ﺍﻟﻔﺭﻗﺔ ﺍﻻﻭﻟﻰ
ﺍﻟﻣﺣﺎﺿﺭﺓ ﺍﻷﻭﻟﻰ
ﻛﻳﻣﻳﺎء ﻋﺿﻭﻳﺔ
ﺩ/ﺣﻧــــــــﺎﻥ
ﺍﺣﻠ ُ ْﻝ ﺳ ْﺭ ِﻟﻲ ﺃَ ْﻣ ِﺭﻱ َﻭ ْ ﺏ ﺍﺷ َْﺭﺡْ ِﻟﻲ َ ﺻﺩ ِْﺭﻱ َﻭﻳَ ِ ّ َﺭ ّ ِ ﺳﺎﻧِﻲ ﻳَ ْﻔﻘَ ُﻬﻭﺍ ﻗَ ْﻭ ِﻟﻲ ﻋُ ْﻘﺩَﺓً ِﻣ ْﻥ ِﻟ َ ﺍﻟﺳﻼﻡ ﻋﻠﻳﻛﻡ ...ﺍﺯﻳﻛﻡ ﻳﺎ ﺷﺑﺎﺏ ﺍﻟﻣﺳﺗﻘﺑﻝ ....ﺍﻟﻑ ﻣﺑﺭﻭﻙ ﻋﻠﻰ ﻧﺗﺎﻳﺞ ﺍﻟﺗﺭﻡ ﺍﻻﻭﻝ ﻭﺍﻥ ﺷﺎء ﷲ ﺍﻟﺗﺭﻡ ﺍﻟﺗﺎﻧﻰ ﻳﻛﻭﻥ ﺍﻓﺿﻝ ﻛﻣﺎﻥ .......ﻭﺍﻟﻠﻰ ﻣﺵ ﺣﺎﻟﻔﻪ ﺍﻟﺣﻅ ﻳﺑﺩﺃ ﻳﺫﺍﻛﺭ ﻣﻥ ﺑﺩﺭﻯ ﺑﻘﻰ ﻓﻳﻪ ﻛﻼﻡ ﻓﻰ ﺍﻟﺑﺩﺍﻳﺔ ﻋﻥ ﺍﻛﺗﺷﺎﻑ ﺍﻟﺑﻧﺯﻳﻥ ﻭﻏﻳﺭﻩ .....ﺩﻩ ﺍﻧﺎ ﻫﺷﺭﺣﻪ ﻣﻊ ﺷﺭﺡ ﺍﻟﺑﻧﺯﻳﻥ ﻋﻠﺷﺎﻥ ﻣﺵ ﺍﺩﺧﻝ ﻛﻠﻪ ﻓﻰ ﺑﻌﺿﻪ .......ﻫﻧﺑﺩﺃ ﻣﻌﺎﻛﻡ ﺑﻣﺭﺍﺟﻌﺔ ﺑﺳﻳﻁﺔ ﻋﻠﻰ ﺍﻟﺗﻬﺟﻳﻥ ﻋﻠﺷﺎﻥ ﻫﻧﺣﺗﺎﺟﻪ ﻭﺑﻌﺩﻫﺎ ﻧﺩﺧﻝ ﻋﻠﻰ ﺍﻟﻣﻁﻠﻭﺏ ^_^
Hybridization • ﻛﻧﺎ ﺑﻧﻌﺭﻑ ﻧﻭﻉ ﺍﻟﺗﻬﺟﻳﻥ ﻋﻥ ﻁﺭﻳﻕ ﻣﺟﻣﻭﻉ : Number of sigma bond + lone pair of electrons
Sp3 Sp2 Sp
• =4 • =3 • =2 • EX:
Sp3 ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
Sp2 1
sp Dr\Ahmed Al3yde
• Atoms Have lone pair of electrons :
HeteroAtoms : O , N , S Halogens : F , CL , Br , I
Sp3
Sp3
ــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ • Hybridization of ions : • Carbocation C
+
• Free radical C• • Carboanion C •
Sp2 Sp2 Sp3 Except in Resonance
EX:
Sp2
CH3
Sp2
-
Sp3
CH3
Sp2 C H
-
Sp2 N H
H2C
-
CH CH2
Dr\Ahmed Al3yde
Sp2
2
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
ﻧﺩﺧﻝ ﺑﻘﻰ ﻋﻠﻰ ﺍﻟﺷﺭﺡ... ﻁﺑﻌﺎ ﺍﻧﺗﻭ ﻋﺎﺭﻓﻳﻥ ﻛﻝ ﺍﻟﻠﻰ ﻓﻭﻕ ﻭﺷﺭﺣﻧﺎﻩ ﻛﺗﻳﺭ ﺍﻟﺗﺭﻡ ﺍﻻﻭﻝo
o What is the difference between aliphatic and aromatic compound ? Aliphatic compound : • Open Chain Hydrocarbon : Alkane , Alkene , Alkyne • Cyclic Hydrocarbon : cyclo alkane , cyclo alkene ﻛﻝ ﺍﻟﺣﺎﺟﺎﺕ ﺍﻟﻠﻰ ﺍﺧﺩﻧﺎﻫﺎ ﺍﻟﺗﺭﻡ ﺍﻻﻭﻝ ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ
Aromaticity
• The compound to be aromatic it must fulfill the following requirements : 1- Cyclic 2- Planar 3- Complete conjugation (sp2 hybride) 4- Obey Huckel’s rule : ﺷﺭﻭﻁ ﺩﻯ٤ • ﻳﻌﻧﻰ ﻋﻠﺷﺎﻥ ﺍﻟﻣﺭﻛﺏ ﻳﺗﻘﺎﻝ ﻋﻠﻳﻪ ﺍﺭﻭﻣﺎﺗﻰ ﻻﺯﻡ ﺗﺗﻭﻓﺭ ﻓﻳﻪ ﺍﻝ ﺣﻠﻘﻰ: Cyclic -١ ﻣﺳﻁﺢ:Planar -٢ ﻳﻌﻧﻰ ﺗﺗﺑﺎﺩﻝ ﻓﻳﻪ ﺍﻟﺭﻭﺍﺑﻁ ﺍﻻﺣﺎﺩﻳﺔ ﻣﻊ: Complete conjugation -٣ ﺍﻟﺛﻧﺎﺋﻳﺔ ﻓﻰ ﻛﻝ ﺍﻟﺣﻠﻘﺔ Dr\Ahmed Al3yde
3
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
-٤ﻭﺍﺧﻳﺭﺍ ﻻﺯﻡ ﻳﺗﺑﻊ ﻗﺎﻧﻭﻥ Huckel ﻳﻼ ﻧﺷﺭﺡ ﻛﻝ ﻧﻘﻁﺔ ﺑﺎﻟﺗﻔﺻﻳﻝ 1-cyclic ﻣﺭﻛﺏ ﺣﻠﻘﻰ
ﻣﺭﻛﺏ ﻏﻳﺭ ﺣﻠﻘﻰ
ﻳﻌﻧﻰ ﺍﻳﻪ ﻣﺭﻛﺏ ﺣﻠﻘﻰ ...ﻳﻌﻧﻰ ﻳﺣﺩﺙ ﺗﺩﺍﺧﻝ ﺑﺎﻟﺭﺃﺱ ﺑﻳﻥ ﺟﻣﻳﻊ ﺫﺭﺍﺕ ﺍﻟﻣﺭﻛﺏﻟﺗﻛﻭﻳﻥ ﺣﻠﻘﺔ )ﺭﻭﺍﺑﻁ ﺳﻳﺟﻣﺎ ( ﻋﻧﺩﻙ ﻋﻠﻰ ﺍﻟﺷﻣﺎﻝ ﺩﻯ ﺣﻠﻘﺔ ﺍﻟﺑﻧﺯﻳﻥ ....ﺣﺻﻝ ﻓﻳﻬﺎ ﺗﺩﺍﺧﻝ ﺑﺎﻟﺭﺃﺱ ﺑﻳﻥ ٦ﺫﺭﺍﺕﻛﺭﺑﻭﻥ ﻭﻛﻭﻧﻭﺍ ﺣﻠﻘﺔ ﺑﻧﺯﻳﻥ ...ﻭﺍﻟﺟﺯء ﺍﻟﻌﻣﻭﺩﻯ ﻋﻠﻰ ﺍﻟﻛﺭﺑﻭﻧﺎﺕ ﺩﻩ ﻋﺑﺎﺭﺓ ﻋﻥ ﺍﻭﺭﺑﻳﺗﺎﻝ pﺍﻟﻠﻰ ﻣﺵ ﺍﺷﺗﺭﻙ ﻓﻰ ﺍﻟﺗﻬﺟﻳﻥ ﻻﻧﻧﺎ ﻋﺎﺭﻓﻳﻥ ﺍﻥ ﺟﻣﻳﻊ ﺫﺭﺍﺕ ﺍﻟﺑﻧﺯﻳﻥ ﺗﻬﺟﻳﻧﻬﺎ ) sp2ﺍﻭﺭﺑﻳﺗﺎﻝ 2 + Sﺍﻭﺭﺑﻳﺗﺎﻝ ( P ﻁﺑﻌﺎ ﺍﻭﺭﺑﻳﺗﺎﻝ Pzﺩﻩ ﻫﻭ ﺍﻟﻣﺳﺋﻭﻝ ﻋﻥ ﺗﻛﻭﻳﻥ ﺭﻭﺍﺑﻁ ﺑﺎﻯ ﻋﻥ ﻁﺭﻳﻕ ﺍﻟﺗﺩﺍﺧﻝﺑﺎﻟﺟﻧﺏ ﺍﻣﺎ ﺍﻟﻣﺭﻛﺏ ﻋﻠﻰ ﺍﻟﻳﻣﻳﻥ ﻓﻬﻭ ﺃﻟﻛﻳﻥ ﻋﺎﺩﻯ .....ﻭﻣﻭﺿﺣﻳﻥ ﺍﻥ ﻣﺵ ﺣﺻﻝ overlapﺑﻳﻥ ﺍﻻﻭﺭﺑﻳﺗﺎﻻﺕ .....ﻓﺗﻛﻭﻧﺕ ﺳﻠﺳﻠﺔ ﻣﻔﺗﻭﺣﺔ ...ﻭﻻ ﻳﻣﻛﻥ ﻳﻛﻭﻥ ﻓﻳﻪ ﻣﺭﻛﺏ ﺍﺭﻭﻣﺎﺗﻰ ﺑﺳﻠﺳﻠﺔ ﻣﻔﺗﻭﺣﺔ ...ﻳﺎ ﺭﺏ ﺗﻛﻭﻥ ﻭﺻﻠﺕ ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
