Full file at https://testbankuniv.eu/Calculus-Single-Variable-6th-Edition-Hughes-Hallett-Solutions-Manual Tangent line
B 1.5(0.2) = 0.3 0.2
A = (4, 25)
0.15 C
0.1
Figure 2.9 18. (a) Since the point B = (2, 5) is on the graph of g, we have g(2) = 5. (b) The slope of the tangent line touching the graph at x = 2 is given by Slope = Thus, g ′ (2) = −0.4.
5 − 5.02 −0.02 Rise = = = −0.4. Run 2 − 1.95 0.05
19. See Figure 2.10.
y y = f (x)
✻✻
(c) f (x + h) − f (x)
❨
❄
✻
(e) Slope =
f (x+h)−f (x) h
(b) f (x + h) (a) f (x)
❄
❄
x
✛
(d) h
x
x+h
✲
Figure 2.10 20. See Figure 2.11. y
(e) Slope =
✻
f (x+h)−f (x) h
✻
✠
(c) f (x + h) − f (x) (which is negative) (a) f (x) (b) f (x + h)
❄ x ✛
(d) h
❄ ✻ ❄
y = f (x)
x ✲+ h
x
Figure 2.11
Full file at https://testbankuniv.eu/Calculus-Single-Variable-6th-Edition-Hughes-Hallett-Solutions-Manual
2.2 SOLUTIONS
105