = (10,000 N/m x 4^2) / 8
Maximum Bending Moment = 20,000 Nm
Question 4: A heat exchanger is used to transfer heat from hot water at 80°C to cold water at 20°C. The hot water flows at a rate of 2 kg/s, while the cold water flows at a rate of 3 kg/s. Calculate the rate of heat transfer in kilowatts.
Solution:
The rate of heat transfer can be calculated using the equation:
Rate of Heat Transfer = Mass Flow Rate x Specific Heat Capacity x Temperature Difference For Any Help Regarding Mechanical Engineering Assignment Help Visit:- https://www.mechanicalengineeringassignmenthelp.com/ Email:- info@mechanicalengineeringassignmenthelp.com
Given:
Mass Flow Rate (hot water) = 2 kg/s
Mass Flow Rate (cold water) = 3 kg/s
Specific Heat Capacity = 4.18 kJ/kg°C
Temperature Difference = (80 - 20)°C = 60°C
Therefore, the rate of heat transfer can be calculated as follows:
Rate of Heat Transfer = (2 kg/s + 3 kg/s) x 4.18 kJ/kg°C x 60°C
Rate of Heat Transfer ≈ 1,256.4 kW