Type:
Test Bank
Resource:
Vector Mechanics for Engineers, Statics and Dynamics
Edition:
12th Edition
Author(s):
Ferdinand P. Beer E. Russell Johnston David Mazurek
Chapter 2 Computer Problems 2.C1 Write a computer program that can be used to determine the magnitude and direction of the resultant of n coplanar forces applied at a point A. Use this program to solve Probs. 2.32, 2.33, 2.35, and 2.38. Fi
F1
θi θ1
θn
x A
Fn
Fig. P2.C1
2.C2 A load P is supported by two cables as shown. Write a computer pro-
gram that can be used to determine the tension in each cable for any given value of P and for values of θ ranging from θ1 = β − 90° to θ2 = 90° − α, using given increments ∆θ. Use this program to determine for the following three sets of numerical values (a) the tension in each cable for values of θ ranging from θ1 to θ2, (b) the value of θ for which the tension in the two cables is as small as possible, (c) the corresponding value of the tension:
A
(1) α = 35°, β = 75°, P = 400 lb, ∆θ = 5° (2) α = 50°, β = 30°, P = 600 lb, ∆θ = 10° (3) α = 40°, β = 60°, P = 250 lb, ∆θ = 5°
β
C θ
2.C3 An acrobat is walking on a tightrope of length L = 20.1 m attached to
supports A and B at a distance of 20.0 m from each other. The combined weight of the acrobat and his balancing pole is 800 N, and the friction between his shoes and the rope is large enough to prevent him from slipping. Neglecting the weight of the rope and any elastic deformation, write a computer program to calculate the deflection y and the tension in portions AC and BC of the rope for values of x from 0.5 m to 10.0 m using 0.5-m increments. From the data obtained, determine (a) the maximum deflection of the rope, (b) the maximum tension in the rope, (c) the smallest values of the tension in portions AC and BC of the rope. A
B α
P
Fig. P2.C2
B
y C
x 20.0 m
Fig. P2.C3
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04_bee77102_Ch02_p001-002.indd 1
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2.C4 Write a computer program that can be used to determine the magni-
tude and direction of the resultant of n forces Fi, where i = 1, 2, . . . , n, that are applied at point A0 of coordinates x0, y0, and z0, knowing that the line of action of Fi passes through point Ai of coordinates xi, yi, and zi. Use this program to solve Probs. 2.93, 2.94, and 2.95.
A2(x2, y2, z2)
A1(x1, y1, z1)
y
F2
F1 A0(x0, y0, z0) Fn
O
x
Fi z
An(xn, yn, zn)
Ai(xi, yi, zi)
Fig. P2.C4
2.C5 Three cables are attached at points A1, A2, and A3, respectively, and are
connected at point A0, to which a given load P is applied as shown. Write a computer program that can be used to determine the tension in each of the cables. Use this program to solve Probs. 2.102, 2.106, 2.107, and 2.115.
y
A2(x2, y2, z2)
A3(x3, y3, z3)
O
A1(x1, y1, z1) A0(x0, y0, z0) x
P AP(xP, yP, zP)
z
Fig. P2.C5
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2
04_bee77102_Ch02_p001-002.indd 2
3/13/18 7:54 AM
I Z.Cz I
\ t ,t Fr,.,,,\ ar..- r'1
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lrc-\I" |
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D A r n 0 F P R ob 5 , | 7,32,2,33,1,,25,An/D | L,3D. I
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= Z f ti c a 0 ; , L=:
*_
'Y d = f , f i s- i n 0 & L--t
Lg.TeI
,Ar{r r ucH Trt+T
g^ . e=h6'3 -6-
rErrsroN (,)1,,. l ftfTb ) t ' b N D r H c r w _ z r , . - 1 < oP.=- ,q 4^of o 4T,a o 5 : Ao=5' l f( tr))X X:=3Sf ,f , Pl ?: 1=5715 1
.-.:,|fvnaisrs
Yftu)e "aanE9 av eo. (:J |i""ffi-q -qoo-< +10",
lF R^?o ArtD RSZo t
On-=O,
rc_fr2or+ilt fr,<o:
0o= sto"1fi ( f) I
tF en<ot
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r
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Data
of
Ptob.
f trtv;2furY
lrc,utS,"^/
2'32
|
Nudberofforcee:N=3
-tu-
t{
(+PA \P "t*''{
'-' o) ' (q+ i>Q\- cu._
0 t'\ I
l t n u t t rut ? i xt'".-v tF1 |
FKoetq|4 autRfi
,vc |
-TT--
h= rat+t*i+il
QuTtrttEaFPR06R.AM
rRrn^,612 FoRcE
or C
Trlatt, t'rr I i.^-
$=
'Ac
?
