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Solutions Manual for Calculus An Applied Approach Brief 9th Edition by Ron Larson

Page 1

SOLUTION MANUAL

SOLUTION MANUAL


Solutions to Tech Tutors

757

Solutions to

T E C H T U T O R S Chapter 1 Section 1.3 (page 29) The lines appear perpendicular in the setting − 9 ≤ x ≤ 9 and − 6 ≤ y ≤ 6.

Section 1.6 (page 61) Most calculators set in connected mode will join the two branches of the graph with a nearly vertical line near x = 2. This line is not part of the graph.

Chapter 4 Section 4.5 (page 287) Answers will vary.

Chapter 6 Section 6.3 (page 395) 1.46265

Chapter 8 Section 8.4 (page 537) Answers will vary.

Section 8.5 (page 546) Answers will vary.

Chapter 11 Section 11.3 (page 676) y = x 2 (ln x + 1)

© 2013 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.


CONTENTS Chapter 1

Functions, Graphs, and Limits ............................................................... 1

Chapter 2

Differentiation.......................................................................................66

Chapter 3

Applications of the Derivative ...........................................................145

Chapter 4

Exponential and Logarithmic Functions ...........................................247

Chapter 5

Integration and Its Applications.........................................................309

Chapter 6

Techniques of Integration ..................................................................367

Chapter 7

Functions of Several Variables ..........................................................416

Chapter 8

Trigonometric Functions....................................................................497

Chapter 9

Probability and Calculus ....................................................................548

Chapter 10

Series and Taylor Polynomials ..........................................................580

Chapter 11

Differential Equations ........................................................................646

Appendix A

Precalculus Review ............................................................................683

Appendix B

Alternate Introduction to the Fundamental Theorem of Calculus ..........................................................................................700

Checkpoints .............................................................................................................704 Tech Tutors .............................................................................................................757


APPENDICES Appendix A A Precalculus Review ........................................................................684 A.1

The Real Number Line and Order .....................................................684

A.2

Absolute Value and Distance on the Real Number Line..................686

A.3

Exponents and Radicals .....................................................................689

A.4

Factoring Polynomials........................................................................691

A.5

Fractions and Rationalization.............................................................696

Appendix B

Alternative Introduction to the Fundamental Theorem of Calculus ..........................................................................................700

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A P P E N D I X A A Precalculus Review Section A.1 The Real Number Line and Order 1. Because 0.25 = 14 , it is rational.

x−2 < 2 4 0 < x−2 < 8

13. 0 <

2. Because −3678 = − 3678 , it is rational. 1

2 < x < 10

3π 3. Because π is irrational, is irrational. 2

4. Because

(b) No, if x = 10, then x is not less than 10. (c) No, if x = 0, then x is not greater than 2.

2 is irrational, 3 2 − 1 is irrational.

5. Because 4.3451 has a repeating decimal expansion, it is rational. 6.

(a) Yes, if x = 4, then 2 < x < 10.

3− x ≤1 2 −2 < 3 − x ≤ 2

14. −1 <

22 is rational. 7

−5 < − x ≤ −1 5 > x ≥ 1 or 1 ≤ x < 5

7. Because 3 64 = 4, it is rational.

(a) No, if x = 0, then x is not greater than or equal to 1.

8. Because 0.8177 has a repeating decimal expansion, it is rational. 9. Because 60 is not the cube of a rational number, 3 60 is irrational.

(b) Yes, if x = 1, then 1 ≤ x < 5. (c) No, if x = 5, then x is not less than 5. 15.

10. Because e is irrational, 2e is irrational.

x−5 ≥ 7

16.

1 2x 2

(a) Yes, if x = 3, then x = 3 = 15 is greater than 12 . 5 5

x −2

−1

0

1

2

4x + 1 < 2x

17.

4x + 1 − 2x − 1 < 2x − 2x − 1 2 x < −1

( ) < 12 (−1)

1 2x 2

24 . = 10

x < − 12

x 12. x + 1 < 3 3x + 3 < x

− 12 x −2

2x + 3 < 0 3 2

18.

