Ncert Solutions For Class 10 Maths

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FORMULAE 1. Mean (π‘₯Μ… ) = 2. Mean (π‘₯Μ… ) =

π‘₯1+ π‘₯2+ π‘₯3 + ⋯…..+π‘₯𝑛 𝑛

=

βˆ‘π‘₯ 𝑛

βˆ‘ 𝑓 𝑖 π‘₯𝑖

3. Mean (π‘₯Μ… ) = A +

βˆ‘ 𝑓𝑖 𝑑𝑖 βˆ‘ 𝑓𝑖 βˆ‘ 𝑓𝑖 𝑒𝑖

4.Mean (π‘₯Μ… ) = A +β„Ž (

βˆ‘ 𝑓𝑖

𝑛+1 π‘‘β„Ž

5 . a) If n is odd, then Median = the value of ( b) If n is even, then Median =

2

βˆ‘ 𝑓𝑖

, where𝑑𝑖 = π‘₯𝑖 βˆ’ 𝐴 ) , where 𝑒𝑖 =

π‘₯π‘–βˆ’π΄ β„Ž

) observation

𝑛 π‘‘β„Ž 𝑛+1 π‘‘β„Ž the value of ( ) observation+ the value of ( ) observation 2 2

2

QUESTIONS 1. If the mean of the numbers 15, 20, a, 32, b is 25, find b in terms of a. 2. The mean of 11 results is 30. If the mean of first 6 results is 28 and that of the last 6 results is 32, find the 6th results. 3. The mean weight of a class of 35 students is 45 kg. If the weight of the teacher be included the mean weight increases by 500 g. find the weight of the teacher. 4. If the median of 11, 12, 14, 18, x +2, x + 4, 30, 32, 35, 41 is 24, find the value of x. 5. The mean of 30 values is 150, if 2 is subtracted from every number, what will be the new mean ? 6. Find the median of: 19, 25, 59, 48, 35, 31, 30, 32, 51.If 25 is replaced by 52, find the new median. 7. For what value of p, the mode of following data is 5 : 1, 2, 5, 7, 5, 2, 7, 5, 9, 2, 3, p, 11. 8. The mean of the following frequency table is 50. But the frequencies 𝑓1 π‘Žπ‘›π‘‘ 𝑓2 in the class 20-40 and 60-80 are missing. Find the value of 𝑓1 and 𝑓2 . Class Frequency

0-20 17

20-40 𝑓1

40-60 32

60-80 𝑓2

80-100 19

Total 120

9. Find the mode of the following distribution by drawing a histogram. Daily wages(in Rs) No. of workers

31-36

37-42

43-48

49-54

55-60

61-65

6

12

20

15

9

4

10. The frequency distribution of weights of a group of 80 students in a class in a school is given below : Weights(in kg) 40-44 45-49 50-54 No. of students 5 8 14 Draw the histogram and find the modal weight.

55-59 20

60-64 16

65-69 10

70-74 7

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