Integrales indefinidas resueltas 02

Page 31

INTEGRALES INDEFINIDAS RESUELTAS

= −2

1 ⋅ dx + 2 x

1 ⋅ dx + 2 x +1

= −2 ⋅ Ln | x | +2 ⋅ Ln | x + 1| +2

1 ⋅ dx + 5 ( x + 1) 2

( x + 1) −2 ⋅ dx + 5

1 ⋅ dx = ( x + 1)3

( x + 1) −3 ⋅ dx =

( x + 1) −1 ( x + 1)−2 = −2 ⋅ Ln | x | +2 ⋅ Ln | x + 1| +2 +5 +k = −1 −2 = Ln

( x + 1) 2 2 5 ( x + 1) 2 4( x + 1) + 5 − − + k = Ln − +k = x2 x + 1 2( x + 1) 2 x2 2( x + 1) 2

= Ln

( x + 1) 2 4x + 9 − +k 2 x 2( x + 1) 2

115.

116.

117.

x3 − 3 x dx 64 x

6

118.

119.

120.

121.

∫e

122.

x 2 dx ( x + 2) 2 ( x + 4) 2

x 4

6

x +1 3

x + x 7

7

dx

x +1

7

4

5

x +

14

x

15

dx e +1 x

4 3

Sol:

2 4 9 2 x − 12 x 13 + k 27 13

(

4

x 3 − Ln

(

4

))

x3 +1 + k

6 12 + 12 + 2 Ln x − 24 Ln (12 x + 1) + k x x 1

1

1

1

 1− x 3 1− x 6  − + 1 − x − Ln 1 + 6 1 − x  + k 2  3 

dx 1− x + 3 1− x

2x

Sol:

14 3 x − 7 x 2 + 14 x 5  + k Sol: 4 14 x − 7 x + 2 3 4 5  

dx

ex dx + ex − 2

5 x + 12  x+4 + Ln   +k 2 x + 6x + 8  x+2

Sol: − 6

dx

x+ x 8

2

Sol: −

Sol: 6

Sol:

1 ex −1 Ln x +k 3 e +2 Sol: x − Ln (e x +1) + k

31

(

)


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