-
_-'r*.
;m+D-
1-
(ftLH f*< . T + srfnLl^ flE t/5 J fH ?ncc LckgLq rt)Lq
-.1
= 311.05 a""t.."
-l ll
Data of Prob . 2 .35 Numberofforcee:N=3
...
resulCant
ahd
x axi6
Data of prob. 2.38 NumberofforceE:N=3 Force and.angle (F, TH)? 50,20
F o r c ea n da n 6 t e ( r , r n l r a o , g s
F o r c e a n d a n-i r e i r , s r i i i i o l i R e s u l u a n t2oL,915
-a -i
d
/rvc(E4Evr56e
o, Tac,-ra5-, I ct+Ectr i-ug: ti+.at T*" *t'tt-rscfiA€Fq,lat h'rii T ^ t l AO- t t. | A - /( t . \ FDp' F'a<)' i
n'Nt4\}rt
I tQocearq ourerlr | I
Force and angle (F, Tn)? 200,215 Force and angle (F, TH)? 150,295 TH)? 100,325 tnt. Lve,r.J and angLe lForce orce anq alrgle t(F, t, = 266.55
AND +. . qU-X
| ffiJ#:H.-;#;'i::*#:16
ii{ iiiir eo,roo
54..931 ReaulEanE= Angle bervreen reFurranr and x axie
between
t-
'TH U{t{Eru]14 =7.L.,-.., flT iS, vt *E,Ap-0: c{+O , g= F
I
=, riffi.:,";'?:i"3;,? " ;:::: :13llSi:[X;Tfi]l33;31"
Angle
'eoss|
fI\r
COH?UTE O,;(S-?O*
ffi;;;i;
Tgc
"*G:il'Efq+ol
oF ?(beRAM l:::::13:1313 ll: Tilili!;i9. | ou-r.LrNr iAngle : * i .betsween : I e F Ire8uLtant ; , j : i . * iand z r ix oaxie , u s= { |e4-69 f f i t deSrees{l voV&luElFa,P,qNo
;;;;
ts hg
5 t t { t tK l t? o s E r o L E
(a) f;,W t3:$" ft:2i;,,rr:2'!r't,: ltz) rsr ll'
ttrE rrl+vE R={ffi ,+r{r ^ * 8E T*+E
Y2-...1'r
| v
|
\\il
I | I
""'"""{l | | |
|
-Al iI |
Ansle between resurtant andxaxie! 33'23 aesreee<ll(b)
geENo.l
mgle ALPltlt = 35 ,lngle BETA = 75 Magnitude a!,srLuss vof r rload vaq 4O0 rP --
':::::'*"'_l:*=: THETA
-15.ooo _10.000 -5'000
TAB
TAE
_o.ooo 4oo.ooo 37.100 385.?89 73'9L7 36A'642
9 1 41s9..51818?:31296.. 90 9 s ..o9o9o9 1 8 3? 10.000 179.895 300.995
s> il,ili tii.ii| ii,i,ii| { 30,000 300.995 L79.896 35.000 40.000 45.000 50.000 55.000
326.083 348.689 368. 642 385.789 400.000
al
145.588 :.tO.L72 73 .9]-7 37.100 -0.000
continued Copyright © McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior written consent of McGraw-Hill Education.
2.C3continued
2.C2continued
fM, flNy l-,'
Set No.2 Angle ALPHA = 50 Angle BETA : 30 Magnit,ude of load P = 500 of THETA = L0 Increment TI{ETA
TAB
-0.000 105.795 2 0 8. 3 7 8 304.628 39L.622 -10.ooo 46G.7L7 0 . 0 0 0 527 .63L 1 0 . 0 0 0 572.5L3 20.000 600.000 3 0 . 0 0 0 609.256 40.000 600.000
-60.000 -50.000 -40.000 -30.000 -20.000
(b)@>
( b)b \ '-
'
TAB
-30.000 -0.000 22.L25 25.000 -20.000 44.o82 -15.000 55.703 -10.000 . 86.824 -5.000 Lo?.284 0.000 L26.928 5.000 L45.505 10. ooo t63.L76 .15.000 179.504 20.000 L94.465 25.000, 207.947 2 L 9. 8 4 6 30.000 230.o72 35.000 2 38.547 40.000 4.5.000 245.247 s0.000 250.000
Ac+cg = L
\fi:+b"- +t/14-rffi
=L
TAC 500.000 6 0 9. 2 5 6 500.000 572.5L3 527.53L 466.7L7 39L .622 304 .628 208.378 L05.796 -0.000
(a-z)- + ? C at- 2,qr+,tY{'
2/ tm'
{
(c)
= I^t t z.qJL- &
4 t" ( z'+5') = (-{-'+ ?a7 -a")" {f-( - 4 L'x" 4L"1"=(/-o+2a2
( r)
?t='
t
eL ALso: ( : tac{'(#\
/3:h;;'ff)
\,d.'
