Sample Problem 3.3.2 — Collision Between Two Objects: Vector Components (Continued) What to Think About 2. In Figure 3.3.2, the resultant momentum ( pR = pio ) was drawn first. Then the directions of pif and psf were constructed. As you can see, it is then a simple task to complete the momentum vector triangle.
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3. After the collision, pR = pio = 0.10 kg⋅m/s in the direction shown. Use trigonometry to solve for the magnitudes of pif and psf .
Figure 3.3.2 pif = pR cos 60 o pif = ( 0.10 kg • m s)( 0.500 ) pif = 0.050 kg • m s pif 0.050 kg • m s = v if = = 1.0 m s 0.050 kg mi
Challenge: Can you see a shorter way to solve this particular problem?
86 Chapter 3 Momentum and Energy
Similarly, psf = pR sin 60 o psf = ( 0.10 kg • m s)( 0.866 ) psf = 0.087 kg • m s psf 0.087 kg • m s = v sf = = 1.7 m s 0.050 kg ms
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