Box dimension and Hausdorff dimension of Uniform Cantor Set

Page 1

International Journal of Applied Mathematics & Statistical Sciences (IJAMSS) ISSN (P): 2319-3972; ISSN (E): 2319-3980 Vol. 9, Issue 3, Apr–May 2020; 31–38 © IASET

BOX DIMENSION AND HAUSDORFF DIMENSION OF UNIFORM CANTOR SET K. J. Shinde1 & S. M. Padhye2 1

Research Scholar, Department of Mathematics, CAET, Dr. Panjabrao Deshmukh Krishi Vidyapeeth, Akola (MS), India 2

Research Scholar, Department of Mathematics, RLT College of Science, Akola (MS), India

ABSTRACT The properties of uniform Cantor sets are proved and determined that Cantor ternary sets Cantor – Cantor –

set, Cantor –

set, Cantor –

set, Cantor –

set, Cantor –

set,

set are uniform Cantor sets by using the definition of uniform

Cantor set. Also, determined box dimension and Hausdorff dimension of uniform Cantor set as well as Cantor like sets.

KEYWORDS: Box Dimension, Cantor Set, Hausdorff Dimension

Article History Received: 09 Apr 2020 | Revised: 15 Apr 2020 | Accepted: 24 Apr 2020

1. INTRODUCTION Definition 1.1: Let F be any nonempty bounded subset of ℝ and let most

( ) be the smallest number of sets of diameter at ( ) =

which can cover F. The lower and upper box dimensions of F are defined respectively as ( )

( )=

and

( )

.

Definition 1.2: Let m ≥ 2 be an integer and 0 < <

. Let I = [ 0 , 1 ]. We construct a Cantor like set by the following

procedure. The set is then called as uniform Cantor set. At first stage, from I we remove (m-1) intervals each of length subintervals!

,#

(1≤ i ≤ m) of lengths |!| =

The left end of ! of subintervals !

,#

,

i.e. &! ,# &=

, 1≤ i ≤ m .

coincides with left end of I and right end of !

,

coincides with right end of I. Let ( be union

(1≤ i ≤ m).

At second stage, we remove from each ! all

, leaving behind m equally spaced

equally spaced subintervals !

,

,!

,

,#

, ….. ,!

(

(1≤ i ≤ m), (m-1) intervals each of length ,#

(1≤ i ≤

)

(

)

, leaving behind in

) of equal lengths &! ,# & i.e. &! ,# &=

, 1≤ i ≤

. The

extreme ends of subintervals coincide with the extreme ends of basic subintervals remaining at first stage. Let ( be union of subintervals!

,

,!

,

, ….. ,!

,#

(1≤ i ≤

).

At third stage, we remove from each ! in all

equally spaced subintervals !

www.iaset.us

,

,!

,

,#

(1≤ i ≤

, ….. ,!

,#

), (m-1) intervals each of length (1≤ i ≤

)

)( )(

) )

) of equal lengths &! ,# & i.e. &! ,# &=

, leaving behind , 1≤ i ≤

.

editor@iaset.us


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