IOL - Final Matric Revision Edition 1

Page 1

MATHEMATICAL

Final Matric revision 2022
LITERACY Paper 1 and Paper 2 Grade 12 NSC (Nov 2021) Question papers & Memos

TRUE ACADEMIC INSTITUTE OF EXCELLENCE

CAD4ALL Institute of Applied Architecture is an award-winning higher education tertiary institution, since 2008 the entity has been offering accredited national certificates and diplomas in Architecture, Interior design, Draughting, Engineering, Construction and Design. Its campuses are located in the central suburbs of Tygervalley & Claremont, Cape Town housing excellent facilities with leading edge technologies and quality assurance. As we are in the era of change, CAD4ALL is recognised for its highly qualified faculty, advanced curriculum in various formats with a dynamic learning environment geared for the 4th industrial revolution. The CAD4ALL Tygervalley campus was abuzz last week as we kicked off our birthday festivities with our Architecture & Design Build Expo held from 13-15 October 2022 in celebration of our 14th birthday.

CAD4ALL celebrated its rich and colourful education history with industry heavyweights as guest speakers in attendance as well as professionals and associated bodies as special attendees. As we continue to transform into an innovative institute of higher learning, we would like to extend sincere thanks to the educators, staff, and students of CAD4ALL from past and present who have contributed to our success story in this fourteen-year celebration. As part of the 14th-anniversary events, the CAD4ALL exhibition showcased our extensive collaborations as pillars of the industry.

The founders of CAD4ALL embarked on a vision to establish an accredited post-secondary institute which was received with much scepticism and conflicted sentiments 14 years ago. CAD4ALL has worked hard over the 14 years and built a vision with purpose and direction evident in its students placed as national finalists in design competitions since 2019, as the most reliable barometer to judge CAD4ALL’s approach to education.

3 x CAD4ALL students were placed in the National Top 9 2022 Caesarstone national architectural student design competition once again showing the consistency of education and growth at CAD4ALL, we look forward to the finals on the 03 November being hosted in Cape Town at the waterfront 03 November 2022. This year again sees various architectural, draughting and construction firms head hunting CAD4ALL Graduates

With reflective practice and passion, CAD4ALL sought to develop more of their discipline and core literacies by creating and owning 3 more subsidiaries of Cadlab, CADprint and the CAD4ALL EGD Academy.

CAD4ALL A
TO ENROL FOR 2023 AT CAD4ALL IN ARCHITECTURE, INTERIOR DESIGN, CONSTRUCTION AND VARIOUS DRAUGHTING DESIGN DISCIPLINES PLEASE VISIT OUR WEBSITE WWW.CAD4ALL.CO.ZA
DELEGATES FROM INCLUDE: 1. NtHBRC (National Home Builders Registration Council) 2. SAIBD (South African Institute of Building Design) 3. Emrin Holdings – Zen 3D Filament 4. Netram Technologies – 3D Printing 5. Contracts on-Demand – E-CLOUD Construction 6. Ashway Investments – South African Institute of Refrigeration & Airconditioning Member 7. Nikon South Africa 8. Leica Geosystems South Africa and various other industry stakeholders
MILESTONE PROJECTS: • 2008 : Opened our doors selling alternative CAD Software • 2009 : Contracted to train 18 Gautrain Contractors • 2010 : ACSA,DELL,ENGEN,SABC,KENYUKA,PUBLIC WORKS, WCED, PARMALAT, NAMIBIAN TRAINING AUTHORITY, corporates come on board • 2011 : Opens 1st private accredited college in Cape Town • 2012 : Receipt of our 1st Accreditation for 2D CAD with CETA • 2013 : 1st Learnership Project with CETA • 2014 : FULL SETA accreditation with CETA & MICT • 2015 : Namibian Training Authority appoints and contracts CAD4ALL for 3 years to activate CAD in 84 Namibian learning institutions • 2016 : Celebrating over 1000 graduates & 500 corporate software clients • 2017 : CAD4ALL relocates to Tygervalley & opens CADLAB retail • 2018 : Public Works Kimberley appoints CAD4ALL as a training provider • 2019 : Receipt of our 2nd Top 10 Award in South Africa in a Design competition • 2020 : CAD4ALL voted best AEC College in South Africa • 2021 : Our second accredited campus opens in Claremont, Cape Town • 2022 : Assigned to assist the CETA to re-align the new Architectural occupational qualifications • CAD4ALL develops the 1st Integrated Architectural STEM degree in Africa • 2022 : Western Cape Education Department appoints CAD4ALL to train all the school teachers as well as activate and manage all the Schools Labs in the Western Cape • 2023 : Council of Higher Education board approval for new NQF7 Degree • CAD4ALL in conjunction with its partners launches the biggest Schools educational competition in South Africa • CAD4ALL Launching Gauteng 2023 • Our educational collaborations in the schools have been instrumental in shaping the development of EGD and other technical subjects and the transition thereof. CAD4ALL Institute of Applied Architecture 2023 Schools Stem Design Competition brief for Grade 12 entries was inspired by the heartening film of ‘’the boy who harnessed the wind.” A tale of discovery and pushing boundaries with self-sufficiency. Entries for the CAD4ALL 2023 STEM competition will be completed online and communication will be shared in December 2022 on the specifics.
CLAREMONT CAMPUS TYGERVALLEY CAMPUS
3 X NATIONAL CAESARSTONE DESIGN
FINALIST CAD4ALL
PRACTICAL EXCURSIONS
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R Rounding off/Afronding NPR No penalty for rounding/Geen penalisasie vir afronding nie AO Answer only/Slegs antwoord MCA Method with consistent accuracy/Metode met volgehoue akkuraatheid RCA Rounding consistent with accuracy/ Afronding met volgehoue akkuraatheid These marking guidelines consist of 20 pages. Hierdie nasienriglyne bestaan uit 20 bladsye. MATHEMATICAL LITERACY P1/ WISKUNDIGE GELETTERDHEID V1 NOVEMBER 2021 MARKING GUIDELINES/NASIENRIGLYNE GRADE/GRAAD 12 NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT

NOTE:

• If a candidate answers a question TWICE, only mark the FIRST attempt.

• If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version.

• Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error.

• If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented.

LET WEL:

• As 'n kandidaat 'n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na

• As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na

• Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout.

• Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item.

