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26.
∠CBE = ∠BAD = 44° because they are corresponding angles ∠DBE and ∠CBE are complementary so ∠DBE + ∠CBE = 90° ∠DBE = 90° − ∠CBE ∠DBE =90° − 44° ∠DBE = 46° 27. 44° because they are corresponding angles ∠EDF = ∠BAD = Angles ∠ADB, ∠BDE , and ∠EDF make a straight angle ∠ADB + ∠BDE + ∠EDF =180° ∠ADB = 180° − ∠BDE − ∠EDF ∠ADB = 180° − 90° − 44° 46° ∠ADB = ∠DFE = ∠ADB because they are corresponding angles ∠DFE = 46°
28. ∠ADE = ∠ADB + ∠BDE
∠ADB = 46° (see Question 27) ∠BDE = 90° ∠ADE =46° + 90° ∠ADE = 136° 29. Using Eq. (2.1), a 3.05 = 4.75 3.20 3.05 = a 4.75 ⋅ 3.20 a = 4.53 m 30. Using Eq. (2.1), 3.05 b = 6.25 3.20 3.05 = b 6.25 ⋅ 3.20 b = 5.96 m 31. Using Eq. (2.1), c 5.05 = 3.20 4.75 (3.20)(5.05) c= 4.75 c = 3.40 m
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