Limit state design (ULS-SLS) J. Walraven and S. Gmainer
z 0,5(1 1 2K ) 0,5 (1 1 2 0,144) 0,922 d
Asl
1 49,1 106 ( ) 856 mm² 435 143 0,922
So the reinforcement ratio ρ can be determined (Eqn. 3.24).
ρ
As bd
ρ
As 856,36 0,60% bd 1000 1,43
(3.24)
Longitudinal reinforcement in X-direction at mid span 1-2: K
MEd bd 2 fcd
18,32 106 0,0538 0,295 25 103 1432 1,5
z 0,5(1 1 2K ) 0,5 (1 1 2 0,0538) 0,972 d
Asl
ρ
1 18,32 106 ( ) 303 mm² 435 143 0,972
As 303 0,21% bd 1000 1,43
Longitudinal reinforcement in X-direction at mid span 2-3 and at support in axis 3: K
MEd bd 2fcd
36,95 106 0,108 0,295 25 103 1432 1,5
z 0,5 (1 1 2 K ) 0,5 (1 1 2 0,108) 0,942 d
Asl
ρ
1 36,95 106 ( ) 630 mm² 435 143 0,942
As 630 0,44% b d 1000 1,43
Longitudinal reinforcement in Y-direction at intermediate support in axis B: K
MEd bd 2 fcd
68,15 106 0,200 0,295 25 103 143 2 1,5
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