QUESTION/VRAAG 1 [30 MARKS/PUNTE] ANSWER ONLY FULL MARKS

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 2 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
Q/V Solution/Oplossing Explanation/Verduideliking T&L 1.1.1 $1,258 $0,80 =$0,458 1MA subtracting different prices 1CA simplification provided 1 value is correct (2) F L1 * 1.1.2 11,14 Botswana pula/Botswana pula = $1 11,14 1 1 BotswanaPula = 0,089767 US dollar 1MA dividing by exchange rate 1A simplification No penalty for correct rounding (2) F L1 * 1.1.3 Angola; Namibia or/of Botswana 1RT first correct country 1RT second correct country Any two (2) F L1 * 1.1.4 1,258; 1,061; 0,87; 0,796; 0,732; 0,254 1RT all correct values 1A correct order (2) D L1 * 1.1.5 0,833 2A correct value (2) P L1 * RT RT RT A MA CA MA A A

Q/

1.2.1

1.2.2 Limpopo / LP / Lim /

1.2.3 (a)

Cost of 1 ℓ of paraffin/Koste van 1 ℓ paraffien 764,59 100 = R7,6459/ℓ = R7,65/ℓ

1.2.3 (b) Cost of paraffin/Koste van paraffien

R7,65/ℓ × 12,5ℓ = R95,625 = R96,00

1.2.4 Solar power OR Coal OR Charcoal OR Wind turbines OR Hydropower OR Generator OR Gel OR Paper OR Straw OR Leaves OR Animal manure (dung) OR Spirits OR Corn stalk

Explanation/Verduideliking

2A correct source (2)

province (2)

L1

L1

L1

1MA dividing by 100

simplification NPR (2)

CA from Question 1.2.3 (a)

1MCA multiply by 12,5ℓ

1R correct rounding (2)

L1

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 3 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
V Solution/Oplossing
T&L
Electricity/Elektrisiteit
D
L Province/Provinsie 2A
D
1A
F
*
F
Sonkrag OF Steenkool OF Houtskool OF Windturbines OF Hidrokrag OF Kragopwekker OF Gel OF Papier OF Strooi OF Blare OF Dieremis (mis) OF Spiritus OF Mieliestronk 2A correct source Any one (2) D L1 * 1.3.1 Survey/Questionnaire/Interview/Google forms Opname/Vraelys/Onderhoud/Google vorms 2A correct instrument (2) D L1 1.3.2 Classifying, preparation, organising, sorting data/ Klassifisering,voorbereiding, organisering, sortering van data 2A correct step Any one word to describe the step (2) D L1 1.3.3 Categorical data/Kategoriese data 2A correct answer (2) D L1 A A MCA R MA A A A A A
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 4 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 1.3.4 Value Added Tax/Belasting op Toegevoegde Waarde 2A correct answer (2) F L1 1.3.5 Any company who sells books/Enige maatskappy wat boeke verkoop OR/OF Publishers/Drukkers OR/OF Library/Biblioteek OR/OF Book Club/Boekklub OR/OF Name of a book store/Naam van 'n boekwinkel OR/OF Name of publisher/Naam van uitgewer 2A correct answer (2) D L1 * [30] A A A A A A A

L1

2A correct definition

list (2)

F L1

1MA

1A

1RT

Accept unit ratio

(2)

F L2

F L1

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 5 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 2 [32 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 2.1.1 Hire purchase agreement/HP/Instalment payment/Loan agreement monthly instalment/Credit option/Credit/Balloon payment option/Residual payment option Huurkoop/HK/Paaiement betaling/Lening ooreenkoms met maandelikse paaiement/Krediet opsie/Krediet/Ballon betaal opsie/Reswaarde betalings opsie
Any one from given
F
2.1.2 Ford Figo Deposit/Deposito = R215 100 × 5% = R10 755
multiplying correct values
simplification AO (2)
* 2.1.3 72 months : 48 months = 3:2
correct values 1A simplification of 2 correct values
AO
* 2.1.4 Ford Figo 2A correct vehicle (2)
2.1.5 Monthly admin fee/Maandelikse administrasie fooi R3 345 × 2,08% = R69,58 Total cost for the VW Polo/Totale koste vir die VW Polo = Total monthly instalments + Admin fee + Residual = (R3 345,00 × 47) + (R69,58 ×47) + R116 759 = R157 215 + R3 270,26 + R116 759 = R277 244,26 1MA calculating 2,08% 1MA multiplying correct values 1MA multiplying correct values 1RT correct value 1M adding values 1CA simplification (6) F L3 * MA A A A MA MA RT M CA RT A MA

R2 580,00

Amount end of year

R60 000

R62 580,00

Interest for year 2/

580,00

R3 191,58

Amount end of year 2/

R62 580,00

R65 771,58

Residual value of

100 ×

R64 530

is correct/

000,00

R65 771,58

Residual value of

100

R64 530

1MA calculating percentage

simplification

adding interest

calculating percentage

einde van jaar 2

simplification

calculating 30%

simplification

conclusion.

adding percentage

adding percentage

calculating percentage

compound calculation

simplification

calculating 30%

simplification

conclusion.

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 6 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 2.1.6 Interest for year 1/Rente vir jaar 1 R60 000,00 100 4,3  =
1/Bedrag aan die einde van jaar 1 =
+ R2 580 =
Rente vir jaar 2 62
100 5,1  =
Bedrag aan die
=
+ R3 191,58 =
Ford Figo R215
30% =
She
Sy is korrek OR/OF R60
100 104,3  100 105,1  =
Ford Figo R215
× 30% =
She is CORRECT/Sy is KORREK
1A
1CA
1MCA
1CA
1M
1CA
1O
OR/OF 1MA
1MA
1M
1M
1CA
1M
1CA
1O
(8) F L4 * O CA M O MA A CA CA MA MA M CA CA M M MCA

