ITM 500 Data and Information Management _ Lab Week 10 Questions. Create a view called V1 that will s

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--Lab Week 10 Questions --Using the Animal2 DB undertake the following --1) Create a view called V1 that will show a count -- of experts and their average and maximum salary amount for each Species. Note NULL is not a species. go DROP VIEW V1 go CREATE VIEW V1( Species, ExpertCnt, SalaryAvg, SalaryMax) AS (SELECT Species, COUNT(*), AVG(Salary), MAX(Salary) FROM Employee WHERE Species IS NOT NULL GROUP BY Species) go SELECT * FROM V1 --2) Create a view called V2 which will have for each Species Status a count of the number species and the average, maximum and minimum value of the estimated numbers in the wild CREATE VIEW V2( SpeciesStatus, NumberOfSpecies, AverageInWild, MinInWild, MaxInWild) AS (SELECT Status, COUNT(Status), AVG(EstNoInWild), Min(EstNoInWild), Max(EstNoInWild) FROM Species GROUP BY Status) SELECT * FROM Species --3) Create a view called V3 that will show a count of animals by zoo.

CREATE VIEW V3(NameOfZoo, CountOfAnimals) AS (SELECT ZooName, COUNT(AnimalID) FROM Animal WHERE Species IS NOT NULL GROUP BY ZooName) --Then using these views write the following queries --4) List the details for the zoo that has had the highest number of animals SELECT z.* FROM Zoo Z INNER JOIN V3 s3 ON z.ZooName = s3.ZooName WHERE CountOfAnimals = (SELECT MAX(CountOfAnimals) From V3) --5) List the species details for the species whose has an estimated number in the wild below the average for its status SELECT s.* FROM Species S INNER JOIN V2 s2 ON S.Status = s2.Status WHERE S.EstNoInWild < AverageInWild --6) List the Employee details for any Employee that has the highest salary for their species expertise

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SELECT e.* FROM Employee E INNER JOIN V1 s1 ON e.Species = s1.Species WHERE Salary = SalaryMax --7) List the details of the animals held for the species that have the lowest estimate number for their status SELECT A.* FROM Animal A INNER JOIN Species S ON A.Species = S.Species INNER JOIN V2 s2 ON S.status = s2.status WHERE EstNoInWild = MinInWild

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