4
Dr\Ahmed Al3yde
ﻣﺳﻁﺢ
2- planar
• ﺍﻳﻪ ﺍﻗﺭﺏ ﻣﺛﺎﻝ ﻟﻠﻣﺭﻛﺏ ﺍﻟﻣﺳﻁﺢ : ﺍﻟﺳﺑﻭﺭﺓ ﻣﺳﻁﺣﺔ ...ﻻﻥ ﺟﻣﻳﻊ ﺍﺟﺯﺍﺋﻬﺎ ﻓﻰ ﻣﺳﺗﻭﻯ ﻭﺍﺣﺩ ﻧﻔﺱ ﺍﻟﺣﻛﺎﻳﺔ ﻻﺯﻡ ﺍﻟﻣﺭﻛﺏ ﺍﻻﺭﻭﻣﺎﺗﻰ ﻳﻛﻭﻥ ﻣﺳﻁﺢ ....ﻳﻌﻧﻰ ﺟﻣﻳﻊﺍﻟﺫﺭﺍﺕ ﺍﻟﻣﻛﻭﻧﺔ ﻟﻠﺣﻠﻘﺔ ﻳﻛﻭﻧﻭﺍ ﻓﻰ ﻧﻔﺱ ﺍﻟﻣﺳﺗﻭﻯ • EX: ﺫﻯ ﻣﺎ ﺍﻧﺗﻭ ﺷﺎﻳﻔﻳﻥ ﺩﻯ ﺣﻠﻘﺔ ﺑﻧﺯﻳﻥ .... ﺟﻣﻳﻊ ﺫﺭﺍﺕ ﺍﻟﻛﺭﺑﻭﻥ ﻭﺍﻟﻬﻳﺩﺭﻭﺟﻳﻥ ﻓﻰ ﻧﻔﺱ ﺍﻟﻣﺳﺗﻭﻯ ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ
)3- complete conjugation (Sp2 hybride
ﻋﻠﻰ ﺍﻟﺷﻣﺎﻝ ﻓﻳﻪ ﺣﻠﻘﺔ ﺍﻟﺑﻧﺯﻳﻥ ﺍﻟﻠﻰ ﺑﺗﺗﺑﺎﺩﻝ ﻓﻳﻬﺎ ﺍﻟﺭﻭﺍﺑﻁ ﺍﻟﺛﻧﺎﺋﻳﺔ ﻣﻊ ﺍﻻﺣﺎﺩﻳﺔ ...ﻭﺟﻣﻳﻊﺫﺭﺍﺕ ﺍﻟﺑﻧﺯﻳﻥ ﺗﻬﺟﻳﻧﻬﺎ Sp2ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ ﺩﻩ ﻓﻳﻪ complete conjugation ﺍﻟﻣﺭﻛﺑﻳﻥ ﺍﻟﺗﺎﻧﻳﻳﻥ ﻓﻳﻪ ﺫﺭﺓ ﻓﻰ ﺍﻟﺣﻠﻘﺔ ﺗﻬﺟﻳﻧﻬﺎ Sp3ﺑﺗﻭﻗﻑ ﺍﻝ conjugation ﻳﻌﻧﻰ ﻧﻘﺩﺭ ﻧﻘﻭﻝ ﻟﻭ ﺍﻟﺣﻠﻘﺔ ﺗﺣﺗﻭﻯ ﻋﻠﻰ ﺫﺭﺓ ﻭﺍﺣﺩﺓ ﺗﻬﺟﻳﻧﻬﺎ Sp3ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ not) aromaticﻭﺧﻠﻰ ﺑﺎﻟﻙ ﺍﻧﺎ ﻗﻠﺕ ﺍﻟﺫﺭﺍﺕ ﺍﻟﻣﻛﻭﻧﺔ ﻟﻠﺣﻠﻘﺔ ﻫﻰ ﺍﻟﻠﻰ ﺗﻬﺟﻳﻧﻬﺎ ( Sp2
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
5
Dr\Ahmed Al3yde
ﺑﺱ ﻳﻌﻧﻰ ﺍﻳﻪ complete conjugation Contineous or nearly continuous overlapping of all p orbitals ﻳﻌﻧﻰ ﺗﺩﺍﺧﻝ ﻣﺳﺗﻣﺭ ﻷﻭﺭﺑﻳﺗﺎﻻﺕ Pﺩﻩ ﻣﻌﻧﺎﻩ ﺍﻥ ﻻﺯﻡ ﻛﻝ ﻛﺭﺑﻭﻣﺔ ﺗﺣﺗﻭﻯ ﻋﻠﻰ ﺍﻭﺭﺑﻳﺗﺎﻝ Pﻏﻳﺭ ﻣﻬﺟﻥ ﻭﺫﻯ ﻣﺎ ﺍﺧﺩﺗﻭﺍ ﺍﻟﺗﺭﻡ ﺍﻻﻭﻝ ﺍﻥ ﺍﻟﻛﺭﺑﻭﻧﺔ ﺍﻟﻠﻰ ﺗﻬﺟﻳﻧﻬﺎ Sp3ﻻﺗﺣﺗﻭﻯ ﻋﻠﻰ ﺍﻭﺭﺑﻳﺗﺎﻝ ﻏﻳﺭ ﻣﻬﺟﻥ ...ﻋﻠﺷﺎﻥ ﻛﺩﻩ ﻣﺵ ﺑﺗﻌﻣﻝ conjugation ﻁﻳﺏ ﻳﺎ ﺩﻛﺗﻭﺭ ﻣﺎ ﺍﻟﻛﺭﺑﻭﻧﺔ ﺍﻟﻠﻰ ﺗﻬﺟﻳﻧﻬﺎ Spﺗﺣﺗﻭﻯ ﻋﻠﻰﺍﻭﺭﺑﻳﺗﺎﻟﻳﻥ Pﻏﻳﺭ ﻣﻬﺟﻧﻳﻥ ...ﻫﻝ ﻳﻧﻔﻊ ﺗﻌﻣﻝ conjugation؟ ﺍﻛﻳﺩ ﻁﺑﻌﺎ ﻳﻧﻔﻊ ...ﻳﻌﻧﻰ ﻣﻣﻛﻥ ﻧﻘﻭﻝ ﻻﺯﻡ ﺟﻣﻳﻊ ﺫﺭﺍﺕ ﺍﻟﺣﻠﻘﺔﺗﻬﺟﻳﻧﻬﺎ Sp2ﺍﻭ SPﺍﻭ ﺍﻻﺗﻧﻳﻥ ﻣﻌﺎ ....ﺍﻩ ﻳﻧﻔﻊ ﺑﺱ ﻣﺵ ﻫﺩﻳﻠﻛﻡ ﺍﻣﺛﻠﺔ ﺍﻻ ﻟﻭ ﺩ/ﺣﻧﺎﻥ ﺷﺭﺣﺗﻬﺎ ﻟﻳﻛﻡ ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ
4- Huckel’s rule Number of ࣊ electrons = 4n+2 • n = 0,1,2,3,….. ﺭﻛﺯ ﻣﻌﺎﻳﺎ ﺑﻘﻰ ﺑﻳﻘﻭﻟﻙ ﻻﺯﻡ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻣﻛﻭﻧﺔ ﻟﻠﺭﺍﺑﻁﺔ ﺑﺎﻯ ﻳﺳﺎﻭﻯ 4n+2ﺑﺣﻳﺙ nﺗﻛﻭﻥﻋﺩﺩ ﺻﺣﻳﺢ -ﺗﻌﺎﻟﻰ ﻧﻔﻬﻡ ﺑﻣﺛﺎﻝ
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
6
Dr\Ahmed Al3yde
2 electrons
EX: 2 electrons
2 electrons -
-
