LESSON 1 PRACTICE EXERCISE ANSWER KEY AND FEEDBACK Item
Correct Answer and Feedback
1.
C. Using the formula D = R x .51 x T, rate of aircraft speed R = 125 knots - 10 knots headwind = 115 knots x conversion factor of knots to meters .51 x time required to complete the drop. T = 30 seconds = 115 x .51 x 30 = 1,759.5m, rounded up to 1,760m (page 3, para 2).
2.
A. Using the formula GD = PD x DPRF, the potential DZ width GD = .075 x 25,000 = 571.5m, rounded down to 571m (page 5, para 5).
3.
C. Using the formula SL = VD x 100, elevation at one end = HD 300ft, HD elevation at the other end is 150ft, SL = VD (300-150ft) x 100 HD (2,000ft) SL = 150 x 100 2,000 SL = 7.5% rounded up = 8% (page 6, para 1).
4.
B. Type of load will be a major consideration when evaluating a potential DZ for accessibility (page 13, para 3).
5.
a. DZ "D" is most suitable, since it is long and wide enough; percent of slope is less than 15%; there is little vegetation, and it is easily accessible. With the forecast of headwinds of 10 knots from 2700, the aircraft flying east to west over the DZ, the required length of the DZ is 810m; DZ "D" is approximately 860m x 375m (pages 2 through 13). b. DZ "A" is not suitable because of excessive slope and it is too short (700m x 350m). c. DZ "B" is not suitable because it is neither long enough nor wide enough (580m x 300m). d. DZ "C" is not suitable because of excessive slope (nearly 35%), rugged terrain, and dense vegetation; however, the DZ is