1M

Verduideliking

095,95

095,95

095,95

correct

1A multiplying by 15%

individual correct calculations: R53,3475

R50,60

CA from Question 2.2.3

correct values

simplification

OF

multiplying by 1,15

simplification

OF

adding correct values

simplification

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 7 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/
T&L 2.2.1 3/Three/Drie 2A correct number (2) F L1 2.2.2 ABC made For You S OR/OF made For You S 2A correct device (2) F L1 2.2.3 VAT calculation/BTW berekening = (R355,65 + R260 + R337,35) × 15% = R953,00 × 15% = R142,95
adding
values
Accept
R39,00
(2) F L1 2.2.4 A = R355,65 + R260 + R337,35 + R142,95 = R1
OR/OF A = R953 × 1,15 = R1
OR/OF A = R953 + R142,95 = R1
1MA adding
1CA
OR/
1MA
1CA
OR/
1MA
1CA
AO (2) F L2 2.2.5 Impossible /Not possible/No chance/Zero percent/Zero/Zero out of three Onmoontlik/Nie moontlik nie/Geen kans/Nul persent/Nul/Nul uit drie 2A correct term (2) P L2 [32] CA MA MA A A A M MA A CA CA
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 8 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 3 [26 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 3.1.1 29 March 2021/29 Maart 2021 OR/OF 29/03/2021 1A correct day 1A correct month and year (2) D L1 3.1.2 One hundred and twenty eight million cubic metres/ Een honderd agt en twintig miljoen kubieke meter 2A number in words NPU (2) D L1 * 3.1.3 KwaZulu Natal OR/OF KZN 2A correct province (2) D L1 3.1.4 Free State/Vrystaat/FS 2A Free State (2) D L2 3.1.5 Mean/Gemiddeld 83 9 DD7382888999101105   83 9 2D637   2D + 637 = 747 2D = 110 D = 55 OR/OF 2D + 637 = 83 × 9 2D + 637 = 747 2D = 110 D = 55 1SF substitution mean correctly 1MA dividing by 9 1CA simplification 1MA dividing by 2 1CA simplification OR/OF 1SF substitution mean correctly 1MA multiplying by 9 1CA simplification 1MA dividing by 2 1CA simplification (5) D L3 3.1.6 Probability/Waarskynlikheid 9 1  1A numerator 1A denominator (2) P L2 * A A A A A SF MA MA CA CA A SF MA CA MA CA A
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 9 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 3.1.7 100 99 15657000000  = 15 500 430 000 1A correct value in millions 1MA multiplying by % 1CA simplification Accept 15 500,43 million (3) D L2 * 3.2.1 100% 1,7 4,31,7 Percentageincrease/  Persentasietoename = 152,94% 1SF correct substitution 1A correct denominator 1CA simplification NPR (3) D L2 3.2.2 Save energy (kWh)/Bespaar energie (kWh) OR/OF Save water (kℓ)/Bespaar water (kℓ) OR/OF Save money/Spaar geld 2A reason (2) D L4 3.2.3 Range of the number of litres/Omvang van die getal liter 120 ℓ 30 ℓ = 90 ℓ OR/OF Difference in time/Verskil in tyd 8 min 2 min Range/Omvang = 6 min 6 min × 15 litres/min = 90 litres Accept litres from 28 32 1RT minimum 1RT maximum 1CA simplification OR/OF 1RT difference in time 1M multiply by 15 min 1CA simplification NPU (3) D L3 [26] RT M CA SF A CA A A CA RTRT A MA CA A
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 10 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 4 [35 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.1.1 Cost of 520 g/Koste van 520 g Rs200 1000 520 520g  = Rs104 OR/OF Unit cost per gram/Eenheidsprys per gram Rs 200 ÷ 1 000 g = Rs 0,20/g Rs 0,20/g × 520 g = Rs 104 1C conversion 1MA multiplying by correct value 1CA simplification OR/OF 1C conversion 1MA multiplying by correct value 1CA simplification (3) F L2 * 4.1.2 Total cost of one plate/Totale koste van een bord (Rs200 + Rs120 + Rs10 + Rs62) ÷ 8 8 Rs392  = Rs49 Total cost including food container/ Totale koste voedselhouer ingesluit = Rs49 + Rs2,43 = Rs51,43 OR/OF 1A total ingredients 1MA divide by 8 1CA simplification 1MA adding the container 1CA simplification OR/OF F L3 CA MA C MA CA CA MA A MA C CA

total

divide

simplification

divide

simplification

total ingredients

adding 1CA simplification

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 11 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.1.2 Total cost of 8 plates/Totale koste van 8 borde = Rs200 + Rs120 + Rs10 + Rs62 + (Rs2,43 ×8) = 392 +(2,43 ×8) = Rs411,44 Total cost of one plate/Totale koste van een bord 8 411,44  = Rs51,43 OR/OF Total cost of one plate/Totale koste van een bord 8 Rs62 8 Rs10 8 Rs120 8 Rs200  = Rs25 + Rs15 + Rs1,25 + Rs7,75 = Rs49 Total cost including food container/Totale koste insluitend koshouer = Rs49 + Rs2,43 = Rs51,43 1A
ingredients 1MA adding the container 1CA simplification 1MA
by 8 1CA
OR/OF 1MA
by 8 1CA
1A
1MA
(5) CA MA CA MA A MA A CA MA CA