ﺫﻯ ﻣﺎ ﺍﺣﻧﺎ ﻋﺎﺭﻓﻳﻥ ﺍﻥ ﺍﻯ ﺭﺍﺑﻁﺔ ﺑﺗﻛﻭﻥ ﻣﻛﻭﻧﺔ ﻣﻥ ﺍﻟﻛﺗﺭﻭﻧﻳﻥ )ﺍﻟﻛﺗﺭﻭﻥ ﻣﻥ ﻛﻝ ﺫﺭﺓ ( ﻳﻌﻧﻰ ﺍﻯ ﺭﺍﺑﻁﺔ ﺑﺎﻯ ﻓﻰ ﺣﻠﻘﺔ ﺍﻟﺑﻧﺯﻳﻥ ﻫﺗﻛﻭﻥ ﻣﻛﻭﻧﺔ ﻣﻥ ﺍﻟﻛﺗﺭﻭﻧﻳﻥ )ﺍﻟﻛﺗﺭﻭﻥ ﻣﻥ ﻛﻝ ﺫﺭﺓ ﻛﺭﺑﻭﻥ ﺑﺗﺷﺎﺭﻛﻪ ﻣﻊ ﺍﻟﺫﺭ ﺍﻟﻣﺟﺎﻭﺭﺓ ﻭﺗﺗﻛﻭﻥ ﺭﺍﺑﻁﺔ ﺑﺎﻯ ( ﻗﺎﻟﻙ ﺑﻘﻰ ﺍﻧﺕ ﺗﻌﺭﻑ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻣﻛﻭﻧﺔ ﻟﻠﺭﻭﺍﺑﻁ ﺑﺎﻯ ﻓﻰ ﺍﻟﺣﻠﻘﺔ ﻭﺗﻌﻭﺽ ﺑﻳﻬﺎ ﻓﻰ ﺍﻟﻘﺎﻧﻭﻥ 4n+2ﻭﻟﻭ nﻁﻠﻌﺕ ﻋﺩﺩ ﺻﺣﻳﺢ ﻳﺑﻘﻰ ﺗﻣﺎﻡ ﻭﺍﻟﻣﺭﻛﺏ ﻳﺗﺑﻊ ﻗﺎﻧﻭﻥ huckel ... ﻛﻝ ﺍﻟﻠﻰ ﻋﻠﻳﻙ ﺍﻧﻙ ﺗﻌﺩﺩ ﺭﻭﺍﺑﻁ ﺑﺎﻯ ﻭﺗﺿﺭﺑﻬﺎ ﻓﻰ ﺍﺗﻧﻳﻥ ....ﻳﻌﻧﻰ ﻣﺛﻼ ﺍﻟﺑﻧﺯﻳﻥ ﻳﺣﺗﻭﻯ ﻋﻠﻰ ٣ﺭﻭﺍﺑﻁ ﺑﺎﻯ .....ﻳﺑﻘﻰ ﻳﺣﺗﻭﻯ ﻋﻠﻰ ٦ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ﻣﻛﻭﻧﻳﻥ ﻟﻬﺫﻩ ﺍﻟﺭﻭﺍﺑﻁ .... ﻧﻌﻭﺽ ﺑﻘﻰ • 4n+2 = 6 • n=1 • Aromatic ﻋﻭﺿﻧﺎ ﻓﻰ ﺍﻟﻘﺎﻧﻭﻥ ﺑﺭﻗﻡ 6ﻓﻁﻠﻌﺕ nﻋﺩﺩ ﺻﺣﻳﺢ ...ﻋﻠﺷﺎﻥ ﻛﺩﻩ ﺍﻟﻣﺭﻛﺏ ﺍﺭﻭﻣﺎﺗﻰ ﻭﻁﺑﻌﺎ ﻣﻼﺣﻅﻳﻥ ﺍﻥ ﺍﻟﺷﺭﻭﻁ ﺍﻻﺭﺑﻌﺔ ﺗﻧﻁﺑﻕ ﻋﻠﻰ ﺍﻟﺑﻧﺯﻳﻥ ﻋﻠﺷﺎﻥ ﻛﺩﻩﻫﻭ ﺍﺷﻬﺭ ﺍﻟﻣﺭﻛﺑﺎﺕ ﺍﻷﺭﻭﻣﺎﺗﻳﺔ ﻳﺑﻘﻰ ﻛﺩﻩ ﻻﺯﻡ ﺍﻝ ٤ﺷﺭﻭﻁ ﺗﻛﻭﻥ ﻣﻭﺟﻭﺩﺓ ﻓﻰ ﺍﻟﻣﺭﻛﺏ ﻋﻠﺷﺎﻥ ﻧﻘﻭﻝ... Aromaticﻭﻟﻠﻌﻠﻡ ﺍﻟﻣﺭﻛﺑﺎﺕ ﺍﻟﻐﻳﺭ ﻣﺳﻁﺣﺔ ﻫﺗﻌﺭﻓﻬﻡ ﺑﺎﻻﺳﻡ ﻓﻣﺵ ﺗﻘﻠﻕ ﻣﻥ ﺍﻟﻧﻘﻁﺔ ﺩﻯ ....ﺗﻌﺎﻟﻰ ﻧﺎﺧﺩ ﻣﺛﺎﻟﻳﻥ ﻋﻠﻰ ﺍﻟﺳﺭﻳﻊ
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
7
Dr\Ahmed Al3yde
4n + 2 = 18
4n + 2 = 14
n=4
n=3
Aromatic
Aromatic
ﺍﻟﻣﺭﻛﺑﻳﻥ ﺍﻟﻠﻰ ﻓﻭﻕ cyclic , planar ,ﻭﻛﻝ ﺫﺭﺍﺗﻬﻡ ﺗﻬﺟﻳﻧﻬﺎ Sp2 ﻭﻛﻣﺎﻥ ﻋﺭﻓﻧﺎ ﻋﺩﺩ ﺭﻭﺍﺑﻁ ﺑﺎﻯ ﻭﺿﺭﺑﻧﺎﻫﻡ ﻓﻰ ﺍﺗﻧﻳﻥ ...ﻭﻋﻭﺿﻧﺎ ﻓﻰ ﺍﻟﻘﺎﻧﻭﻥ ﻭﻁﻠﻊ nﻋﺩﺩ ﺻﺣﻳﺢ ....ﻳﺑﻘﻰ ﺧﻼﺹ ﺍﻟﻣﺭﻛﺏ Aromatic ﻫﻧﻌﺭﻑ ﻳﻌﻧﻰ ﺍﻳﻪ Annuleneﻣﺵ ﺗﺳﺗﻌﺟﻝ ^_^ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ
ﻁﻳﺏ ﺍﻣﺗﻰ ﺍﻗﻭ ﻻﻥ ﺍﻟﻣﺭﻛﺏ not aromatic ﺍﻛﻳﺩ ﻳﻌﻧﻰ ﻟﻭ ﺣﺻﻝ ﻧﻘﺹ ﻓﻰ ﺍﻯ ﺷﺭﻁ ﻣﻥ ﺍﻟﺷﺭﻭﻁ ﺍﻻﺭﺑﻌﺔ ﺍﻟﻠﻰ ﺍﺧﺩﻧﺎﻫﻡ ...ﺗﻌﺎﻟﻰ ﻧﺎﺧﺩ ﻣﺛﺎﻝ ﻟﻠﺗﻭﺿﻳﺢ ﺩﻟﻭﻗﺗﻰ
ﺍﻟﻣﺭﻛﺏ ﺍﻟﻠﻰ ﻓﻭﻕ ﺩﻩ ﻋﻠﻰ ﺍﻟﺭﻏﻡ ﺍﻧﻪ ﺣﻠﻘﻰ ﻭﺟﻣﻳﻊ ﺫﺭﺍﺗﻪ ﺗﻬﺟﻳﻧﻬﺎ sp2 ﺍﻻ ﺍﻧﻪ ﻣﺵ ﺍﺭﻭﻣﺎﺗﻰ ؟!!! ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
8
Dr\Ahmed Al3yde
ﻻﻥ ﺍﻟﻣﺭﻛﺏ ﻣﺵ ﻣﺳﻁﺢ ...ﻳﻌﻧﻰ ﻓﻳﻪ ﺫﺭﺍﺕ ﻛﺭﺑﻭﻥ ﻓﻭﻕ ﻣﺳﺗﻭﻯ ﺫﺭﺍﺕﻛﺭﺑﻭﻥ ﺗﺎﻧﻳﺔ ...ﻣﺵ ﻛﻝ ﺍﻟﺫﺭﺍﺕ ﻧﻔﺱ ﺍﻟﻣﺳﺗﻭﻯ ﻳﻌﻧﻰ ﺍﻟﻣﺭﻛﺏ non- planarﻳﺑﻘﻰ ﻋﻠﻰ ﻁﻭﻝ not aromatic ﻫﻧﺎﺧﺩ ﺍﻟﻣﺭﻛﺏ ﺩﻩ ﺑﺎﻟﺗﻔﺻﻳﻝ ...ﺍﻧﺎ ﺣﻁﻪ ﻫﻧﺎ ﻛﻣﺛﺎﻝ ﻟﻠﻔﻬﻡ ﺍﻣﺗﻰ ﺍﻗﻭﻝ ﻋﻠﻰ ﺍﻟﻣﺭﻛﺏ Anti-Aromatic؟؟؟ ﺭﻛﺯ ﻣﻌﺎﻳﺎ ﺑﻘﻰ ﻋﻠﺷﺎﻥ ﻧﻔﺭﻕ ﺑﻳﻥ Aromatic , not aromatic ,anti aromatic ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ
Anti Aromatic
• Requirements : 1- Cyclic 2- Planar 3- Complete conjugation 4- Number of ࣊ electrons = 4n ﻭﺍﺿﺢ ﺟﺩﺍ ﺍﻧﻪ ﺫﻯ ﺍﻝ Aromaticﻟﻛﻥ ﻫﻣﺎ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻠﻰ ﻓﻰﺍﻟﻣﺭﻛﺏ ﻫﻳﺳﺎﻭﻯ 4nﺑﺣﻳﺙ nﺗﻛﻭﻥ ﻋﺩﺩ ﺻﺣﻳﺢ ﺗﻌﺎﻟﻰ ﻧﻔﻬﻡ ﺑﺎﻷﻣﺛﻠﺔCyclo butadiene ﺩﻩ ﻣﺭﻛﺏ ﻫﻧﺗﻌﺎﻣﻝ ﻣﻌﺎﻩ ﻋﺎﺩﻯ ﺟﺩﺍ ﺫﻯ ﻣﺎ ﺍﺗﻌﻭﺩﻧﺎ ﻫﻧﻼﻗﻳﻪ cyclic , planar ,ﻛﻝ ﺫﺭﺍﺗﻪ ﺗﻬﺟﻳﻧﻬﺎ sp2 ﻋﻧﺩﻩ ﺭﺍﺑﻁﺗﻳﻥ ﺑﺎﻯ ......ﻳﺑﻘﻰ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻣﻛﻭﻧﺔ ﻟﻠﺭﻭﺍﺑﻁ ﺑﺎﻯ = ٤ ﺗﻌﺎﻟﻰ ﻧﻌﻭﺽ ﻓﻰ ﻗﺎﻧﻭﻥ huckelﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
9
Dr\Ahmed Al3yde
4n = 4
4n + 2 = 4
n=1
n=0.5
anti aromatic ﺑﻛﻝ ﺑﺳﺎﻁﺔ ﺗﻌﺎﻟﻰ ﻧﻔﻬﻡ ﻓﻛﺩﻩ ﺍﻟﻣﺭﻛﺏ ﺩﻩ... ﻋﺑﺎﺭﺓ ﻋﻥ ﻛﺳﺭn ﻁﻠﻌﺕhuckel ﻓﻭﻕ ﻟﻣﺎ ﻋﻭﺿﻧﺎ ﻓﻰ ﻗﺎﻧﻭﻥ huckel ﻣﺵ ﺑﻳﺗﺑﻊ ﻗﺎﻧﻭﻥ ﺍﻟﻠﻰ ﻫﻭ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕanti-aromatic ﻓﺩﺧﻠﻧﺎ ﻋﻠﻰ ﺍﻟﻘﺎﻧﻭﻥ ﺍﻟﺗﺎﻧﻰ ﺑﺗﺎﻉ ﺍﻝ 4n = ﺍﻟﻣﻛﻭﻧﺔ ﻟﻠﺭﺍﺑﻁﺔ ﺑﺎﻯ ﻋﺩﺩ ﺻﺣﻳﺢn ﻟﻣﺎ ﻋﻭﺿﻧﺎ ﻁﻠﻌﺕ anti aromatic ﻳﺑﻘﻰ ﺧﻼﺹ ﺍﻟﻣﺭﻛﺏ ﺑﺗﺎﻋﻰ
