latihan

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CHAPTER 2: LINEAR LAW PAPER 1 xy

1.

n •

• ( 8, k ) x

0

Diagram 1 10 Diagram 1 shows part of a straight line graph drawn to represent y   1. Find the values of k and x n. [answer: n  10 k  2 ] [4 marks]

2.

log10 y ( 3,9 ) •

• ( 7,1) log10 x

0 Diagram 2

Diagram 2 shows part of a straight line graph drawn to represent y = 10kxn, where k and n are constants. Find the values of k and n. [answer: n = -2,k = 15] [4 marks]

1

prepared by: cik shila 11/4/2012


y x 3.

• 12, 7 

1 x

0 • (2 , - 3 )

Diagram 3

Diagram 3 shows that the variables x and y are related in such away that when

y is plotted against x

1 , a straight line that passes through the points (12 , 7 ) and (2 , - 3 ) is obtained . Express y in x terms of x. [answer: y = 1-5x] [3 marks]

4.

log10 y

3 •

x

0

• ( 5 , -7 ) Diagram 4 Diagram 4 shows part of the graph of log10 y against x. The variables x and y are related by the a equation y  x where a and b are constants. Find the values of a and b. b [answer: a = 1000, b = 100] [4 marks ]

2

prepared by: cik shila 11/4/2012


log10 y 5. 2

0

x

4 Diagram 5

Diagram 5 shows part of the graph of log10 y against x. The variables x and y are related by the bx

equation y = a (10 ) where a and b are constants. Find the values of a and b. [answer: a = 100, b = - 1/2]

[3 marks]

6.

log10 y

• 2

• -4

0

log10 x

Diagram 6

Diagram 6 shows part of a straight line graph when log10 y against log10 x is plotted. Express y in terms of x. [answer: y  100 x ]

[4 marks]

3

prepared by: cik shila 11/4/2012


7. The variable x and y are related by equation y  pk 3 x , where k and p are constant. Diagram 7 shows the straight line obtained by plotting log 10 y against x . log 10 y

( 0, 8 ) 

(2,2) x

O Diagram 7

a) Reduce the equation y  pk 3 x to linear form Y = mX + c. b) Find the value of, i) ii)

log 10 p ,

k.

[answer: log 10 p  8 ] [answer: k = 10 ]

[4 marks]

Orang-orang Berjaya mempunyai disiplin yang tinggi.

4

prepared by: cik shila 11/4/2012


PAPER 2 1. Use graph paper to answer this question. Table 1 shows the values of two variables , x and y obtained from an experiment. Variables x n and y are related by the equation y  2rx 2  x, where r and n are constants. r x y

2 8

3 13.2

4 20

5 27.5

6 36.6

7 45.5

Table 1 (a).

(b).

y against x , using a scale of 2 cm to 1 unit on both axes. x Hence, draw the line of best fit.

[5 marks]

Use your graph in (a), to find the value of (i). n, (ii). r, (iii). y when x = 1.5.

[5 marks]

Plot

2. Use graph paper to answer this question. Table 2 shows the values of two variables , x and y obtained from an experiment. Variables x h and y are related by the equation y    kx, where h and k are constants. x x y

1 5.1

2 6.9

3 9.7

4 12.5

5 15.4

6 18.3

Table 2 (a).

(b).

Plot xy against x 2 , using a scale of 2 cm to 5 units on the x 2 -axis and 2 cm to 10 units on the xy-axis. Hence, draw the line of best fit.

[5 marks]

Use your graph in (a), to find the value of (i). h, (ii). k, (iii). y when x = 2.5.

[5 marks]

5

prepared by: cik shila 11/4/2012


3. Use graph paper to answer this question. Table 3 shows the values of two variables, x and y obtained from an experiment. Variables x n and y are related by the equation y  w , where n and w are constants. x x y

3 103

4 87

5 76

6 68

7 62

8 57.4

Table 3 (a).

(b).

Plot log10 y against log10 x , using a scale of 2 cm to 0.1 unit on the log10 x -axis and 2 cm to 0.2 units on the log10 y -axis. Hence, draw the line of best fit. [5 marks] Use your graph in (a), to find the value of (i). n, (ii). w, (iii). y when x = 2.

[5 marks]

4. Use graph paper to answer this question. Table 4 shows the values of two variables, x and y obtained from an experiment. Variables x b and y are related by the equation y  a x  , where a and b are constants. x x y

0.2 12.40

0.4 8.50

0.6 6.74

0.8 5.66

1.2 4.90

1.4 3.87

Table 4 (a).

Plot y x against x , using a scale of 2 cm to 0.2 unit on the x -axis and 2 cm to 0.2 units on the y x -axis. Hence, draw the line of best fit. [5 marks]

(b).

Use your graph in (a), to find the value of (i). a, (ii). b, (iii). y when x = 0.9. 6

[5 marks]

prepared by: cik shila 11/4/2012


5. Use graph paper to answer this question. Table 5 shows the values of two variables, x and y obtained from an experiment. Variables x and y are related by the equation y  pm x , where m and p are constants. x y

1.5 2.51

3.0 3.24

4.5 4.37

6.0 5.75

7.5 7.76

9.0 10.00

Table 5 (a).