from Question 4.1.2

conclusion

OF

calculating 1,5

multiplying

simplification

claim

Bobby

conclusion

OR

percentage calculation

subtracting

conclusion

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 12 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.1.3 Profit of one plate/Wins van een bord Rs80 Rs51,43 = Rs28,57 % profit of one plate/% wins van een bord 100% Rs51,43 Rs28,57  = 55,55% Bobby's claim is VALID/Bobby se eis is GELDIG OR/OF Rs51,43 × 1,5 =Rs77,15 Rs80,00 > Rs77,15 Bobby's
is VALID/
se eis is GELDIG OR/OF Percentage income/Persentasie inkomste 100% Rs51,43 Rs80  = 155,55% Percentage profit/Persentasie wins 155,55% 100% = 55,55% Bobby's claim is VALID/Bobby se eis is GELDIG CA
1MA subtracting CP from SP 1CA simplification 1M percentage calculation 1CA simplification 1O
OR/
2A
1MA
1CA
1O
OF/
1MA
1CA simplification 1M
values 1CA simplification 1O
F L4 O A CA MA CA M MA CA O O CA CA MA M
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 13 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.1.3 OF/OR 50% of cost price/50% van die kosprys = Rs 51,43 x 50% = Rs 25,72 Profit per plate/Wins per bord = Rs 80 Rs 51,43 = Rs 28,57 Rs 28,57 >Rs 25,72 Bobby's claim is VALID/Bobby se eis is GELDIG OF/OR 1MA percentage calculation 1CA simplification 1M subtracting values 1CA simplification 1O conclusion (5) 4.1.4 Cost of masala/Koste van masala 0,206839 Rs1 Rs10  = R2,06839 = R2,07 OR/OF Cost of masala/Koste van masala 4,834670 Rs10  = R2,06839 = R2,07 1RT correct values 1MA multiplying by 0,260839 1A simplification OR/OF 1RT correct values 1MA dividing 1A simplification (3) F L2 4.2.1 Cost (R) = 600,00 + 13 p, where p = number of plates. 1 380,00 = 600,00 + 13p 1 380,00 600,00 = 13p R780 = 13 p p = 60 plates 1SF correct substitution 1MA subtracting 600 1CA simplification 1CA simplification AO (4) F L2 * A MA RT SF MA CA CA MA CA M CA O RT MA A
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 14 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.2.2 1A Start point (0;600) 1A End point (100; 1 900) 1A Correct straight line Number of Plates 0 10 30 50 70 90 100 Cost (R) 600 730 990 1250 1 510 1 770 1 900 (3) F L2 0 500 1000 1500 2000 2500 0 10 20 30 40 50 60 70 80 90 100 Janet's Business graphs for plates of Biryani Amount in Rand Number of plates of Biryani Cost Income A A A
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 15 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.2.3 50 plates 2RT number of plates (2) F L2 * 4.3.1 100 18,7  = 0,187 1RT reading 18,7 1CA simplification AO (2) P L2 * 4.3.2 As the time increase the number of tourists visiting India increases./ Soos die tyd verbygaan, neem die aantal toeriste wat Indië besoek toe. 2A increases Accept increase (2) D L4 4.3.3 Number of tourist from Bangladesh/Aantal toeriste uit Bangladesj 10,93 million 100 37,1  = 4,05503 million/miljoen = 4 055 030 His statement is NOT CORRECT/Sy bewering is NIE KORREK NIE OR/OF Number of tourist from Bangladesh/Aantal toeriste uit Bangladesj 100% 10,93million/miljoen 4,5million/miljoen  = 41,1% Then 37,1% is less than the 41,1% His statement is NOT CORRECT/Sy bewering is NIE KORREK NIE. 1RT correct percentage 1M multiply with percentage provided one value is correct 1CA simplification 1O conclusion 1RT correct values 1M multiply with percentage provided one value is correct 1CA simplification 1O conclusion (4) D L4 * M RT CA O RT A RT CA RT M CA O
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 16 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.3.4 Due to the rounding of large numbers in converting to a percentage/ As gevolg van die afronding van grooter getalle tydens die omskakeling na 'n persentasie. 2A stating rounding (2) D L4 [35] A

301 R555

263

36%

from Question 5.1.1

301 R555

263

36%

R100 263 + 36% (R551 762

263 + (36% × R128 462)

R100 263 + R46 246,32

R146 509,32

R146 509,32

R132 289,32

300)

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 17 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 5 [27 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 5.1.1 Tax Bracket 4/Belastinghakkie 4 OR/OF Tax Bracket/Belastinghakkie R423
600 OR/OF 100
+
of taxable income above 423 300 2A correct tax bracket (2) F L2 5.1.2 Annual tax/Jaarlikse belasting R423
600 100
+
of taxable income above 423 300
R423
R100
=
Tax payable/Belasting betaalbaar =
R14 220 =
CA
1SF substitution 1CA simplification 1CA tax before rebate 1MCA subtracting rebate 1CA simplification (5) F L3 A CA SF MCA CA CA A A

289,32

R11 024,11

Annual tax

289,32 R7 794

R124 495,32

tax

495,32

R10 374,61

024,11 R10 374,61

R649,50

Verduideliking

from Question 5.1.2

dividing by 12

correct rebate

794

simplification

His statement is CORRECT/

KORREK OR/OF R132 289,32 R124 495,32 = R7 794

794 ÷ 12 = R649,50

statement

KORREK

conclusion

OF

correct values

correct rebate

dividing by 12

794

conclusion

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 18 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/
T&L 5.1.3 Present monthly tax payable =R132
÷ 12 =
payable one year older R132
=
Monthly
payable one year older R124
÷ 12 =
Monthly tax savings R11
=
Sy bewering is
R7
His
is CORRECT/Sy bewering is
CA
1MA
and simplify 1A
R7
1MA subtracting rebate and simplification 1CA
1CA simplification 1O
OR/
1RT
2A
R7
1MA
1CA simplification 1O
F L4 *MA CA MA CA O A A RT MA CA O
Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 19 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 5.1.3 OR/OF Annual tax payable one year older/Jaarlikse belasting betaalbaar een jaar ouer = R146 509,32 R14 220 R7 794 = R124 495,32 Annual tax payable/Jaarlikse belasting betaalbaar = R132 289,32 Monthly tax savings/Maandelikse belasting besparing 12 R132289,32R124495,32  = R649,50 His statement is CORRECT/Sy bewering is KORREK OR/OF 1MA subtracting rebate and simplification 1A correct tax payable 1M simplification 1MA dividing by 12 1CA simplification 1O conclusion (6) 5.1.4 Medical credits/Mediese krediete: R310 + R310 + (R209 × 2) R310 + R310 + R418 = R1 038 1RT correct values 1MA multiplying with 2 1MA adding all the values 1CA simplification AO (4) F L3 5.2.1 (a) Huawei 2RT correct brand (2) D L2 * 5.2.1 (b) 21,5% CA from Question 5.2.1 (a) 2RT correct percentage (2) D L2 * 5.2.2 IQR = Q3 Q1/IKV = K3 K1 = 18,75 15,7 = 3,05 1MA concept of IQR 1RT correct value (Q3) 1RT correct value (Q1) 1CA simplification (4) D L3 *RT MA RT CA MA MA RT RT CA RT A O CA MA MA M

Oplossing

Quartile 3 is at 15,95 which includes 75% of the dataset.

3 is by 15,95 wat 75% van die datastel insluit.

statement is VALID/Die bewering is GELDIG

OR/OF

15,95% < 16% which is Quartile 3 which includes 75% of the dataset.

< 16% wat Kwartiel 3 is wat 75% van die datastel insluit

statement is VALID/Die bewering is GELDIG

OR/OF

Verduideliking

75

is below the 16% on the Box and whisker plot.

