Solutions manual for precalculus with limits a graphing approach texas edition 6th edition by larson

Page 33

72 27.

Chapter 2 f ( x) =

3x 3x = x 2 − x − 2 ( x + 1)( x − 2)

33.

f ( x) =

2+ x x+2 =− 1− x x −1

Vertical asymptote: x = 1 Horizontal asymptote: y = −1

Intercept: (0, 0) Vertical asymptotes: x = −1, 2 Horizontal asymptote: y = 0

Domain: x ≠ 1 or (−∞, 1) ∪ (1, ∞) 35.

−3 0 3 4 1 9 3 9 6 y − 0 − 10 2 4 5 x 2 + 3x x( x + 3) x f ( x) = 2 = = , x + x − 6 ( x − 2)( x + 3) x − 2

Domain: t ≠ 0 or (−∞, 0) ∪ (0, ∞)

x ≠ −3 Intercept: (0, 0) Vertical asymptote: x = 2 (There is a hole at x = −3. ) Horizontal asymptote: y = 1

37. h(t) =

y

31.

f ( x) =

−2 −1 1 1 2 3

4 t2 + 1

Domain: all real numbers or (−∞, ∞) Horizontal asymptote: y = 0

39. x

3t + 1 t

Vertical asymptote: t = 0 Horizontal asymptote: y = 3

x

29.

f (t ) =

0

1

2

0

−1 Undef.

3 3

x 2 − 1 ( x + 1)( x − 1) = = x − 1, x +1 x +1

x ≠ −1 The graph is a line, with a hole at x = −1.

f ( x) =

x +1 x +1 = 2 x − x − 6 ( x − 3)( x + 2)

Domain: all real numbers except x = 3, −2 Vertical asymptotes: x = 3, x = −2 Horizontal asymptote: y = 0


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