Algebra and Trigonometry 5th Edition Blitzer Solutions Manual F u l l D o w n l ohat dt p: s : / / a l i b a b a d o w n l o a d . c o m / p r o d u c t / a l g e b r a - a n d - t r i g o n o m e t r y - 5 t h - e d i t i o n - b l i t z e Chapter 1 Equations and Inequalities
Section 1.6
x+5 − x−3 = 2
4.
x +5 = 2+ x−3
Check Point Exercises
(
4 x 4 = 12 x 2
1.
4 x 2 ( x 2 − 3) = 0
or
x=± 0
x=± 3
x=0
x=± 3
{
}
(1)
x2 − 4 = 0 5.
x2 = 4
a.
)
= ( x − 3)
(
=
x −3
)
2
5 x 3/ 2 − 25 = 0 x 3/ 2 = 5
(x )
3/ 2 2 3
= ( 5)
23
x = 52/3 or
3
25
Check:
x +3 = x−3 x+3
x−3
5 x 3/ 2 = 25
x+3 +3 = x
(
2
x = ±2
3 The solution set is −2, − , 2 . 2
2
) (
x−3 +
1= x −3 4=x The check indicates that 4 is a solution. The solution set is {4} .
(2 x + 3)( x 2 − 4) = 0
3.
2
4 4 x −3 = 4 4 1= x−3
x 2 (2 x + 3) − 4(2 x + 3) = 10
2 x= − 3 3 x=− 2
2
) + 2 ( 2) ( x −3
4 = 4 x−3
2 x 3 + 3x 2 = 8 x + 12
2 x + 3 = 0 or
2
x+5 = 4+ 4 x−3 + x −3
x2 − 3 = 0 x2 = 3
The solution set is − 3, 0, 3 . 2.
) = (2 +
x + 5 = ( 2)
4 x 4 − 12 x 2 = 0
4 x2 = 0 x2 = 0
x+5
5 ( 52/3 )
2
3/ 2
− 25 = 0
5 ( 5 ) − 25 = 0
x + 3 = x2 − 6x + 9
25 − 25 = 0
0 = x − 7x + 6 0 = ( x − 6)( x − 1) x − 6 = 0 or x − 1 = 0
0=0
2
The solution set is {52/3 } or
x=6 x =1 1 does not check and must be rejected. The solution set is {6} .
{ 25} . 3
2 x 3 − 8 = −4 x 2/3 = 4
b.
( x2/3 )
3/2
= 43/2
or
( )
x = 22
3/2
x = 23
x = (−2)3
x = −8 x=8 The solution set is {–8, 8}.
144
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)
2