Irodov problems in general physics

Page 304

2.5. (a) p = (v1 + v2 + v3) RT/V = 2.0 atm; (b) M = v3) = 36.7 g/mol. v31113)/(vi ± v2 v2M2 0.42 kK. 2.6. T olli 012— 1)/i (112 — 1) 2.7. n— In (1+InAIT/17) • 2.8. p = 2.9. t = (V/C) In 11 = 1.0 min. 2.10. AT = (mg PoAS) l/R ---- 0.9 K. 2.11. (a) Tmax = 3(PoIR)17 Pd 3a; (b) Tmax=Po/ePR. 2.12. Pmin = 2/117aTo. 2.13. dT/dh = —MgIR = —33 mK/m. 2.14. dT/dh = —Mg (n — 1)/nR. 2.15. 0.5 and 2 atm. 2.16. (a) h = RT IMg = 8.0 km; (b) h 1RTIMg = 0.08 km. 2.17. m = (1 — e -MghIRT) poSIg. OP

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2.18. he = .c hp dh I p dh = RTI Mg. 2.19. (a) p = Po (1 — ah.)n , h <11a; (b) p = p 01 (1 + ah)n. Here n = MglaRT o. 2.20. p p0elt1(02r2/2RT 2.21. pid =pRTIM =80 atm; p = pRTI(M — pb) — ap2/M2= = 80 atm. b) = 133 K; (b) 2.22. (a) T = a (V — b) (1 + 1))/RV (QV p = RTI(V — b) — alV2 =9.9 atm. 2.23. a = V2 (T1p2 — T 2pi)I(T 2 — T1) = 185 atm•12/mo12, b = V — R (T 2 — T1)I(p2 — pi) = 0.042 1/mol. 2.24. x = VZ (V — b)-2/1R7T3 — 2a (V — b)2]. 2.25. T > a/bR. 2.26. U = pVl•y — 1) = 10 ML 2.27. AT = 1/2/Vv2 (' — 1)/R. 2.28. T = T1T2 p2V2T1); P + P2 V2)/(PiViT2 P2V2)/(Vi + V2). (PiVi —AU. 2.29. AU = —poVATIT0 (7 — 1) = —0.25 kJ, Q' 2.30. Q = A?/(? — 1) = 7 J. 2.31. A = RAT = 0.60 kJ, AU = Q — RAT = 1.00 kJ, .17 = Ql(Q — RAT) = 1.6. 2.32. Q = vRT 0 (1 — 1/n) = 2.5 kJ. 2.33. vai (v1-1)___ .33. vl (72 —1) ± V2 (71 -1) 2.34. cy = 0.42 J/(g•K), cp = 0.65 J/(g•K). RT (n — 1. — ln n). 2.35. A 2.36. A' = PoVo In [(n + 1)2/44 2.37. y = 1 + (n — 1)1(Q1vRT, — ln n) = 1.4. 2.38. See Fig. 13 where V is an isochore, p is an isobaric line, T is an isothermal line, and S is an adiabatic line. ivy - niv = 0.56 kK; (b) A' = RT 2.39. (a) T = T 1)/(y — 1) = 5.6 kJ —


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