Plot log10 y against x , using a scale of 2 cm to 1 unit on the x-axis and 2 cm to 0.1 units on the log10 y -axis. Hence, draw the line of best fit. [5 marks]

(b).

Use your graph in (a), to find the value of (i). m, (ii). p, (iii). x when y = 4.8.

[5 marks]

6. Use graph paper to answer this question. Table 6 shows the values of two variables, x and y obtained from an experiment. Variables x and y are related by the equation y  hk x , where h and k are constants. x y

3 10.2

4 16.4

5 26.2

6 42

7 67.1

8 107.4

Table 6 (a).

(b).

Plot log10 y against x , using a scale of 2 cm to 1 unit on the x -axis and 4 cm to 0.5 units on the log10 y -axis. Hence, draw the line of best fit. [5 marks] Use your graph in (a), to find the value of (i). h, (ii). k, (iii). x when y = 35.6. [5 marks]

7

prepared by: cik shila 11/4/2012


ANSWER

No. 1.

PAPER 1 Solution xy   x  10 Calculate gradient from graph n  10 k 2

Marks 1 1 1 1

log10 y  2log10 x  15 Calculate gradient from graph n  2 k  15

1

c = -5 y 1  5 x x y  1  5x

1 1

4.

log10 y = - log10 b + log10 a Gradient = -2 b = 100 a = 1000

1 1 1 1

5.

log10 y = bx + log10 a or log10 y = bxlog10 10 + log10 a a = 100 b=-½

1 1 1

2.

3.

6. log10 x1/2

Gradient = ½ log10 y = ½ log10 x + 2 or log10 102 or log10 x1/2.102 y  100 x

1 1 1

1

1 1 1 1

7(a)

 3 log 10 k  3

1

(b)(i)

log10 y  (3log10 k ) x  log10 p

1

8

prepared by: cik shila 11/4/2012


log 10 p  8 k  10

(ii)

1 1

PAPER 2 No. 1(a)

Solution x y x

(b) (i) (ii) (iii)

3 4.4

4 5

5 5.5

6 6.1

7 6.5

Uniform scale for x-axis and y-axis 6 points plotted correctly Draw the line of best fit Reduce non-linear to linear equation y n  2rx  x r Calculate gradient from graph n = 0.77 r = 0.275 y From graph ,  3.6 x y = 5.4

(b) (i) (ii) (iii)

2.(a)

2 4

x2 xy

1 4 5.1 13.8

9 29.1

16 50

25 77

Uniform scale for x-axis and y-axis 6 points plotted correctly Draw the line of best fit Reduce non-linear to linear equation xy  kx 2  h Calculate gradient from graph h  2 k 3 From graph, xy = 20 y= 8

9

Marks 1

1 1 1 1

1 1 1 1 1 36 109.8

1

1 1 1 1 1 1 1 1 1

prepared by: cik shila 11/4/2012


3.(a)

log10 x

0.48 0.60

0.70

0.78

0.85

0.90

log10 y

2.01 1.94

1.88

1.83

1.79

1.76

(b) (i) (ii) (iii)

4.(a)

(b) (i) (ii) (iii)

x y x

1

Uniform scale for x-axis and y-axis 6 points plotted correctly Draw the line of best fit Reduce non-linear to linear equation log10 y  w log10 x  log10 n Calculate gradient from graph n  102.3  199.526 w  0.6 From graph, log10 y  2.12

1 1 1 1

y  102.12  131.825

1

0.2 0.4 5.55 5.38

0.6 5.22

0.8 5.06

1.2 4.9

Uniform scale for x-axis and y-axis 6 points plotted correctly Draw the line of best fit Reduce non-linear to linear equation y x  ax  b Calculate gradient from graph a  - 0.8 b  5.7 From graph y x  4.9 y = 5.165

10

1 1 1 1

1.4 4.74

1

1 1 1 1 1 1 1 1 1

prepared by: cik shila 11/4/2012


5.(a)

(i) (ii) (iii)

x log10 y

1.5 3.0 0.4 0.51

6 0.76

7.5 0.89

1

9 1

Uniform scale for x-axis and y-axis 6 points plotted correctly Draw the line of best fit Reduce non-linear to linear equation log10 y  x log10 m  log10 p Calculate gradient from graph m  100.084 or m  1.2134 p  100.26 or1.8197 log10 4.8  0.68 x= 5

1 1 1 1

All values of log10 y are correct

1

6.(a) x log10 y

(i) (ii) (iii)

4.5 0.64

3 4 1.0 1.21

5 1.42

6 1.62

7 1.82

Uniform scale for x-axis and y-axis 6 points plotted correctly Draw the line of best fit Reduce non-linear to linear equation log10 y  x log10 k  log10 h Calculate gradient from graph k  100.2 or k  1.588 h  100.425 or h  2.66 log10 35.6  1.55 x = 5.7

11

1 1 1 1 1

8 2.03 1 1 1 1 1 1 1 1 1

prepared by: cik shila 11/4/2012


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