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Aromatic , not , anti ﺗﻌﺎﻟﻰ ﻧﺟﻣﻊ ﺍﻟﻔﺭﻕ ﺑﻳﻥ ﺍﻝ Aromatic Not aromatic (non-aromatic) Anti Aromatic
cyclic, planar, completely conjugated compound with 4n + 2 π electrons. (stable) compound that lacks one (or more) of the requirements for aromaticity: being cyclic, planar, and completely conjugated. (less stable) cyclic, planar, completely conjugated compound with 4n π electrons. (very unstable)
Aromaticity increase stability
Dr\Ahmed Al3yde
10
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
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ﺍﻯ ﻣﺭﻛﺏ ﺍﺭﻭﻣﺎﺗﻰ ﺑﻳﻛﻭﻥ ﻋﻧﺩﻩ ﺛﺑﺎﺗﻳﻪ ﻋﺎﻟﻳﺔ .....ﻳﻌﻧﻰ ﺍﻟﻣﺭﻛﺑﺎﺕ ﺍﻟﺗﺭﻡ ﺩﻩ ﺛﺑﺎﺗﻳﺗﻬﺎ ﺍﻋﻠﻰ ﻣﻥ ﻣﺭﻛﺑﺎﺕ ﺍﻟﺗﺭﻡ ﺍﻻﻭﻝ ﻛﻠﻪ )ﺗﻔﺎﻋﻼﺕ ﺍﻟﺗﺭﻡ ﺍﻻﻭﻝ ﻣﺵ ﺗﻧﻔﻊ ﻣﻌﺎﻫﺎ( ﻭﺍﻧﺎ ﻓﻰ ﺍﻟﺟﺩﻭﻝ ﻓﺭﻗﺗﻠﻙ ﺑﻳﻥ ﺍﻝ ٣ﻓﻰ ﺍﻟﺛﺑﺎﺗﻳﻪ ﺍﻟﻣﺭﻛﺑﺎﺕ ﺍﻻﺭﻭﻣﺎﺗﻳﺔ ﺍﻋﻼﻫﻡ ﻓﻰ ﺍﻟﺛﺑﺎﺗﻳﻪ ﻭﺑﻌﺩﻫﺎ ﺍﻟﻣﺭﻛﺑﺎﺕ not aromaticﺫﻯ ﺍﻻﻟﻛﺎﻥ ﻭﺍﻻﻟﻛﻳﻥ ﻭﺍﻗﻝ ﺣﺎﺟﺔ ﻓﻰ ﺍﻟﺛﺑﺎﺗﻳﻪ ﻫﻰ ﺍﻝ anti aromaticﻋﻠﺷﺎﻥ ﻛﺩﻩ ﺑﻳﻘﻭﻟﻙ ﺍﻥ ﺍﻟﻣﻭﺍﺩ ﺩﻯ ﻣﻥ ﻛﺗﺭ ﻋﺩﻡ ﺍﻟﺛﺑﺎﺗﻳﻪ ﻣﺵ ﻣﻭﺟﻭﺩﺓ ﻻﻧﻬﺎ ﺑﺗﺗﻔﺎﻋﻝ ﻋﻠﻰ ﻁﻭﻝ
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ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
11
Dr\Ahmed Al3yde
Sp3 carbon
Not Aromatic ــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ
Aromaticity of ions • requirements : 1-Cyclic 2-Planar )3-Complete conjugation (sp2 hybride 4-Obey Huckel’s rule -
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ﺍﻻﺧﺗﻼﻑ ﻫﻧﺎ ﺑﻘﻰ ...ﺍﻣﺗﻰ ﺍﺣﺳﺏ ﺍﻟﺷﺣﻧﺔ ﻓﻰ ﻗﺎﻧﻭﻥ huckel ﺑﻛﻝ ﺑﺳﺎﻁﺔ ﻟﻭ ﺍﻟﺷﺣﻧﺔ ﺍﻟﺳﺎﻟﺑﺔ ﺩﺍﺧﻠﺔ ﻓﻰ ﺍﻝ resonanceﻣﻊ ﺍﻟﺣﻠﻘﺔ ﻳﺑﻘﻰ ﻫﺗﺣﺳﺏ ﺍﻟﺷﺣﻧﺔ ﺍﻟﺳﺎﻟﺑﺔ ﺏ ٢ﺍﻟﻛﺗﺭﻭﻥ ﻭﻟﻭ ﻣﺵ ﺩﺧﻠﺕ ﻓﻰ ﺍﻝ resonanceﻳﺑﻘﻰ ﻣﺵ ﻫﻧﺣﺳﺑﻬﺎ ... ﻁﺑﻌﺎ ﺩﻩ ﻋﻛﺱ ﻛﻼﻡ ﺗﺣﺩﻳﺩ ﻧﻭﻉ ﺍﻟﺗﻬﺟﻳﻥ ﻓﻰ ﺍﻟﺷﺣﻧﺔ ﺍﻟﺳﺎﻟﺑﺔ .....ﻛﻧﺕ ﺑﻧﻘﻭﻝ ﻟﻭ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﺩﺧﻠﺕ resonanceﻣﺵ ﺑﻧﺣﺳﺑﻬﺎ ﻓﻰ ﺗﺣﺩﻳﺩ ﻧﻭﻉ ﺍﻟﺗﻬﺟﻳﻥ ...ﺍﻥ ﺷﺎء ﷲ ﺗﻛﻭﻥ ﻓﺎﻛﺭ ﺍﻟﺗﻬﺟﻳﻥ ^_^ ﺗﻌﺎﻟﻰ ﻧﺎﺧﺩ ﻣﺛﺎﻝ ﻋﻥ ﺗﺣﺩﻳﺩ ﺍﻷﺭﻭﻣﺎﺗﻳﺔ ﻓﻰ ﺍﻟﻣﺭﻛﺏ ﻟﻠﻰ ﻋﻠﻳﻪ ﺷﺣﻧﺔ
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
٠١٠٢٦٢١٨٨٦١ 12
Dr\Ahmed Al3yde
2
1
ﺗﻌﺎﻟﻰ ﻧﻌﺭﻑ ﺍﻟﻔﺭﻕ ﺑﻳﻥ ﺍﻟﻣﺭﻛﺏ ١ﻭﺍﻟﻣﺭﻛﺏ ٢ ﻣﺭﻛﺏ ﻭﺍﺣﺩ ﺍﻟﻣﺭﻛﺏ ﺍﻟﻠﻰ ﻗﺩﺍﻣﻙ cyclic , planarﻭﺟﻣﻳﻊ ﺫﺭﺍﺗﻪ ﺗﻬﺟﻳﻧﻬﺎ Sp2 ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻣﺷﺗﺭﻛﺔ ﻓﻰ ﺍﻝ resonanceﻣﻊ ﺍﻟﺣﻠﻘﺔ ﻭﺫﻯ ﻣﺎ ﺍﺣﻧﺎﻋﺎﺭﻓﻳﻥ ﻣﻥ ﺍﻟﺗﺭﻡ ﺍﻻﻭﻝ ﺍﻥ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﺗﻣﺛﻝ ﺍﻟﻛﺗﺭﻭﻧﻳﻥ ﻋﻠﺷﺎﻥ ﻛﺩﻩ ﻭﺍﺣﻧﺎ ﺑﻧﺷﻭﻑ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻠﻰ ﻫﻧﻌﻭﺽ ﻓﻳﻬﺎ ﻓﻰ ﻗﺎﻧﻭﻥ huckelﻻﺯﻡ ﻧﺣﺳﺏ ﺍﻝ ٢ﺍﻟﻛﺗﺭﻭﻥ ﻟﻺﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻳﻌﻧﻰ ﻓﻰ ﺍﻟﻣﺭﻛﺏ ﻭﺍﺣﺩ ﻫﻧﻼﻗﻰ ﻓﻳﻪ ﺭﺑﻁﺗﻳﻥ ﺑﺎﻯ ....