Uprosti izraz 6x – (3 – 2x) ⋅ (3x – 2). Re{ewe 6x – (3 – 2x) ⋅ (3x – 2) = 6x – (9x – 6 – 6x2 + 4x)
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pomno`ili smo binome (3 – 2x) i (3x – 2)
= 6x – 9x + 6 + 6x2 – 4x
– (9x – 6 – 6x2 + 4x) = –9x + 6 + 6x2 – 4x
= 6x – 9x – 4x + 6 + 6x2
grupisali smo sli~e monome
= –7x + 6 + 6x
= 6 – 7x + 6x2
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Uprosti izraz. a) 4z – (z – 2) ⋅ (z + 6) b) 2a2 – (2a – 1) ⋅ (4 – a)
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Uprosti izraz. a) (x – 3) ⋅ (x + 2) – 6x ⋅ (x + 1) b) (x – 5) ⋅ (x + 7) + (1 – x) ⋅ (4 + x)
Множење полинома 1
Uprosti izraz. a) –2 ⋅ (3a – a2)
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b) 12 – 3 ⋅ (x – 4)
v) 2m ⋅ (3m2 – 4m) + 3m2
Uprosti izraz. a) x ⋅ (5 + x) + 2 ⋅ (x2 – 3x)
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v) (x2 – 8x + 2) ⋅ (–3x)
Uprosti izraz. a) 3c ⋅ (2c + 4) – 4c
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b) 5 ⋅ (2a – 3b + 4c)
b) y2 – y ⋅ (1 – y)
Na osnovu teksta napi{i izrzaz i uprosti ga. a) Od binoma 3x3 – 5x oduzmi proizvod monoma 2x i 3x2. b) Od proizvoda monoma –5x i 4x oduzmi polinom 7x2 + 12x . v) Razliku monoma 2x i –9 pomno`i binomom 7x2 + 4x.
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Uprosti izraz. a) –2 ⋅ (6a2 + 2a – 5) – (1 – 5a) ⋅ (–3a) b) (–2x + 3) ⋅ (–5x) – 4 ⋅ (1 – 3x + 3x2)
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