CHAPTER
VI
The Problem of Squaring the Circle THE GREEKS WERE able to construct a square equal in area to any given polygon. Thus to construct a square equal to a given parallelogram, we can use the equation x 2 = bh, where band h are the base and altitude of the parallelogram, and x is a side of the square. First construct the altitude of the given parallelogram. Then a semicircle is constructed with a
G
x
ÂŁ
D ''------v-,- - - - - A . - v - ' b h
F
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