0

1

2

2x + 7 < 3 2 x < −4

( ) < 12 (−4)

1 2x 2

3 (b) No, if x = 4, then x is not less than − . 2 3 (c) Yes, if x = −4, then x is less than − . 2

−1

2x + 7 − 7 < 3 − 7

3 (a) No, if x = 0, then x is not less than − . 2

684

16

3 2

1 3 2

25 is greater than (c) Yes, if x = 52 , then x = 52 = 10

x < −

14

x > 32

than 12 . 5

12 5

12

2x > 3

( )> ()

x > 12 5

(b) No, if x = −3, then x = −3 = − 15 is not greater 5

10

x ≥ 12

11. 5 x − 12 > 0 5 x > 12

x

x −5+5 ≥ 7+5

x < −2 x −6

−4

−2

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Section A.1 4 − 2 x < 3x − 1

19.

26.

4 − 2 x − 4 − 3x < 3x − 1 − 4 − 3x −5 x < −5 − 15 ( −5 x) > − 15 ( −5)

The Real Number Line and Order

x x − > 5 2 3 x⎞ ⎛x 6⎜ − ⎟ > 6(5) 3⎠ ⎝2

685

x −10

0

10

20

30

40

0

1

50

3 x − 2 x > 30

x >1

x > 30 x

−2

0

2

x − 4 ≤ 2x + 1

20.

2x2 − x − 6 < 0

(2 x + 3)( x − 2) < 0

x − 4 − x − 1 ≤ 2x + 1 − x − 1 −5 ≤ x

21.

−2

−4 < 2 x − 3 < 4

− 12

7 2

−2

0

2

4

x

−3

−2

−1

0

1

2

3

3 4

1 4 x

x + 1 − 1 > 14 − 1

−1

2

3

4

5

(

) ( 12 , 4), and

x = 4. By testing the intervals −∞, 12 ,

29. Let E represent the earnings per share, in dollars. Then 4.1 ≤ E ≤ 4.25.

31. Let p represent the percent of Americans who conduct banking transactions online. Then p ≤ 40. x

−3

−2

−1

0

1

2

32. Let I represent the net income, in millions of dollars. Then I ≥ 239.

3

33. A = 20 and r = 220 − A = 200. Let T be the target heart rate. Then

−3 < − x < 3 3 > x > −3

(0.60)( 200) ≤ T ≤ (0.90)(200) x 4

6

8

120 ≤ T ≤ 180 So, the target heart rate for a 20-year-old is between 120 beats per minute and 180 beats per minute.

3 x + 2 x > 30

34. C = 0.35m + 2500 < 13,000

5 x > 30

0.35m < 10,500

1 1 (5 x) > (30) 5 5 x > 6

1

30. Let p represent the daily oil production, in millions of barrels. Then 2 < p < 2.4.

− 34 < x < − 14

x x 25. + > 5 2 3 ⎛ x⎞ ⎛ x⎞ 6⎜ ⎟ + 6⎜ ⎟ > 6(5) ⎝ 2⎠ ⎝ 3⎠

0

0

1 2

− 14 > x > − 43

x <1 3 ⎛ x⎞ 3( −1) < 3⎜ − ⎟ < 3(1) ⎝ 3⎠

x −1

(4, ∞), the solution set is 12 < x < 4.

> x + 1 > 14

−1 < −

2x − 9x + 4 < 0

Zeros of the polynomial ( 2 x − 1)( x − 4) are x = 12 and

−3 ≤ x < 2

24.

1 2

2

(2 x − 1)( x − 4) < 0

0−3 ≤ x +3−3 < 5−3

3 −1 > 4

2x2 + 1 < 9 x − 3

28. x

0 ≤ x +3 < 5

3 4

2

− 32 < x < 2.

−1 < 2 x < 7 −1 2x 7 < < 2 2 2 1 7 − < x < 2 2

23.