ﻳﻌﻧﻰ ٤ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ...ﻭﻧﺿﻳﻑ ﻋﻠﻳﻬﻡ ٢ﺍﻟﻛﺗﺭﻭﻥ ﺍﻟﺷﺣﻧﺔ ﺍﻟﺳﺎﻟﺑﺔ ....ﻳﺑﻘﻰ ﺍﻟﻣﺟﻣﻭﻉ ٦ ﻧﻌﻭﺽ ﻓﻰ ﻗﺎﻧﻭﻥ huckelﻟﻘﻳﻧﺎ nﻋﺩﺩ ﺻﺣﻳﺢ ...ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ ﺍﺭﻭﻣﺎﺗﻰﻣﺭﻛﺏ ٢ ﺍﻟﻣﺭﻛﺏ cyclic , planarﺟﻣﻳﻊ ﺫﺭﺍﺗﻪ ﺗﻬﺟﻳﻧﻬﺎ sp2 ﺍﻝ resonanceﺍﻟﻠﻰ ﻓﻰ ﺍﻟﺣﻠﻘﺔ ﺑﻳﺗﻡ ﻋﻥ ﻁﺭﻳﻕ ٣ﺭﻭﺍﺑﻁ ﺑﺎﻯ ...ﻭﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻣﺵ ﻣﺷﺗﺭﻛﺔ ﻓﻰ ﺍﻝ resonanceﺩﻩ . ﻳﺑﻘﻰ ﻣﺵ ﻫﻧﺣﺳﺏ ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻭﺍﺣﻧﺎ ﺑﻧﻌﻭﺽ ﻓﻰ ﻗﺎﻧﻭﻥhuckel ﻳﺑﻘﻰ ﻓﻳﻪ ٣ﺭﻭﺍﺑﻁ ﺑﺎﻯ .....ﻳﻌﻧﻰ ٦ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ﻁﻠﻌﺕ nﻋﺩﺩ ﺻﺣﻳﺢ ......ﻳﺑﻘﻰ ﻣﺭﻛﺏ ﺍﺭﻭﻣﺎﺗﻰﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
13
Dr\Ahmed Al3yde
ﺍﻭﻋﻰ ﺣﺩ ﻳﺗﻠﺧﺑﻁ ......ﻭﺍﻟﻠﻰ ﻳﺗﻠﺧﺑﻁ ﻳﻌﺭﻑ ﺍﻥ ﻟﻭ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻋﻠﻰ ﺫﺭﺓﻣﺭﺗﺑﻁﺔ ﺑﺭﺍﺑﻁﺔ ﺛﻧﺎﺋﻳﺔ ﻓﻣﺵ ﻫﻧﺣﺳﺏ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻟﻛﻥ ﻟﻭ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻋﻠﻰ ﺫﺭﺓ ﺟﻣﻳﻊ ﺭﻭﺍﺑﻁﻬﺎ ﺍﺣﺎﺩﻳﺔ ....ﻳﺑﻘﻰ ﻧﺣﺳﺏﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻓﻰ ﻗﺎﻧﻭﻥ huckel • ﺳﺅﺍﻝ ﺍﻣﺗﺣﺎﻥ ﻫﺎﻡ ﺟﺩﺍ Give reasonable explanation - The anion of benzene is aromatic although it ? contains total 8 free electrons
- Answer : the negative charge is found in Sp2 ࣊ orbital prependicular on the 2Pz orbitals of electrons of the double bonds , so can not enter in conjugation in ring ,so the number of ࣊ electrons inside the ring is still 6 , so obey huckel rule ﻳﻌﻧﻰ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﺑﺗﻛﻭﻥ ﻋﻣﻭﺩﻳﺔ ﻋﻠﻰ ﺍﻭﺭﺑﻳﺗﺎﻝ ) 2pzﻳﻌﻧﻰ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﺑﺗﻛﻭﻥ ﻓﻰ ﻧﻔﺱ ﻣﺳﺗﻭﻯ ﺫﺭﺍﺕ ﺍﻟﻛﺭﺑﻭﻥ ( ...ﻟﺫﻟﻙ ﻣﺵ ﺑﺗﻘﺩﺭ ﺗﺩﺧﻝ ﺍﻝ conjugationﺍﻭ ﺍﻻﻧﺗﻘﺎﻝ ﺍﻻﻟﻛﺗﺭﻭﻧﻰ ﺍﻟﻠﻰ ﻓﻰ ﺍﻟﺣﻠﻘﺔ ....ﻟﺫﻟﻙ ﻣﺵ ﺑﻧﺣﺳﺑﻬﺎ ﻭﺑﻳﻔﺿﻝ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺩﺍﺧﻝ ﺍﻟﺣﻠﻘﺔ ٦ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ...ﻟﺫﻟﻙ ﺍﻟﻣﺭﻛﺏ ﻳﺗﺑﻊ ﻗﺎﻧﻭﻥ huckelﻭﺑﻳﻛﻭﻥ ﺍﺭﻭﻣﺎﺗﻰ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﺑﻌﻳﺩﺓ ﻋﻥ ﺍﻝ conjugationﻭﻓﻰ ﻧﻔﺱ ﻣﺳﺗﻭﻯ ﺫﺭﺍﺕ ﺍﻟﻛﺭﺑﻭﻥ .....ﻳﺎ ﺭﻳﺕ ﻟﻭ ﺗﻌﺭﻓﻭﺍ ﺗﺭﺳﻣﻭﺍ ﺍﻟﺭﺳﻣﺔ ﻓﻰ ﺍﻻﻣﺗﺣﺎﻥ ﻟﻭ ﺟﺎﻟﻙ ﺍﻟﺳﺅﺍﻝ
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
14
2Pz Sp2
Dr\Ahmed Al3yde
-ﺗﻌﺎﻟﻰ ﻧﺎﺧﺩ ﻣﺛﺎﻝ ﻋﻠﻰ ﺍﻻﺷﺎﺭﺓ ﺍﻟﻣﻭﺟﺑﺔ