75ste persentiel is onder die 16% op die Mond en snor diagram.

statement is VALID/Die bewering is GELDIG

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 20 DBE/November 2021 NSCNSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Q/V Solution/
Explanation/
T&L 5.2.3
Kwartiel
The
15,95%
The
The
th percentile
Die
The
1O explanation 1O conclusion (2) D L4 * [27] TOTAL/TOTAAL: 150 O O O O O O
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief MARKS/PUNTE: 150 SYMBOL/KODE EXPLANATION/VERDUIDELIKING M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/map/diagram/Lees vanaftabel/kaart/grafiek/diagram SF Correct substitution in a formula/Korrekte vervanging in formule O Opinion/Explanation/Reasoning /Opinie/Verduideliking/Redenasie P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisering, bv. vir geen eenhede/verkeerde afronding, ens. R Rounding off/Afronding NPR No penalty for correct rounding minimum two decimal places/Geenpenaliseringvir korrekte afronding tot twee desimale plekke nie AO Answer only/Slegs antwoord MCA Method with constant accuracy/Metode met volgehoue akkuraatheid These marking guidelines consist of 19 pages. Hierdienasienriglynebestaanuit19 bladsye. MATHEMATICAL LITERACY P2/ WISKUNDIGE GELETTERDHEID V2 NOVEMBER 2021 MARKING GUIDELINES/NASIENRIGLYNE NATIONAL SENIOR CERTIFICATE/NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12

NOTE:

• If a candidate answers a question TWICE, only mark the FIRST attempt.

• If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version.

• Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error.

• Note: consistent accuracy (CA) does not apply in cases of a breakdown.

• If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented.

As a general marking principle, if a candidate has incurred one mistake and there is evidence of sound mathematics thereafter, then that candidate should lose one mark only

LET WEL:

• As 'n kandidaat 'n vraag TWEE KEER beantwoord, merk slegs die EERSTE poging.

• As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, merk die doodgetrekte (gekanselleerde) poging.

• Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout.

• Let wel: volgehoue akkuraatheid (CA) geld nie in die geval van ‘n afbreuk nie.

• Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item.

• 'n Algemene merkbeginsel is dat indien ‘n kandidaat een fout maak en daarna voortgaan met korrekte wiskunde, dat die kandidaat slegs een punt verloor.

Please

over/Blaai

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 2 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopieregvoorbehou
turn
om asseblief
QUESTION/VRAAG 1 [29 MARKS/PUNTE]Answer Only AO full marks Q/V Solution/Oplossing Explanation/Verduideliking T/L 1.1.1 Total mass/Totale massa = 6 × 110g = 660 g 1MA multiply mass by 6 1A mass (2) M L1 1.1.2* Radius = 32 mm 2A radius (2) M L1 1.1.3 A 2A correct letter [accept: mm 3] (2) M L1 1.1.4* Total No. of days/Totale getal dae = 11 Jan to 31 Mar = (31 10) + 28 + 31 = 21 + 28 + 31 = 80 1MA days in Jan 1MCA adding days in 3 months 1CA simplification (3) M L1 MA A A A CA  MA  MCA

Q/V Solution/Oplossing

1.1.5* Price for 2 Pringles/Prys vir 2 Pringles = 2 ( 6 R100 ) = 2 × R16,666 = R33,33

1.2.1 A

1.2.2 D

1.3.1 7,3 m = 7,3 × 100 cm = 730 cm

1.3.2* D = 7,3 m 5,2 m = 2,1 m

1.3.3 0,5m

1.4.1* A layout plan is a top view that shows the arrangement of features.

'n Uitlegplan is die bo aansig wat die rangskikking van die voorwerpe aantoon.

OR/OF

layout plan is the structural arrangement of items within a certain space.

'n Uitlegplan is die strukturele rangskikking van items binne 'n bepaalde ruimte.

OR/OF Plan of the entire inside cabin, showing location of seats, exit doors etc.

'n Plan van die hele binnekant van die kajuut wat die posisie van sitplekke, uitgang, deure ens. aantoon

OR/OF Drawing to scale showing physical arrangements of all resources that consume space within facilities.

Skaaltekening wat die fisiese posisies van al die items van spasie in beslag neem binne die fasiliteit

Explanation/Verduideliking T/L

M/F L1

1MA dividing price by 6 and multiplying by 2

1CA simplification

NPR (2)

2A correct letter (2)

2A correct letter Accept 60 km/h (2)

1MA multiplying correct value by 100

1A simplification (2)

1MA difference of correct lengths

1CA simplification (2)

2A height (2)

M L1

M L1

M L1

M L1

M L1

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 3 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
A
'n
2Aexplanation (2) MP L1  CA A  A  MA A  A  MA A  CA  MA A
Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 4 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T/L 1.4.2* 28 2A number of seats (2) MP L1 1.4.3 G1 1A correct seat 1A correct row (2) MP L1 1.4.4* 6 2A correct number (2) P L1 [29] A  A  A

numerator

denominator

probability of

numerator

denominator

simplification

wrong,

Africa

is on the

does not get a lot of

side.In

verkeerd. Die kombuis is aan die suidlike kant. In Suid Afrika kry dit nie baie son nie.

cannot be the view

does not show the

the

kannie die kombuis

eetkamer

nie want

wys nie die venster van die badkamer nie.

wrong

not show the other rooms

both sides of the

wys nie die ander kamers weerskante van die vensters nie.

the veranda, door, bedroom and livingroom windows.

wys die stoep, deur en slaapkamer

woonkamervensters.

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 5 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 2 [24MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L 2.1 3 2A correct number (2) MP L2 2.2 Living room/Woonkamer 2A correct room (2) MP L1 2.3 North East or NE/Noordoos of NO 2A direction (2) MP L2 2.4* Pnot interior/nie binne = Pexterior/buite = 6 2 = 3 1 OR/OF Pnot interior/nie binne = 1 6 4 = 6 2 = 3 1 2RT
1A
1CA simplification OR/OF 1MA
NOT 1RT
1A
1CA
(4) P L2 2.5 Jan is
the kitchen
Southern
South
it
sun. Jan is
1A
2O reasoning (3) MP L4 2.6 It
showing the kitchen and dining room, as it
extra window for
bathroom. Dit
en
wees
dit
It does
on
windows. Dit
OR/OF It shows
Dit
en
OR/OF 2O reason MP L4 A RT A A O CA A A CA A O RT MA

Q/V Solution/Oplossing

OR/

Because there is no veranda on the side of the kitchen and the picture shows the veranda. Daar is nie 'n stoep aan die kombuis se kant nie en die prent toon 'n stoep

OR/OF

The drawing shows the SE elevation and the kitchen is on the SW side.