−1

(−∞, − 32 ), (− 32 , 2), and (2, ∞), the solution set is

−4 + 3 < 2 x − 3 + 3 < 4 + 3

22.

x −2

x = − 32 and x = 2. By testing the intervals

x −4

3

−2

Zeros of the polynomial ( 2 x + 3)( x − 2) are

−5 −6

2 x2 − x < 6

27.

m < 30,000 So, the number of miles driven must be less than 30,000.

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686

Appendix A

A Precalculus Review

35. R = 115.95 x and C = 95 x + 750 and because R > C , you can write

37. (a) False. Because a < b, −2a > −2b.

(b) True. Because a < b, a + 2 < b + 2.

115.95 x > 95 x + 750

(c) True. Because a < b, 6a < 6b.

20.95 x > 750 750 x > = 35.7995… 20.95 x ≥ 36.

(d) False, if ab > 0, then

1 1 > . a b

38. (a) True. Because a < b, a − 4 < b − 4.

(b) False. Because a < b, − a > −b and 4 − a > 4 − b.

So, this product will return a profit if x ≥ 36 units. 36. Revenue: R = 4.50 x

(c) True. Because a < b, − 3a > −3b.

Cost: C = 2.75 x + 220

(d) True. Because a < b, 14 a < 14 b.

Profit: P = R − C = 4.50 x − ( 2.75 x + 220) = 1.75 x − 220 So, 60 ≤ 1.75 x − 220 ≤ 270 280 ≤ 1.75 x ≤ 490 160 ≤ x ≤ 280 So, the daily donut sales vary between 160 dozen donuts per day and 280 dozen donuts per day.

Section A.2 Absolute Value and Distance on the Real Number Line 1. (a) d = 126 − 75 = 51

61 6. (a) d = − 18 − 15 = 23 5 3

(b) d = 75 − 126 = − 51

( )

61 (b) d = 15 − − 18 = 23 5 3

(c) d = 126 − 75 = 51

61 (c) d = − 18 − 15 = − 23 5 3

2. (a) d = −126 − ( − 75) = 51

(b) d = − 75 − ( −126) = 51

7. x ≤ 2

(c) d = −126 − ( − 75) = − 51

8. x < 3

3. (a) d = 9.34 − ( − 5.65) = 14.99

9. x > 2

(b) d = − 5.65 − 9.34 = −14.99

10. x ≥ 3

(c) d = 9.34 − ( − 5.65) = 14.99 4. (a) d = − 2.05 − 4.25 = 6.3

(b) d = 4.25 − ( − 2.05) = 6.3 (c) d = − 2.05 − 4.25 = − 6.3 5. (a) d = 16 − 112 = 128 5 75 75

11. x − 5 ≤ 3 12. x + 4 < 3 13. x − 2 > 2 14. x − 22 > 2

(b) d = 112 − 16 = − 128 75 5 75

15. x − 5 < 3

(c) d = 16 − 112 = 128 5 75 75

16. x − 2 > 5 17.

y − a ≤ 2

18.

y −c < h

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Section A.2 19. −4 < x < 4 20.

Absolute Value and Distance on the Real Number Line

−4

−2

2

0

4

10 − x < −4

27.

x −6

6

x −3

( ) < 12 (2 x) < 12 (6)

1 −6 2

−2

−1

0

1

2

− x > −6

x > 14

x < 6

3

x 6

x or < −3 2 ⎛ x⎞ 2⎜ ⎟ < 2( −3) ⎝ 2⎠

x > 3 2 ⎛ x⎞ 2⎜ ⎟ > 2(3) ⎝ 2⎠

x < −6

x > 6

0

3x > 12 −4

−2

2

0

4

10

0

1

2

3

4

5

6

7

− 12 ( −10) > − 12 (−2) x > − 12 (−8)

8

5 > x > 4

3x + 1 ≥ 4

or

x 2

3x + 1 − 1 ≥ 4 − 1 3x ≥ 3

−5 3x ≤ 3 3 5 x ≤ − 3

3x 3 ≥ 3 3 x ≥1

30.