• ﺗﻌﺎﻟﻰ ﻧﻌﺭﻑ ﻟﻳﻪ ﺍﻟﻣﺭﻛﺏ ﻋﻧﺩﻙ cyclic , planarﺟﻣﻳﻊ ﺫﺭﺍﺗﻪ ﺗﻬﺟﻳﻧﻬﺎ Sp2 • ﺍﻻﺷﺎﺭﺓ ﺍﻟﻣﻭﺟﺑﺔ ﺗﻌﻧﻰ ﻧﻘﺹ ﻓﻰ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﻋﻠﺷﺎﻥ ﻛﺩﻩ ﺑﻧﻌﺗﺑﺭﻫﺎ ﻣﺵ ﻣﻭﺟﻭﺩﺓ ﻭﺍﺣﻧﺎ ﺑﻧﺷﻭﻑ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻠﻰ ﻫﻧﻌﻭﺽ ﺑﻳﻬﺎ ﻓﻰ ﻗﺎﻧﻭﻥ huckel • ﺍﻟﻣﺭﻛﺏ ١ﻋﻧﺩﻩ ﺭﺍﺑﻁﺗﻳﻥ ﺑﺎﻯ ......ﻳﻌﻧﻰ ٤ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ﻣﻛﻭﻧﻳﻥ ﻟﻬﺫﻩ ﺍﻟﺭﻭﺍﺑﻁ • ﺑﺎﻟﺗﻌﻭﻳﺽ ﻓﻰ ﺍﻟﻘﺎﻧﻭﻥ ﻫﺗﻼﻗﻰ nﻛﺳﺭ • ﻋﻠﻰ ﻁﻭﻝ ﻧﺩﺧﻝ ﻋﻠﻰ ﻗﺎﻧﻭﻥ ....... 4nﻟﻘﻳﻧﺎ nﻋﺩﺩ ﺻﺣﻳﺢ • ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ ﺑﺗﺎﻋﻰ anti-aromatic ﺗﻌﺎﻟﻰ ﻧﺎﺧﺩ ﺍﻣﺛﻠﺔ ﻟﻠﺗﺩﺭﻳﺏCyclo propene
ﺣﻠﻘﺔ ﻣﻥ ٣ﺫﺭﺍﺕ
Anti aromatic
Three membered ring
Aromatic
Not aromatic ﻻﻥ ﻓﻳﻪ ﺫﺭﺓ ﺗﻬﺟﻳﻧﻬﺎ sp3
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
15
Dr\Ahmed Al3yde
ﻁﺑﻌﺎ ﻓﻰ ﺍﻟﻣﺭﻛﺏ ﺍﻟﻠﻰ ﻋﻠﻰ ﺍﻟﻳﻣﻳﻥ ﺣﺳﺑﻧﺎ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ ﻻﻧﻬﺎ ﺩﺧﻠﺔ ﻓﻰﺍﻝ resonanceﻭﺍﻟﻣﺭﻛﺏ ﻋﻧﺩﻩ ﺭﺍﺑﻁﺔ ﺑﺎﻯ ﻭﺍﺣﺩﺓ .....ﻓﺎﻟﻣﺟﻣﻭﻉ ﻫﻳﻛﻭﻥ ٤ five membered ring
Cyclo pentadienyl anion
Cyclo pentadienyl cation
Cyclo pentadiene
Not aromatic
ﻓﻳﻪ ﻣﻠﺣﻭﻅﺗﻳﻥ ﻣﻬﻣﻳﻥ :• ﺍﻭﻻ :ﺍﻟﺷﻛﻝ ﺍﻟﻠﻰ ﺗﺣﺕ ﺩﻩ ﺍﻟﻠﻰ ﻫﻭ ﻋﺑﺎﺭﺓ ﻋﻥ ﺩﺍﻳﺭﺓ ﻭﺟﻭﺍﻫﺎ ﺍﺷﺎﺭﺓ ﺩﺍﺧﻝ ﺍﻟﻣﺭﻛﺏ ....ﻣﻌﻧﺎﻩ ﺍﻥ ﺍﻟﻣﺭﻛﺏ ﻳﺣﺗﻭﻯ ﻋﻠﻰ ﺍﺷﺎﺭﺓ ﺗﺗﺑﺎﺩﻝ ﻣﻊ complete conjugation ﺍﻟﺭﻭﺍﺑﻁ ﺍﻟﺛﻧﺎﺋﻳﺔ ﻓﻰ ﺍﻟﺣﻠﻘﺔ ﻣﻛﻭﻧﺔ conjugatio
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
16
Dr\Ahmed Al3yde
ﺍﻟﻣﻠﺣﻭﻅﺔ ﺍﻟﺗﺎﻧﻳﺔ ﻋﺑﺎﺭﺓ ﻋﻥ ﻣﻌﻠﻭﻣﺔ ﻋﻥ ﺍﻟﺣﻠﻘﺎﺕ ﺍﻟﺧﻣﺎﺳﻳﺔ metallocenes
Sandwich like compounds
They are compounds in which two cyclo pentadienylidiene ringsform sandwich around ametal ion .the most known of these is ferrocene ﻳﻌﻧﻰ ﺣﻠﻘﺗﻳﻥ ﺧﻣﺎﺳﻳﺗﻳﻥ ﻟﻣﺎ ﻳﺷﻭﻓﻭﺍ ﻣﻌﺩﻥ ﺑﻳﻌﻣﻠﻭﺍ ﺳﻧﺩﻭﺗﺵ ﻋﻠﻳﻪ )ﺑﻳﺭﺗﺑﻁﻭﺍ ﺑﻪ ( ﻳﻌﻧﻰ ﺫﻯferrocene ﻫﻳﺗﻛﻭﻥ ﻣﺭﻛﺏ ﺍﺳﻣﻪ... • ﻭﻟﻭ ﺍﻟﻣﻌﺩﻥ ﺩﻩ ﻋﺑﺎﺭﺓ ﻋﻥ ﺣﺩﻳﺩ ﻣﺎ ﻭﺍﺿﺢ ﻓﻰ ﺍﻟﺭﺳﻣﺔ
ferrocene
• It is stable compound because the two rings are freely rotate • The most stable form : staggered form
Dr\Ahmed Al3yde
17
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
Cyclo heptatriene
seven membered ring
Not aromatic
Tropylium cation
Tropylium anion
• ﺧﻠﻰ ﺑﺎﻟﻙ ﺍﻥ ﺍﻳﻭﻥ ﺍﻟﺣﻠﻘﺔ ﺍﻟﺳﺑﺎﻋﻳﺔ ﺍﺳﻣﻪ tropylium • ﻫﻧﺎ ﺑﺭﺩﻩ ﻓﻳﻪ ... metallocenesﻋﺑﺎﺭﺓ ﻋﻥ ﺣﻠﻘﺔ ﺳﺑﺎﻋﻳﺔ ﻣﻊ ﺧﻣﺎﺳﻳﺔ ﺣﻭﻟﻳﻥ ﻣﻌﺩﻥ ....ﺍﻋﺭﻑ ﺍﻟﻣﻌﻠﻭﻣﺎﺕ ﺩﻯ ﻋﻠﺷﺎﻥ ﻣﻣﻛﻥ ﺗﺗﺳﺄﻝ ﻓﻳﻬﺎ )ﻣﺵ ﺑﻌﻳﺩﺓ (
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
18
Dr\Ahmed Al3yde
metallocenes • Metallocenes that contain tropylium ion have been prepared recently ﻟﻠﺣﻠﻘﺔ ﺍﻟﺳﺑﺎﻋﻳﺔ ﻟﺳﻪ ﻣﺣﺿﺭﻳﻧﻪ ﺣﺩﻳﺛﺎ )ﺍﻛﺗﺷﻑmetalocenes • ﻳﻌﻧﻰ ﺍﻝ (ﺣﺩﻳﺛﺎ
M=metal
ــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ Eight membered ring
Cyclo octatetraene
ﻣﻬﻡ ﺟﺩﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍﺍ
Not aromatic !