Die prent toon die SO aansigen die kombuis is aan die SW kant.

OR/OF

The windows shown does not look like kitchen windows, they are too big.

Die vensters wat aangetoon word lyk nie soos kombuisvensters nie, hulle is te groot

OR/OF

The drawing represents the front view

Die prent is die vooraansig

OR/OF

Kitchen should be on the left hand side with the window and door / The door knob is on the right hand side and not on the left hand side of the door adjacent to the kitchen window.

Kombuis moet aan die linkerkant met die vensterendeur wees / Die deurknop is aan die regterkant en nie aan die linkerkant van die deur wat grens aan die kombuisvenster nie.

Explanation/Verduideliking T/L

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 6 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
OF
(2) 2.7.1* 10 mm : 1 000 mm = 1 : 100 OR/OF 1 cm : 100 cm = 1 : 100 1A correct ratio and conversion 1CA simplification OR/OF 1A correct ratio and conversion 1CA simplification AO (2) MP L2 2.7.2 Length on floor plan/Lengte op die vloerplan = 4,4 cm 1 cm = 100 cm 4,4 cm = 4,4 × 100 cm = 440 cm = 4,4 m OR/OF CA from 2.7.1 1A correct measurement 1MCA using the scale 1CA simplification 1C conversion Accept 4,3 m to 4,5 m MP L3 MCA CA C CA A A CA A

cm

400

cm

000

plan

the same.

Explanation/Verduideliking T/L

1A correct measurement

1MCA using the scale

simplification

1C conversion OR/OF

using the scale

1C conversion

1A correct measurement

simplification

1A opinion

2O verification

is korrek.

jy ‘n fotostaat maak, kan die grootte van die plan verander

die getalskaal bly dieselfde

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 7 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing
1 cm is 1 000 mm 4,4
is 4
mm 4 400 mm = 4,4 m OR/OF 1cm : 1
mm 1cm : 1 m 4,4
: 4,4 m
1CA
1MCA
1CA
(4) 2.7.3 Jan is correct. When a photocopy is made the size of the
may change while the number scale remains
Jan
Wanneer
en
(3) MP L4 [24] MCA CA C A O MCA C CA A A

3.1.1

= 162 cm

cm

165 cm

3.1.2*

1,5 cm

(1,5

= 80 cm (40 cm

32,5

1,5

3.2 31,496

inch/duim

2,54

4,5

1,5

1RT inside length 1MA adding both sides

1CA simplification (3)

M L1

80

3.3.1

of a

length

165

13 200

1,5 cm)

1RT both heights 1MA subtracting 1CA simplification (3)

1RTheight 80 cm 1MA dividing by 31,496

1A simplification (3)

CA from 3.1.1 1MCA substitution 1CA simplification (2)

from 3.3.1

1CA

from 3.3.2

M L1

M L2

M L2

M

M L3

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 8 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 3 [35 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L
A
+
+
cm = 162
+
cm × 2) =
B
+
cm +
cm +
=
cm
inches/duim = 80 cm 1
=
31496 , cm =
cm
Area
rectangle =
× width Opp van ‘n reghoek = lengte × breedte =
cm × 80 cm =
cm2
3.3.2* Area of a rectangle = 13 200 cm2 = 2 13200 (100) m 2 = 1,32 m2 CA
1MCA dividing by 1002 or 10 000
simplification AO (2)
L2 3.3.3 1ℓ covers/bedek 6,9 m2 n ℓ covers/bedek 1,32 m2 n = 132 69 , , = 0,1913… ℓ To paint three coats/ Om drie lae te verf 0,1913... ℓ × 3 = 0,57 ℓ CA
1MA dividing by 6,9 1CA simplification 1MA multiplying with 3 1CA simplification 1R rounding
MCA RT CA RT RT MA MA A MA MCA CA CA CA MA MA CA R CA or Area = 1,65×0,8 =1,32 m 2

Total area to cover / Totale oppervlakte om te dek

1,32 m × 3 = 3,96 m

covers/bedek 6,9 m

ℓ covers /bedek 3,96 m

= 6,9 3,96 = 0,57 ℓ

OR/OF Paint needed/Verfbenodig

1,3221,32

= 0,38 ℓ + 0,19 ℓ = 0,57 ℓ

OR/OF Total area to cover / Totale oppervlakte om te dek = 1,32 m 2 × 3 = 3,96 m Spread rate/ Spreikoers = 26,9

m

= 0,144… ℓ/m2

Total amount of litres / Totale aantal liters = 0,144 × 3,96 = 0,57 ℓ

OR/OF Spread rate/ Spreikoers = 26,9

m

= 0,144… ℓ/m

Explanation/Verduideliking

Copyright

1MA multiplying with 3 1CA simplification

dividing by 6,9 1CA simplification

rounding

OR/OF

1MA dividing by 6,9

adding the 2 coats and 1 1CA simplification

simplification

rounding

OR/OF

1MA multiplying with 3 1CA simplification 1MA dividing by 6,9 1CA simplification

rounding

OR/OF 1MA dividing by 6,9

1MA multiplying with 3 1CA simplification

rounding

(from

turn over/Blaai

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 9 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne
reserved/Kopiereg voorbehou Please
om asseblief Q/V Solution/Oplossing
T/L OR/OF
=
2 1ℓ
2 x
2 x
=
6,96,9  
1
1
2 Paint needed for 1 coat/ Verf nodig vir 1 laag == 0,144 × 1,32 = 0,19… ℓ Paint needed for 3 coats/ Verf nodig vir 3 lae = 0,19.. × 3 = 0,57 ℓ
1MA
1R
1MA
1CA
1R
1R
1CA simplification
1R
(5) 3.3.4 0,57 ℓ × 1 000 = 570 mℓ Not valid Nie geldig nie 1MCA
Q3.3.3 multiply by 1 000) 1CA simplification 1O verification M L4MCA CA O MA MA MA CA R CA MA R CACA MA R MA CA R MA CA MA CA CA
Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 10 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T/L OR/OF 500 mℓ ÷ 1 000 MCA = 0,5 ℓ less than 0,57ℓCA Tsidi’s statement is invalid OR/OF 1ℓ covers/bedek 6,9 m2 500 mℓ covers/bedek 6,9 2 = 3,45 m2 Area to paint / Opp om te verf = 1,32 m2 × 3 = 3,96 m 2 The paint is not enough / invalid Die verfis nie genoeg / nie geldig OR/OF Coverage per coat/Dekking per laag = 3 0,5 3 500   m = 0,166.. Coverage /Dekking= 0,166 × 6,9 = 1,15 m2 1,32 m2 needs to be covered per coat/moet per laag gedek word. Not valid / Nie geldig nie OR/OF 1MCA (from Q3.3.3dividingby 1 000) 1CA simplification 1O verification OR/OF 1MCAarea 1CA simplification 1O verification OR/OF 1MCAdividing 1CA simplification 1O verification (3) 3.4.1* Number of boxes/ Getal bokse = 162cm 345cm , = 4,695…  4 boxes OR/OF Number of boxes/ Getal bokse = mm mm 345 1620 = 4,695…  4 boxes 1MA dividing 1C conversion 1CA simplification 1R rounding down OR/OF 1C conversion 1MA dividing 1CA simplification 1R rounding down (4) M L2 # C MA CA R C MA CA R MCA MCA O O CA CA O