x 2

3

x −3 ≤ −5 2 x −3 (2) ≤ −5(2) 2 x − 3 ≤ −10

6

2x <1 3 2x −1 − 1 < 1 − −1<1−1 3 2x −2 < − < 0 3 ⎛ 2x ⎞ 3( −2) < 3 ⎜ − ⎟ < 3(0) ⎝ 3⎠ −1 < 1 −

1 1 1 ( −6 ) > − ( − 2 x ) > − ( 0 ) 2 2 2 3 > x > 0 0 < x < 3

x − 3 + 3 ≥ 10 + 3

x ≤ −7

x −1

x ≥ 13

−7

4

−6 < −2 x < 0

x −3 ≥ 5 2 x −3 ( 2) ≥ 5( 2) 2 x − 3 ≥ 10

or

x − 3 + 3 ≤ −10 + 3

31.

13 x 0

50

−10 < −2 x < −8

− 35

−10

40

−1 − 9 < 9 − 2 x − 9 < 1 − 9

3 x ≤ −5

1

30

4 < x < 5

3x + 1 ≤ −4

0

20

−1 < 9 − 2 x < 1

29.

6

x

3x + 1 − 1 ≤ −4 − 1

25.

x ≤ 5

45

3 < x < 7

−1

− x ≥ −5

x ≥ 45

x −6

3x 12 > 3 3 x > 4

−2 + 5 < x − 5 + 5 < 2 + 5

−2

− x ≤ −45 5

−2 < x − 5 < 2

−3

25 − x − 25 ≥ 20 − 25

x

or

−12 3x < 3 3 x < −4

25 − x ≥ 20

or

6

22. 3x < −12

24.

14

25 − x − 25 ≤ −20 − 25

0

23.

10

25 − x ≤ −20

28.

x −6

10 − x − 10 > 4 − 10

− x < −14

−3 < x < 3

21.

10 − x > 4

or

10 − x − 10 < −4 − 10

−6 < 2 x < 6

687

0

1

2

3

−b ≤ x − a ≤ b −b + a ≤ x − a + a ≤ b + a

10

a −b ≤ x ≤ a + b 26.

−5 < 2 x + 1 < 5 x

−5 − 1 < 2 x + 1 − 1 < 5 − 1

a−b

a

a+b

−6 < 2 x < 4 6 2x 4 < < 2 2 2 −3 < x < 2

x −3

−2

−1

0

1

2

3

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688

Appendix A

A Precalculus Review

2 x − a ≤ −b

32.

2x − a ≥ b

or

2 x − a + a ≤ −b + a

2x − a + a ≥ b + a

2x ≤ a − b

2x ≥ a + b

a −b 2x ≤ 2 2 a −b x ≤ 2

a +b 2x ≥ 2 2 a +b x ≥ 2

5 + 5 2

40. Midpoint = 6 41.

33.

a 2

−25,000 ≤ x − 200,000 ≤ 25,000 175,000 ≤ x ≤ 225,000

The low production level is 175,000 barrels of oil, and the high production level is 275,000 barrels of oil.

a+b 2

3x − a < 2b 4 ⎛ 3x − a ⎞ 4( −2b) < 4⎜ ⎟ < 4( 2b) ⎝ 4 ⎠

43. x − 20 ≤ 0.75

−0.75 ≤ x − 20 ≤ 0.75 19.25 ≤ x ≤ 20.75 The lowest and highest acceptable weights for a 20-ounce cereal box are 19.25 ounces and 20.75 ounces.