ﻟﺳﺑﺑﻳﻥ ﻣﻬﻣﻳﻥ ﺟﺩﺍnot aromatic • ﺍﻟﻣﺭﻛﺏ ﺩﻩ 1- Not plannar (tube – like shape)
Tube – like shape Dr\Ahmed Al3yde
19
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
2- Not obey Huckel's rule • 4n+2=8 • n=1.5 • ﻁﺑﻌﺎ ﻣﺵ ﻳﻧﻔﻊ ﻫﻧﺎ ﻧﻘﻭﻝ ﺍﻟﻣﺭﻛﺏ anti aromaticﻻﻥ ﺍﺻﻼ ﺍﻟﻣﺭﻛﺏ non-planar • ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ ﺍﺻﻼ ﻏﻳﺭ ﻣﺳﺗﻭﻯ ﻭﻛﻣﺎﻥ ﻻ ﻳﺗﺑﻊ ﻗﺎﻧﻭﻥ huckel • ﺍﻛﺗﺷﻔﻭﺍ ﻁﺭﻳﻘﺗﻳﻥ ﻳﺣﻭﻟﻭﺍ ﺍﻟﻣﺭﻛﺏ ﺩﻩ ﻝ aromaticﺗﻌﺎﻟﻰ ﻧﺷﻭﻑ ﺍﺯﺍﻯ To be Aromatic )1- Reaction with potassium metal to obtain (dianion
• 2K
Dianion Aromatic, Stable , diatropic and plannar
1,3,5,7 tetramethyl cyclo octatetraene
ﻓﺎﻋﻠﻧﺎ ﺍﻟﻣﺭﻛﺏ ﻣﻊ ﺑﻭﺗﺎﺳﻳﻭﻡ ﻓﻧﺗﺞ ﻣﺭﻛﺏ ﻋﻠﻳﻪ ﺷﺣﻧﺗﻳﻥ ﺳﺎﻟﺑﺗﻳﻥ .....ﺗﺗﻭﻓﺭ ﻓﻳﻪﺍﻟﺧﻭﺍﺹ ﺍﻻﺭﻭﻣﺎﺗﻳﻪ -ﺗﻌﺎﻟﻰ ﻧﺷﻭﻑ ﺍﻟﻁﺭﻳﻘﺔ ﺍﻟﺗﺎﻧﻳﺔ
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
20
Dr\Ahmed Al3yde
2- By dissolving in conc.H2SO4 to obtain Homo tropylium ion
H+
Homo-tropylium ion • A proton adds to one of double bonds to form a homotropylium ion , and in this case the aromatic sextet is spread over seven carbons , as in tropylium ion • The eight carbon is Sp3 carbon and so can not take part in aromaticity ﺗﻡ ﺍﺿﺎﻓﺔ ﻫﻳﺩﺭﻭﺟﻳﻥ ﻟﻠﺭﺍﺑﻁﺔ ﺍﻟﻣﺯﺩﻭﺟﺔ... • ﻫﻧﺎ ﺑﻌﺩ ﻣﺎ ﺍﻟﻣﺭﻛﺏ ﺗﻔﺎﻋﻝ ﻣﻊ ﺍﻟﺣﻣﺽ ﻭﻛﺭﺑﻭﻧﻪ ﻭﺍﺣﺩﺓ ﺑﻌﻳﺩﺓ..... ﻛﺭﺑﻭﻧﺎﺕ ﺟﻧﺏ ﺑﻌﺿﻬﺎ٧ ﻓﺗﻛﻭﻥ ﺣﻠﻘﺔ ﺗﺣﺗﻭﻯ ﻋﻠﻰ.... ﻟﻠﺣﻠﻘﺔ ﺍﻟﺳﺑﺎﻋﻳﺔ ﻭﻁﺑﻌﺎtropylium ion ﻓﺎﻟﻣﺭﻛﺏ ﺑﻳﺗﺣﻭﻝ ﻛﺈﻧﻪ.... ﻋﻥ ﺍﻟﺣﻠﻘﺔ ﺩﻯ ﺍﺭﻭﻣﺎﺗﻳﻪ ﺫﻯ ﻣﺎ ﺍﺧﺩﻧﺎ
ـــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــــ nine membered ring
1,3,5,7 Cyclo nona-tetra-ene
Dr\Ahmed Al3yde
21
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
ﺳﺅﺍﻝ ﻣﻬﻡHow could 1,3,5,7 cyclo nonatetraene be converted into an aromatic substance ? . indicate the reactions that would be used and draw the structure of the starting material and te product Sp3 ﻻﻥ ﻓﻳﻪ ﺫﺭﺓ ﺗﻬﺟﻳﻧﻬﺎnot aromatic • ﻳﻌﻧﻰ ﺍﻟﻣﺭﻛﺏ ﺍﻟﻠﻰ ﻓﻭﻕ ﺩﻩ • ﺑﻳﻘﻭﻟﻙ ﻓﻰ ﺍﻟﺳﺅﺍﻝ ﺍﺯﺍﻯ ﺗﺧﻠﻳﻪ ﺍﺭﻭﻣﺎﺗﻰ ﻭﻭﺿﺢ ﺍﻟﺗﻔﺎﻋﻝ ﻣﻊ ﺭﺳﻡ ﺍﻟﻣﺎﺩﺓ ﻭﺍﻟﻧﺎﺗﺞ.... ﺍﻟﺩﺍﺧﻠﺔ • Answer : - By reaction with base
Base
Not aroma c has Sp3 carbon
Anion , aromatic , planar and
, not planar , and has 8 ࣊ electrons
contain 10 ࣊ electrons
ﻭﻟﻣﺎ ﻧﺧﻠﺹ ﺍﻯ ﻣﻭﺿﻭﻉ ﻫﻧﺯﻟﻛﻡ ﺍﺳﺋﻠﺔ ﻋﻠﻳﻪ ﺍﻥ ﺷﺎء ﷲ.... ﺩﻯ ﺍﺟﺎﺑﺔ ﺍﻟﺳﺅﺍﻝhetero atom ﻧﺩﺧﻝ ﻋﻠﻰ ﺟﺯﺋﻳﺔ ﺟﺩﻳﺩﺓ ﻭﻫﻰ ﺍﻻﺭﻭﻣﺎﺗﻳﺔ ﻓﻰ ﺍﻟﺣﻠﻘﺎﺕ ﺍﻟﻠﻰ ﻓﻳﻬﺎ-
Dr\Ahmed Al3yde
22
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
Hetero cyclic aromatic compounds ﺣﻠﻘﺔ ﺗﺣﺗﻭﻯ ﻋﻠﻰ ﺫﺭﺓ ﻧﻳﺗﺭﻭﺟﻳﻥ ﺍﻭ ﺍﻛﺳﺟﻳﻥ ﺍﻭ ﻛﺑﺭﻳﺕ ﺑﺟﺎﻧﺏ ﺍﻟﻛﺭﺑﻭﻥ ﻭﺍﻟﻬﻳﺩﺭﻭﺟﻳﻥ ...ﺍﺯﺍﻯ ﺍﻋﺭﻑ ﺍﻟﺣﻠﻘﺔ ﺍﻻﺭﻭﻣﺎﺗﻳﻪ ﻣﻥ ﻏﻳﺭﻫﺎ ؟ ﻧﻔﺱ ﺍﻟﻠﻰ ﻗﻭﻟﻧﺎﻩ ﺑﺎﻟﺿﺑﻁ ﻳﻌﻧﻰ ﻻﺯﻡ ﺍﻟﻣﺭﻛﺏ ﻳﻛﻭﻥ : Cyclic , planar , complete conjugation , obey huckel's rule • ﺍﻻﻫﻡ ﺑﻘﻰ ﺍﻣﺗﻰ ﺍﺣﺳﺏ ﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻠﻰ ﻋﻠﻰ ﺍﻟﺫﺭﺍﺕ ﺩﻯ • ﻗﺎﻟﻡ ﻧﻔﺱ ﻣﻭﺿﻭﻉ ﺍﻻﺷﺎﺭﺓ ﺍﻟﺳﺎﻟﺑﺔ • ﻟﻭ ﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺷﺎﺭﻙ ﻓﻰ ﺍﻝ conjugationﻳﺑﻘﻰ ﻫﻧﺣﺳﺑﻬﻡ ﻭﺍﺣﻧﺎ ﺑﻧﻌﺩ ﻋﺩﺩ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﻋﻠﺷﺎﻥ ﻧﻌﻭﺽ ﻓﻰ ﻗﺎﻧﻭﻥ huckel
pyrrol
-
