SOLUTIONS MANUAL
Fundamentals of Momentum, Heat, and Mass
Transfer 7th Edition By James Welty, Gregory
Rorrer, David Foster | All Chaters 1-31
Part 1: End of Chapter Problem Solutions
Part 2: Instructor Only Problems Solutions
Part 3: Show/Hide Problems Solutions
1.1
Chapter 1 End of Chapter Problem Solutions
n = 4 x 1020 molecules/in3
= = 1.32x104 in./s
A= (10-3 in)2
NA = n A=1.04x108 m/s
Flow Properties: Velocity, Pressure Gradient, Stress
Fluid Properties: Pressure, Temperature, Density, Speed of Sound, Specific Heat
mass of solid= ρsvs mass of fluid= ρfvf
mix= = =
1.4
Given = 7
For P1= 1 atm = 1.01
P= 3001(1.01)7 – 3000 = 217 atm
1.5
At Constant Temperature = constant = constant
For 10% increase in P must also increase by 10 %
1.6
Since density varies as & =nM (M=Molecular wt.)
n250,000= nS.L. = 4 x 1020 = 2.5 x 1016