DATABASE MANAGEMENT SYSTEM _Write a PL/SQL block to change address of a particular employee by takin

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Siddhesh Sunil Kubal 16BCI0045

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EXERCISE 7

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1. Write a PL/SQL block to change address of a particular employee by taking his/her

employee number interactively.

DECLARE

NUM EMPLOYEE.SSN_NUMBER % TYPE;

ADR EMPLOYEE.ADDRESS % TYPE;

BEGIN

NUM := '&SSN_NUMBER';

SELECT ADDRESS INTO ADR FROM EMPLOYEE WHERE SSN_NUMBER = NUM;

DBMS_OUTPUT.PUT_LINE('OLD ADDRESS : '||ADR);

ADR := '&NEW_ADDRESS';

DBMS_OUTPUT.PUT_LINE('NEW ADDRESS : '||ADR);

UPDATE EMPLOYEE SET ADDRESS=ADR WHERE SSN_NUMBER = NUM;

END;

/

SQL> @ Z:\DBMS\PLSQL\file.sql

Enter value for ssn_number: 333445555

old 15: NUM := '&SSN_NUMBER';

new 15: NUM := '333445555';

Enter value for new_address: 123 ABC, VELLORE

old 23: ADR := '&NEW_ADDRESS';

new 23: ADR := '123 ABC, VELLORE';

PL/SQL procedure successfully completed.

=====================================================================================

2. Write a PL/SQL block to display number of employees for each department.

DECLARE

NUM NUMBER;

DN EMPLOYEE.DEP_NUMBER % TYPE;

CURSOR CUR IS SELECT COUNT(*), DEP_NUMBER FROM EMPLOYEE GROUP BY(DEP_NUMBER);

BEGIN

OPEN CUR;

FOR EACH IN 1..4 LOOP

FETCH CUR INTO NUM, DN;

DBMS_OUTPUT.PUT_LINE('COUNT : '||NUM||' DEP NUMBER : '||DN);

END LOOP;

CLOSE CUR;

END;

/

SQL> @ Z:\DBMS\PLSQL\file2.sql

COUNT : 2 DEP NUMBER : 1

COUNT : 3 DEP NUMBER : 5

COUNT : 3 DEP NUMBER : 4

COUNT : 3 DEP NUMBER : 3

PL/SQL procedure successfully completed.

=====================================================================================

3. Write a program to delete employee details who are having age >60.

DECLARE

NUM EMPLOYEE.SSN_NUMBER % TYPE;

CURSOR CUR IS SELECT SSN_NUMBER FROM EMPLOYEE WHERE (MONTHS_BETWEEN(SYSDATE, BIRTHDAY)/12) > 60 ;

BEGIN

OPEN CUR;

FOR EACH IN 1..2 LOOP

FETCH CUR INTO NUM;

DELETE FROM EMPLOYEE WHERE SSN_NUMBER = NUM;

DBMS_OUTPUT.PUT_LINE('1 ROW DELETED SSN NUMBER : '||NUM);

END LOOP;

CLOSE CUR;

END;

/

SQL> @ Z:\DBMS\PLSQL\file4.sql

1 ROW DELETED SSN NUMBER : 123456789

1 ROW DELETED SSN NUMBER : 666884444

PL/SQL procedure successfully completed.

===================================================================================== 4. Write a PL/SQL block to display employees who are top three earners in the

company.

DECLARE

NAME EMPLOYEE.FIRST_NAME % TYPE;

SAL EMPLOYEE.SALARY % TYPE;

CURSOR CUR IS SELECT FIRST_NAME, SALARY FROM EMPLOYEE ORDER BY (SALARY) DESC;

BEGIN

OPEN CUR;

FOR EACH IN 1..3 LOOP

FETCH CUR INTO NAME, SAL;

DBMS_OUTPUT.PUT_LINE('NAME : '||NAME||' SALARY : '||SAL);

END LOOP;

CLOSE CUR;

END;

/

SQL> @ Z:\DBMS\PLSQL\file1.sql

NAME : DOUG SALARY : 80000

NAME : JOYCE SALARY : 70000

NAME : JAMES SALARY : 55000

PL/SQL procedure successfully completed.

