A light emitting diode radiates 2 mW. Compute dBm value this radiated power. The power travels throu

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A light emitting diode radiates 2 mW. Compute dBm value this radiated power.

The power travels through a group a components having a combined loss of 23 dB. Compute the output power.

Answer & Explanation Solved by verified expert (a) Radiated power = 3.0 dBm (b) Output power = 0.01 mW Step-by-step explanation (a) The expression to convert power in mW to dBm is: PdBm = 10 log10 ( PmW / 1 mW ) PdBm = 10 log10 ( 2 mW /1 mW) = 3.0 dBm

(b) Output Power = 3.0 dBm - 23 dB = -20 dBm 10 log10 P0 (mW) = -20 dBm P0 = 10-2 = 0.01 mW