stof

makliker

haar lêers

lêers

OR/OF

verdeel

Dit

Dit

om haar lêers

Verduideliking

CA number of boxes from 3.4.1

of files in a

denominator from 3.4.2

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 11 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/
T/L 3.4.2 Number of single files/ Getal enkel lêers = 162cm 81cm , = 20 Number of files in boxes /Getal lêers in ‘n boks = 4 × 4 = 16 Difference in the number of files/Verskil in getal lêers = 20 16 = 4
1MA dividing 1A simplification 1RT number
box 1CA simplification 1CA difference in files (5) M L3 3.4.3 Neater storage/ Netjieser berging OR/OF Files stand up straight/Die lêers staan regop OR/OF Prevents dust on documents in the files/ Verhoed dat
op die dokumente in die
kom.
It is easier to separate the files accordingly.
is
om
te
OR/OF To categorise /organise her files/
is
te katagoriseer /organiseer OR/OF Prevent files from breaking/ damage/protect files Verhoed dat lêers breek of beskadig/beskerm lêers 2O reason (2) M L4 3.4.4 P = 1 100% 16  = 6,25% CA
1A numerator 1MCA denominator 1CA simplification (3) P L2 [35] MA A  CA RT O CA MCA A
Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 12 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 4 [33 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.1.1 Perennial garden bed./Meerjarige tuinbeddings OR/OF Compost / Kompos 2A correct feature (2) MP L2 4.1.2 Water is scarce/Water is skaars OR/OF Rain water is free compared to tap water Reënwater is gratis invergelyking met kraanwater OR/OF Pay less water bills/Betaal minder vir water OR/OF Water storage/ om water te stoor OR/OF To save water for future use Om water te spaar vir toekomstige gebruik OR/OF To harvest rain water Om reënwater op te gaar 2A Reason (2) MP L4 4.1.3 Greenhouseroof/ gutters / Kweekhuis dak/geute OR/OF Livestock Barnroof/ gutters / Veestoor dak/geute OR/OF Solar greenhouseroof / gutters/ Sonkrag kweekhuis 1A correct structure 1A 2nd correct structure Accept roof and gutter /pipe full marks (Any 2 structures) (2) MP L4 4.1.4 Area/Oppervlakte = 17,024m19,5m 2 1  = 165,984 m2 1RT correct height 1RTcorrect base 1CAarea of a triangle NPR (3) M L2 4.1.5 Option/Opsie A = R1 154 × 2 = R2 308 Option/Opsie B = R127,30 × 19 = R2 418,70 Option A. Opsie A. 1MA multiply by 2 1CA option A cost 1MA multiply by 19 1CA option B cost 1O best option (5) MF L4 O O RT RT CA CA MA  CA  O MA O A
Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 13 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.2 Volume = 3,142 × × height/hoogte 5000 ℓ = 3,142 × × 220 cm 5000 000 = 691,24 × 691,24 5000000 = 7233,377698 = 7233,377698 = r 85,05 cm = r 1SF substituting 5000 1C converting ℓ to cm3 1M dividing by 691,24 1S simplification 1M finding square root 1CA radius value NPR (6) M L3 4.3.1* 18 : 42 = 3 : 7 1A correct order and values 1CA only if one value is correct or reversed order (2) MP L1 4.3.2 Height/hoogte = 12" 42" = 3,5 feet/voet 3,28084 feet/voet = 1 000 mm 3,5 feet/voet = 1000 3,28084 3,5  = 1 066,799…mm OR/OF 3, 28084feet = 1 000mm 1 foot = n n = 304,79999mm 1 foot = 12 inches Then 12 inches = 304,79999mm 1 inch = 12 304,79999mm = 25,39999 mm Therefore 42 inches = 42 × 25,39999mm = 1066, 7999mm = 1 066,8 mm 1MA converting to feet 1C converting to mm 1CA simplification OR/OF 1MA converting to feet 1C converting to mm 1CA simplification NPR (3) M L2 C SF M M S CA CA A MA C CA CA MA C

mentioning

the

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 14 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.3.3 (a) iii (b) i (c) ii 3A correct Roman numeral (3) MP L1 4.3.4 Q 2A correct letter (2) MP L1 4.3.5* The notch labelled S is placed against B and the notch labelled R is placed against C Die sitplek word bo op die kantspanstukke geplaas Die uitkeping S word op B geplaas en die uitkeping R word teen C geplaas. 2A
the position of
1st notche 1A second notch (3) MP L4 [33] A A A A A A
Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 15 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief QUESTION/VRAAG 5 [29MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 5.1.1 (a) W 2A correct letter Accept      60 50 (2) M L1 5.1.1 (b) Z 2A correct letter Accept Plymouth (2) MP L2 5.1.2* (a) Providence to Boston = 52 miles Springfield to Worcester =55 miles 2RT distance 1RT distance (3) MP L2 5.1.2 (b) Conditions or nature of the roads/Toestand van die paaie OR/OF Permissible speed or differing speed limits /Toelaatbare spoed of verskillende spoedbekerkings OR/OF Volume of traffic on the road/Hoeveelheid verkeer op die pad OR/OF Number of Traffic lights/Aantal verkeers ligte OR/OF Speed humps / Animals / Riots/Unrest/Protest Spoedhobbels /diere / oproer/ onrus/ protes aksies 2A opinion (2) MP L4 5.1.3 A Newburyport B Lawrence C Boston D Worcester 1A Newburyport 1A Lawrence 1A Boston 1A Worcester (4) MP L2 A A O A A A A RT RT

of

87,664..