' Set, No. 3 engle ALPHA = 40 Angle BETA = 50 Magnit,ude of load P = 25A Increment of THETA = 5 THETA
B
;7
F . B , D r f t G " R A0rrt \ C l
i*v?'
70Rff TT td r-f. LE.'
(a+P) t-n,/ oF 5r vEs,' Tt, = Tac : u/
J-W ,frv
TAC 250.000 245.207 238 .547 230 .072 2L9.846 207 .947 1 , 9 4. 4 6 5 L79. 504
sfnf\
Jio{
-Ttlr s: Tr=r,v ;-f.,ffil Tor=ruffi;
ieg.iic 4C) 145.606 L26 .928 LO'l.284 86.824 65 .703 44 .082 22 . L25 -0..oqo
f /, i*l AgI:Lj ?_!f . PLo-6 ENTER Q= 2O n, /-='7A,I m, T0
FOA /=0,5 Co*1?u1e $ -t
C n tt P u ' rE C0l4 PuTc
(e)
q
lO,l
uitr.f6
Sin(4*
(s)
tV= BOO^/ O,5 sT E?5
FQortrfA.(r) FRoi.lFA5.(Z) A uof
Tsa A N D
Tsc trco^1 .51,ls.(3)
our PU-' BSoOnr-rnn
20.0 nr
-G r v E h l ;
A F V 6 Tt + O F R O P E= t - : 2 D , l n D I S I A N C FS e T W € P U A n u s I = Q , = ? O n t+T 0F ACRu$f e tlD 5A unrJct tJG eoLi'= W. BOOt'l Vr/Et6 loil f\ ssv t4E Nu strTn v a AND No E L*srrc DEF0prtlD-r 0F n,nPE F - INP:
XY 0.5 1.0 1.5 , 2.0 2.s 3 .0 3. s 4.0 4.5 5.0 s. s 6.0 6. s 7.0 7.5 8.0 8.5 9.0 9.5 10.0
TAC TBC 0.327 1426.03 LL93.97 0.446 1867.,33 L706.L4 0.534 2205 . 66 2.07I .69 2482 .42 0.605 2377 .4 8 27L7.45 2627.65 0.666 ' 0 .7r.8 29L9.79 2842.03 0.754 3096 . 14 302e .22 0 . 8 0 3 , 3250 .74 3191 . 13 0.838 3386.57 3334.19 0.859 3505.79 3459.85 0.895 3610.06 3559.95 0.919 3700.6s 3665.90 0..939 3778.51 3748.76 0.955 384.4.,45 39X9.40 0.970 3899.06 3878.49 0.981 3942,8L 3925.55 0. 990 3976.44 - 3953,.9s 0.995 3999.07 3991..05 1.000 40L2.00 4009.ot, 1.001 40L4.97 +O]-+.91
@,) lurAxtt|vt"lDe F L EcT,orN".Un = LO}l ftt
A L u zIsr(b) ^ N D T F { S I o x s}, r l ? vvALuEs I4AX|MOM4 " r E N s l o N DEFr€crreN6 ^ND-rE{sruxs 4 . 4 NANDTBc e T ^ , tuR | l ; M n X ' ^ 4 D rTENSI0N: -T -'T - b,O I K,V 0 F , ? R o t 40 , 5 m ' t o t 0 , 0 f i l , r l s r N i Q i - m - i * c t e N e r . r rIl 'Rc- 'g'c' F|P L:[g,0ra: FRuM DftrA og TA I r.rEg A LV Ff N' (e) tl44xlmur\A-DEFLEC-ir bN cr Ro eg ( b ) t t 4 4 x t r L t u pTt E N s l o N l N R O f F
dj
C ) 5 ^ ' tA L L T S TV A L U E S o F T + . A r v D b
s v A L L E s Tv A L u E so F T n c P s / oU .
continued
f o n { = o , 5 n:
TAr=1,4?,6AN -T-
l8c-
l , F t +( t /
{
4
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