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5. Write a PL/SQL to delete a records whose basic salary is <20000 from Emp table.

DECLARE

NUM EMPLOYEE.SSN_NUMBER % TYPE;

CURSOR CUR IS SELECT SSN_NUMBER FROM EMPLOYEE WHERE SALARY < 20000;

BEGIN

OPEN CUR;

FOR EACH IN 1..1 LOOP

FETCH CUR INTO NUM;

DELETE FROM EMPLOYEE WHERE SSN_NUMBER = NUM;

DBMS_OUTPUT.PUT_LINE('1 ROW DELETED SSN NUMBER : '||NUM);

END LOOP;

CLOSE CUR;

END;

/

SQL> @ Z:\DBMS\PLSQL\file3.sql

1 ROW DELETED SSN NUMBER : 943775543

PL/SQL procedure successfully completed.

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EXERCISE 8

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Aim: To know the usage of different sequential and conditional control structures in

PL/SQL blocks.

1. Write a PL/SQL block to find the greatest of three numbers.

DECLARE

A NUMBER;

B NUMBER;

C NUMBER;

BEGIN

A := &FIRST_NUMBER;

B := &SECOND_NUMBER;

C := &THIRD_NUMBER;

IF A>B AND A>C THEN

DBMS_OUTPUT.PUT_LINE('GREATEST NUMBER IS : '||A);

ELSIF B>C THEN

DBMS_OUTPUT.PUT_LINE('GREATEST NUMBER IS : '||B);

ELSE

DBMS_OUTPUT.PUT_LINE('GREATEST NUMBER IS : '||C);

END IF;

END;

/

SQL> @ Z:\DBMS\PLSQL\file2.1.sql

Enter value for first_number: 10

old 9: A := &FIRST_NUMBER;

new 9: A := 10;

Enter value for second_number: 20

old 10: B := &SECOND_NUMBER;

new 10: B := 20;

Enter value for third_number: 30

old 11: C := &THIRD_NUMBER;

new 11: C := 30;

GREATEST NUMBER IS : 30

PL/SQL procedure successfully completed.

===================================================================================== 2. Write a PL/SQL code to print the employee’s cadre based on their basic scales as

given below (hint use: case selector….)

Basic Scale Cadre

45000 Manager

35000 Supervisor

25000 Worker

DECLARE

NAME EMPLOYEE.FIRST_NAME % TYPE;

SAL EMPLOYEE.SALARY % TYPE;

TYP VARCHAR2(20);

RET VARCHAR2(20);

CURSOR CUR IS SELECT FIRST_NAME, SALARY FROM EMPLOYEE;

BEGIN

OPEN CUR;

FOR EACH IN 1..8 LOOP

FETCH CUR INTO NAME, SAL;

IF SAL>=45000 THEN

TYP := 'A';

ELSIF SAL>=35000 THEN

TYP := 'B';

ELSIF SAL>=25000 THEN

TYP := 'C';

END IF;

RET :=

CASE TYP

WHEN 'A' THEN 'MANAGER'

WHEN 'B' THEN 'SUPERVISOR'

WHEN 'C' THEN 'WORKER'

END;

DBMS_OUTPUT.PUT_LINE('NAME : '||NAME||' CADRE : '||RET);

END LOOP;

CLOSE CUR;

END;

/

SQL> @ Z:\DBMS\PLSQL\file2.2.sql

NAME : DOUG CADRE : MANAGER

NAME : JOYCE CADRE : MANAGER

NAME : FRANKIN CADRE : SUPERVISOR

NAME : JENNIFER CADRE : SUPERVISOR

NAME : JOYCE CADRE : WORKER

NAME : JAMES CADRE : MANAGER

NAME : ALICIA CADRE : WORKER

NAME : AHMAD CADRE : WORKER

PL/SQL procedure successfully completed.