the function
Curve Text f(x) = x − 3 4x Find the equation of the tangent line of f at the point where x = 2 Text Derivative of a polynomial dx dy a = n nan−1
Given
Equation of Tangent to The
f(x) = x − 3 4x dx dy = 3x − 2 4 Evaluate the first derivative at x = 2 dx dy (2)= 3(2) − 2 4 dx dy (2)= 8 Slope of the tangent line
f(x) = x − 3 4x Find the y value for x = 2 f(2) = (2) − 3 4(2) f(2) = 8−8 f(2) = 0 (2,0) Point located in f Slope=dx dy (2)= 8 With slope and a point you can write the equation of the line tangent y − y = 1 m(x − x )1 y +0 =8(x −2) y = 8(x −2)