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 16 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T&L 5.1.4 Number of litres in 23 gallons/Getal liter in 23 gelling = 3,785 × 23 = 87,055 litre Cost of 87,055 litre/ Prys vir 87,055 liter = 87,055 × R15,97 = R1 390,27 Valid/ Geldig OR/OF Number of litres / Getal liter = =
litre Number of gallons / Getal gellings = =23,16 gallons Can buy more with R1 400/Kan meer koop met R 1400 Valid / Geldig 1C gallons to litre 1S simplification 1CA cost
fuel 1O conclusion OR/OF 1S simplification 1C gallons to litre 1CA cost of fuel 1O conclusion NPR (4) MF L4  S  O  CA  C  C  O  CA  S

NSC/NSS Marking Guidelines/Nasienriglyne

Q/V Solution/Oplossing Explanation/Verduidelik T/L

5.1.5

1 full tank of fuel/ 1vol tenk = 23 gallons /gelling

He can travel/ Hykan reis = 23 × 18 = 414 miles

Distance/afstand Greenfield Fitchburg = 49 miles/myl

Number of trips on 1 full tank /Getalritte met 1 voltenk

= 49 414 = 8,448..

 8 trips on 1 full tank / 8 ritte met 1 voltenk

So, then he will fill tank back to 23 gallons Dan hervulhy die tenk tot 23 gelling

Amount of fuel for 1 return trip/ brandstofvir1heen en weer reis = 18 98 = 5,44 gallon

Left in a tank is 23 5,44 = 17,56 gallons. Oor in die tenk is 23 5,44 = 17,56 gelling

OR/OF Distance/afstand(Greenfield and Fitchburg) = 49 miles/myl

Weekly must travel/ moet weekliks ry = 5 × 2 = 10 trips

He can travel = 23 × 18 = 414 mileswith a full tank. Hy kan 414 myl ry met ‘n vol tenk, 8 trips is 49 × 8 = 392 miles now he needs to refill after Thursday’s trips

ritte is 392 myl dan hervul hy na Donderdag se terugkeer.

With the full tank he only needs to travel Friday return trip / HyrydanslegsVrydagheen en weer Friday trip: 49 × 2 = 98 miles / myl

Used/Gebruik = 18 98 = 5,44 gallons/ gelling

Left in a tank is 23 5,44 = 17,56 gallons. Daar is 23 5,44 = 17,56 gelling in die tenkoor

Copyright reserved/Kopiereg voorbehou

1A travel distance

1RT trip distance 1MA dividing 1CA number of trips

1MA dividing 1CA simplification

1MA subtracting 1CA simplification

OR/OF 1RT trip distance

1MA weekly miles 1MA multiply

1A travel distance

1MA dividing 1CA usage on last day

1MA subtracting 1CA diff. between capacity and used gallons

Please turn over/Blaai om asseblief

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 17 DBE/November 2021
8
M L3  MA  A  MA  MA  CA  CA  CA  A  CA  CA  MA  RT  MA  MA  MA  RT

1RT trip distance

dividing

travel distance

1CA number of

simplification

subtracting

simplification

1CA

trip distance

dividing

subtracting 1CA simplification

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 18 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Q/V Solution/Oplossing Explanation/Verduideliking T/L 18 miles on 1 gallon / 18 myl op 1 gelling 49 miles on x gallon / 49 myl op x gelling x = 48 18 = 2,722… gallon per trip / gelling per rit Number of trips on 1st full tank / Getalritte met 1stvoltenk = 23 2,722... = 8,44…  8 trips before he fills up again / 8 rittevoorhyweervolmaak 2 trips with second full tank/ 2 ritte met die 2de voltenk Fuel used / Brandstofverbruik = 2,722…× 2 = 5,44… gallon / gelling Left in the tank / Oor in die tenk = 23 5,44… = 17,56 gallon / gelling OR/OF Single Trip/Enkelrit = 49 miles /myl Number of gallons for 1 trip/ Getal gelling vir 1 rit = 49 ÷ 18 = 2,72 Number of gallons for return trip/ virretoerrit = 2,72 × 2 = 5,44 23 gallons/gelling ÷ 5,44 = 4,22 days/dae ≈ 4 days/dae No of gallons left / Hoeveelheid gelling oor = 23 5,44 = 17,56 gallons OR/OF
1MA
1A
trips 1MAmultiplying 1CA
1MA
1CA
OR/OF 1RT
1MA
1A travel distance 1CA number of trips 1MA dividing
simplification 1MA
OR/OF  RT  MA  A  CA  MA  CA  MA  CA  RT  MA  A  MA  CA  MA  CA  CA

Explanation/Verduideliking T/L

23 × 18 = 414 miles/myl

Monday/Maandag : 49 × 2 = 98 miles/myl Tuesday/Dinsdag : 98 miles/myl

Wednesday/Woensdag: 98 miles/myl Thursday/ Donderdag 98 miles/myl Totaal = 392 miles/myl

Fill up the tank on Thursday / Maak die tenk vol

op Donderdag

Used per day /Gebruik

= 98 ÷ 18 = 5,44gallons

Petrol left in tank/Petrol oor in tenk = 23 5,44 = 17,56 gallons

Miles that can be travelled after Friday/Myle wat nog gereis kan word na Vrydag = 414 98 = 316 miles/myl Petrol left in tank/Petrol oor in tenk = 316 ÷ 18 = 17,56 gallons

Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 19 DBE/November 2021 NSC/NSS Marking Guidelines/Nasienriglyne Copyright reserved/Kopieregvoorbehou Q/V Solution/Oplossing
petrol
per dag
1A travel distance 1RT trip distance 1MA multiplying 1CA number of trips 1MA dividing 1CA simplification 1MA subtracting 1CA simplification (8) 5.2 0C = 9 5 (0F 32 ) 7 = 9 5 ( 0F 32) 0F = 5 9 × 7 + 32 = 19,4 ≈ 200F 1SF substitution 1S simplification 1CA simplification 1R rounding (4) M L2 [29] TOTAL/TOTAAL: 150  R  S  SF  CA Or/of °F = = 19,4 °C ≈ 20 °C  RT A MA CA  CA  MA  MA  CA
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