Preview Chemistry for the IB Diploma Exam Preparation Guide

Page 51

4.7 Sigma and pi bonds (HL only)

Worked example 4.3

2– O1 O4 S O2 O3 Structure 1

Two alternative Lewis structures for SO42− are shown here. Use the concept of formal charge to deduce which is the better representation of the actual structure. Structure 1

2– O1 O4 S O2 O3 Structure 2

Structure 2 Formal Charges

S O1 O2 O3 O4

1 × 8 0 = 2+ 2 1 FC = 6 − × 2 6 = 1− 2 1 FC = 6 − × 2 6 = 1− 2 1 FC = 6 − × 2 − 6 = 1− 2 1 FC = 6 − × 2 − 6 = 1− 2

FC = 6 −

1 × 12 − 0 = 0 2 1 FC = 6 − × 2 6 = 1− 2 1 FC = 6 − × 4 4 = 0 2 1 FC = 6 − × 2 − 6 = 1− 2 1 FC = 6 − × 4 4 = 0 2

FC = 6 −

S O1 O2 O3 O4

The sum of the formal charges on all the atoms should add up to the overall charge on the molecule/ion.

Structure 2 has lower individual formal charges (S in Structure 1 has a 2+ charge) and therefore it is the preferred Lewis structure. T E S T Y O UR SELF 4. 7

Use the concept of formal charge to work out the preferred Lewis structures for: − − SO3 PO43 ClO4 XeO4

4.7 Sigma and pi bonds (HL only) Sigma (σ) bonds result from the axial (head-on) overlap of atomic orbitals. The electron density in a σ bond lies mostly along the axis joining the two nuclei.

p orbital

p orbital

σ

A pi (π) bond is formed by the sideways overlap of parallel p orbitals. The electron density in the π bond lies above and below the internuclear axis (Figure 4.18). Figure 4.17

Single bond

σ

H H

Double bond Triple bond

σ

C σ

H

H

C

σ σ

H

H

σ+π

σ + 2π

σ

σ

H H

σ

σ

C σ

C

π σ π σ π

σ

H

C

C

σ

H H

H

σ σ

σ

C

σ

C

side-on overlap

H

σ

head-on overlap

side-on overlap

H

H σ

sigma bond

σ

H H

H

π C

C

H

H H

π- bond

Figure 4.18 σ

H

41


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