ﻓﻰ ﺍﻝ pyrrolﻫﻧﻼﻗﻰ ﺍﻥ ﺍﻟﻧﻳﺗﺭﻭﺟﻳﻥ ﻋﻠﻳﻬﺎ ﺫﻭﺝ ﻣﻥ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ....ﻭﺍﻟﺯﻭﺝ ﺩﻩ ﺑﻳﺷﺎﺭﻙ ﻓﻰ ﺍﻝ conjugationﺍﻟﻠﻰ ﻓﻰ ﺍﻟﺣﻠﻘﺔ ﻳﺑﻘﻰ ﻫﻧﺣﺳﺏ ﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺩﻭﺍ +ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻣﻛﻭﻧﺔ ﻟﺭﻭﺍﺑﻁ ﺑﺎﻯ ﻫﻧﺎ ﻓﻳﻪ ﺭﺍﺑﻁﺗﻳﻥ ﺑﺎﻯ ﻳﺑﻘﻰ ﻓﻳﻪ ٤ﺍﻟﻛﺗﺭﻭﻧﺎﺕ + ......ﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﺣﺭﺓ ﺍﻟﻠﻰ ﻋﻠﻰ ﺍﻟﻧﻳﺗﺭﻭﺟﻳﻥ ......ﻳﺑﻘﻰ ﺍﻟﻣﺟﻣﻭﻉ ٦ ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ aromaticﻻﻧﻪ ﺗﺗﻭﻓﺭ ﻓﻳﻪ ﻛﻝ ﺍﻟﺷﺭﻭﻁ
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
23
Dr\Ahmed Al3yde
oﺍﻣﺎ ﻓﻰ ﺍﻝ pyridine
N ﻫﻧﻼﻗﻰ ﺍﻥ ﺍﻝ resonanceﺍﻭﺍﻝ conjugationﺍﻟﻠﻰ ﻓﻰ ﺍﻟﺣﻠﻘﺔ ﺑﻳﺗﻡ ﻋﻥ ﻁﺭﻳﻕ ٣ﺭﻭﺍﺑﻁ ﺑﺎﻯ ....ﻭﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻠﻰ ﻋﻠﻰ ﺍﻟﻧﻳﺗﺭﻭﺟﻳﻥ ﻟﻡ ﻳﺷﺎﺭﻛﻭﺍ ﻓﻰ ﺍﻝ resonanceﻳﺑﻘﻰ ﻣﺵ ﻫﻧﺣﺳﺏ ﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﺛﻧﺎء ﺍﻟﺗﻌﻭﻳﺽ ﻓﻰ ﻗﺎﻧﻭﻥ huckel ﻳﺑﻘﻰ ﺑﺭﺩﻩ ﻓﻳﻪ ٣ﺭﻭﺍﺑﻁ ﺑﺎﻯ ...ﻳﺑﻘﻰ ٦ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ ﺗﺗﻭﻓﺭ ﻓﻳﻪ ﻛﻝ ﺍﻟﺷﺭﻭﻁ ...ﻭﻁﺑﻌﺎ ﺍﻟﻣﺭﻛﺏ ﺍﻟﻠﻰ ﻓﻭﻕ ﻭﺍﻟﻣﺭﻛﺏﺩﻩ ﻛﻝ ﺫﺭﺍﺗﻬﻡ ﺗﻬﺟﻳﻧﻬﺎ Sp2 -ﻭﺩﻯ ﺻﻭﺭﺓ ﺗﻭﺿﺣﻠﻙ ﺍﺯﺍﻯ ﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺑﺭﻩ ﺍﻝ conjugation
• ﻁﻳﺏ ﻟﻭ ﺑﺩﻝ ﺍﻟﻧﻳﺗﺭﻭﺟﻳﻥ ﻓﻳﻪ ﺍﻛﺳﺟﻳﻥ ﺍﻭ ﻛﺑﺭﻳﺕ ﺍﻟﻠﻰ ﻋﻧﺩﻫﻡ ﺯﻭﺟﻳﻥ ﻣﻥ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﺣﺭﺓ
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
24
Dr\Ahmed Al3yde
-
-
S
O
Thiophene
Furan
ﻫﻧﺎ ﻛﻝ ﺫﺭﺓ ﻣﻥ ﺍﻻﻛﺳﺟﻳﻥ ﺍﻭ ﺍﻟﻛﺑﺭﻳﺕ ﻋﻠﻳﻬﻡ ﺯﻭﺟﻳﻥ ﻣﻥ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﺣﺭﺓ ﻓﻳﻪ ﺯﻭﺝ ﻣﻧﻬﻡ ﻫﻳﺷﺎﺭﻙ ﻓﻰ ﺍﻝ conjugationﻭﺯﻭﺝ ﺗﺎﻧﻰ ﻣﺵ ﻫﻳﺷﺎﺭﻙ ..ﻟﺫﻟﻙ ﻫﻧﺣﺳﺏ ﺯﻭﺝ ﻭﺍﺣﺩ ﺑﺱ ﻣﻊ ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ﺑﺎﻯ ﻋﻠﺷﺎﻥ ﻧﻌﻭﺽ ﻓﻰ ﻗﺎﻧﻭﻥ huckel ﻳﻌﻧﻰ ﻛﻝ ﻣﺭﻛﺏ ﻓﻳﻪ ﺭﺍﺑﻁﺗﻳﻥ ﺑﺎﻯ ٤ ......ﺍﻟﻛﺗﺭﻭﻧﺎﺕ .....ﻣﻊ ﺯﻭﺝ ﻣﻥ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ......ﻳﺑﻘﻰ ﺍﻟﻣﺟﻣﻭﻉ ٦ ﻳﺑﻘﻰ ﺍﻟﻣﺭﻛﺏ Aromatic
ﻣﻠﺣﻭﻅﺔ ﻫﺎﻣﺔ : Aromaticity
ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
Electronegativity
25
Dr\Ahmed Al3yde
ﻳﻌﻧﻰ ﻟﻭ ﻫﻧﺭﺗﺏ ﺍﻟﻣﺭﻛﺑﺎﺕ ﺍﻟﻠﻰ ﻓﻭﻕ ﻋﻠﻰ ﺣﺳﺏ ﺍﻝ aromaticity ﻫﻧﻼﻗﻰ ﺍﻥ in aromaticity
Thiophene > pyrrol > furan
ﺍﻧﺎ ﻋﻣﻠﺗﻠﻛﻡ ﺗﺭﺗﻳﺏ ﻣﺧﺗﻠﻑ ﻋﻥ ﺍﻟﺩﻛﺗﻭﺭﺓ ﺷﻭﻳﺔ ﻭﻓﻳﻪ ﺣﺎﺟﺎﺕ ﺫﻯ ﺍﻝ annuleneﻣﺵ ﻗﻠﺗﻬﺎ ﺩﻟﻭﻗﺗﻰ ....ﻣﺵ ﺗﻘﻠﻕ ﻛﻝ ﻛﻠﻣﺔ ﺍﻟﺩﻛﺗﻭﺭﺓ ﺷﺭﺣﺗﻬﺎ ﻫﻘﻭﻟﻬﺎ ﻟﻛﻥ ﻓﻰ ﻭﻗﺗﻬﺎ ....ﺍﻧﺎ ﻣﺵ ﻫﺯﻭﺩ ﻋﻥ ﻛﺩﻩ ﻭﻫﺩﻳﻠﻙ ﺷﻭﻳﺔ ﺍﻣﺛﻠﺔ ﻋﻠﺷﺎﻥ ﺗﺛﺑﺕ ﺍﻟﻠﻰ ﺍﺧﺩﻧﺎﻩ ﺍﻟﻧﻬﺎﺭﺩﻩ ﺩﻩ ﺑﺱ
N
N
ﻓﻰ ﺍﻟﻣﺛﺎﻝ ﺩﻩ ....ﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻠﻰ ﻋﻠﻰ ﺍﻟﻧﻳﺗﺭﻭﺟﻳﻥ ﻣﺵ ﺷﺎﺭﻙﻓﻰ ﺍﻝ ) resonanceﻭﻗﻠﺗﻠﻙ ﻣﻣﻛﻥ ﺗﻌﺭﻓﻬﺎ ﻟﻭ ﻓﻳﻪ ﺭﺍﺑﻁﺔ ﺛﻧﺎﺋﻳﺔ ﻟﻠﻧﻳﺗﺭﻭﺟﻳﻥ( ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
26
Dr\Ahmed Al3yde
ﻟﻛﻥ ﺯﻭﺟﻳﻥ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻟﻠﻰ ﻋﻠﻰ ﺍﻻﻛﺳﺟﻳﻥ ....ﺷﺎﺭﻙ ﻣﻧﻬﻡ ﺯﻭﺝﻭﺍﺣﺩ ﻓﻰ ﺍﻝ conjugation ﻳﺑﻘﻰ ﻛﺩﻩ ﺭﺍﺑﻁﺗﻳﻥ ﺑﺎﻯ +ﺯﻭﺝ ﺍﻟﻛﺗﺭﻭﻧﺎﺕ ﺍﻻﻛﺳﺟﻳﻥ .....ﻳﺑﻘﻰ ﻛﻠﻪ ٦ ....ﻳﺎﺭﺏ ﺗﻛﻭﻥ ﺍﺗﻔﻬﻣﺕ
ﻫﻧﺎ ﺍﻟﻧﻳﺗﺭﻭﺟﻳﻥ ﺟﻣﻳﻊ ﺭﻭﺍﺑﻁﻪ ﺍﺣﺎﺩﻳﻪ ﻓﺯﻭﺝ ﺍﻻﻟﻛﺗﺭﻭﻧﺎﺕ ﺷﺎﺭﻙ ﻓﻰ ﺍﻝ ٤ + conjugationﺭﻭﺍﺑﻁ ﺑﺎﻯ
Anti Aromatic
• ﻛﻔﺎﻳﺔ ﻋﻠﻳﻛﻡ ﻛﺩﻩ ﺍﻟﻧﻬﺎﺭﺩﻩ • ﻭﺍﻥ ﺷﺎء ﷲ ﻧﺧﻠﺹ ﺍﻟﻣﻭﺿﻭﻉ ﺩﻩ ﻣﻊ ﺍﻻﺳﺋﻠﺔ ﺍﻟﻣﺣﺎﺿﺭﺓ ﺍﻟﻠﻰ ﺟﺎﻳﺔ ﻭﻧﺩﺧﻝ ﻋﻠﻰ ﺍﻟﺑﻧﺯﻳﻥ ﻭﺗﻔﺎﻋﻼﺗﻪ ....ﺩﻣﺗﻡ ﻓﻰ ﺭﻋﺎﻳﺔ ﷲ ...ﻭﺫﺍﻛﺭﻭﺍ ﻛﻭﻳﺱ
ﻛﻭﺭﺱ ﺍﻟﻌﺿﻭﻳﺔ ﺍﻟﺳﺑﺕ ﻭﺍﻟﺛﻼﺛﺎء ﺍﻟﺳﺎﻋﺔ ١ﻭﺍﻟﺳﺎﻋﺔ ٢:٣٠ ﺳﻧﺗﺭ ﺍﻟﺟﺎﻣﻌﺔ ﺃﺣﻣﺩ ﺍﻟﻌﺎﻳﺩﻯ
27
Dr\Ahmed Al3yde