Cambridge Checkpoint Mathematics Coursebook 7

Page 15

1.4 Factors and tests for divisibility

Divisible by 7 Divisible by 8 Example Divisible by 9 Example Divisibility by 10 or 100

There is no simple test for 7. Sorry! A number is divisible by 8 if its last three digits form a number that is divisible by 8. 17 816 is divisible by 8 because 816 is. 816 รท 8 = 102 with no remainder. Add the digits. If the sum is divisible by 9, so is the original number. This is similar to the test for divisibility by 3. The number 6786, used for divisibility by 3, is also divisible by 9. Multiples of 10 end with 0. Multiples of 100 end with 00.

Exercise 1.4 1 The number 18 has six factors. Two of these factors are 1 and 18. Find the other four. 2 Find all the factors of each of each number. a 10 b 28 c 27 e 11 f 30 g 16

d 44 h 32

3 The number 95 has four factors. What are they? 4 One of the numbers in the box is different from the rest. Which one, and why? 5 The numbers 4 and 9 both have exactly three factors. Find two more numbers that have exactly three factors.

13

17

21

23

29

Think about the factors of 4 and 9.

6 Find the common factors of each pair of numbers. a 6 and 10 b 20 and 25 c 8 and 15 d 8 and 24 e 12 and 18 f 20 and 50 7 There is one number less than 30 that has eight factors. There is one number less than 50 that has ten factors. Find these two numbers. 8 a Find a number with four factors, all of which are odd numbers. b Find a number with six factors, all of which are odd numbers. 9 Use a divisibility test to decide which of the numbers in the box: a is a multiple of 3 b is a multiple of 6 c is a multiple of 9 d has 5 as a factor. 10 a Which of the numbers in the box: i is a multiple of 10 ii has 2 as a factor iii has 4 as a factor iv is a multiple of 8?

421

222

594

12 345

67 554

55 808 55 810 55 812 55 814 55 816 55 818

b If the sequence continues, what will be the first multiple of 100?

1

Integers

13


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