Linear Inequalities

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Linear Inequalities Linear Inequalities

Friends! Today we are going to discuss some complex mathematical problems of class 10th and also elaborate the solution of those problems. Most of the students require a perfect tutor for math who would assist them whenever they get fixed in any math problem. Because if the doubt doesn't get cleared at the time of problem solving then those doubts won't enable him to understand the other facts and situation of the problems. Because we all know that in math a single problem can be asked in several ways and if you are not able to understand the general form of math query then it's solution is not easy to be implemented. So being that perfect assistance for your math studies, math online help is provided by various online math tutors. math online learning is the reliable and most advanced way of learning in present time because this service works on Internet platform which is globally accessible so you can take math lessons while sitting at your home. Know More About :- Pythagorean Theorem Word Problems

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In 10th standard syllabus, graphing is important factor and easily can be done by following some predefined steps. But when this application is used for linear inequalities then it gets complex. Because although linear inequalities are linear form mathematical expressions but still its answer is not a fixed value, it stays in a certain limit of integer range. This integer range is decided according to the inequality relation and the numerical integer value of the linear inequalities equation. Inequality is introduced in any equation by using the comparison operators which are "less than(<) or greater than(>) " and " greater than equal to(>=) or less than(<=) equal to". The representation of any linear inequality equation is same as any linear equation by just replacing the equality relation with inequality as: x + y =1 ( linear equation form ) x + y <1 ( linear inequality form ) To simplify expressions of linear inequalities, two standard principles are used which are addition principle and multiplication principle: According to Addition principle ' if 'p' is less than 'q' then (p+c) will also be less than (q+ c) : if p<q : (p+c)<(q+ c). and by multiplication principle: if p<q and c>0 than pc< qc and if c<0 than pc > qc.

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Student gets introduced with linear inequalities in their previous standards but in 10th these problems are more complex, for example : x2 + 3y2 > 18 and x + y2 > 9 The above equation is compound inequality which is joined with disjunction. But the tough part of it is that the equations are not in linear form so you have to convert them first into linear form to apply the standard principles on it.

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