−8b < 3 x − a < 8b −8b + a < 3 x − a + a < 8b + a 1 1 (a − 8b) < x < (a + 8b) 3 3

44.

w − 57.5 ≤1 7.5 w − 57.5 ≤1 7.5 −7.5 ≤ w − 57.5 ≤ 7.5 −1 ≤

x

a −

34.

a 3

a + 8b 3

5x < −b 2

50 ≤ w ≤ 65 The guidelines specify that the weights for male collies lie between 50 pounds and 65 pounds

5x > b 2 −5 x > b − a 2 5x < a −b 2 2 x < ( a − b) 5

a −

or

5x − a < −b − a 2 −5 x < −a − b 2 ⎛ −5 x ⎞ −1⎜ ⎟ < −1( − a − b) ⎝ 2 ⎠

a −

45. (a)

E − 4750 ≤ 237.50 (b) $5116.37 is not within 5% of the specified budgeted amount; at variance. 46. (a)

2 ( a + b) 5

2 2 a− b 5 5

8 + 24 = 16 2

36. Midpoint =

7.3 + 12.7 = 10 2

37. Midpoint =

−6.85 + 9.35 = 1.25 2

39. Midpoint =

−4.6 + ( −1.3) 2

− 12 + 43 2

1

I − 15,000 ≤ 500 0.05(15,000) = 750

x

35. Midpoint =

38. Midpoint =

E − 4750 ≤ 500 0.05( 4750) = 237.50

5x > a +b 2 2 ⎛ 5x ⎞ 2 ⎜ ⎟ > ( a + b) 5⎝ 2 ⎠ 5 x >

5 3

42. x − 200,000 ≤ 25,000

−2b <

a − 8b 3

=

p − 33.15 ≤ 2

x a−b 2

2

2a 5

2 2 a+ b 5 5

I − 15,000 ≤ 750 (b) $14,695.00 is within $500 of the specified budgeted amount; not at variance. 47. (a)

= −2.95

1 = 4 = 2 8

E − 20,000 ≤ 500 0.05( 20,000) = 1000 E − 20,000 ≤ 1000

(b) $22,718.35 is not within $500 of the specified budgeted amount; at variance. 48. (a)

T − 7500 ≤ 500 0.05(7500) = 375 T − 7500 ≤ 375

(b) $8691.00 is not within 5% of the specified budgeted amount; at variance.

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Section A.3

Exponents and Radicals

689

49. Let r be the percent of defective units. 0.0005 − 0.0001 ≤ r ≤ 0.0005 + 0.0001 0.0004 ≤ r ≤ 0.0006

Number of defective units = x = 150,000r 0.0004(150,000) ≤ 150,000r ≤ 0.0006(150,000) 60 ≤

≤ 90

x

Cost of refunds = C = 195.99 x 60(195.99) ≤ 195.99 x ≤ 90(195.99) 11,759.40 ≤

≤ 17,639.10

C

The total cost of refunds should be between $11,759.40 and $17,639.10.

Section A.3 Exponents and Radicals 1. −2(3) = −2( 27) = −54 3

15. ( −32)

62 36 2. = = 12 3 3

3. 4( 2)

17. 500(1.01)

60

1 + 3−1 1+13 43 = = = 4 3−1 13 13

19.

3

− 54 ≈ − 3.7798

20.

6

325 ≈ 2.6221

=

−2

= 3−

4

(3)

2

= 3−

4 23 = 9 9

3

10,000

(1.1)120

0

0

3

=

1 1 ( −4)

3

0

=

1 = −64 1 ( −64)

1

(−2)

2

=

1 4

2

3

1 1 = 2 4

14. 16−3 4 =

1 = 163 4

3

1

( 16 ) 4

= 6 y −2 ( 2−3 y −12 )

23. 10( x 2 ) = 10 x 4

( 19 ) = ( 19 ) = ( 13 ) = 271

13. 4−1 2 =

−3

22. z −3 (3z 4 ) = 3 z −3 + 4 = 3 z

27 2 = 3 729 = 9 3

=

⎛1⎞ = 6⎜ ⎟ y −14 ⎝8⎠ 3 = 4 y14

9. 6(10) − ⎡⎣6(10)⎤⎦ = 6(1) − (60) = 6 − 1 = 5 −3

( −32 )

2

⎛1⎞ = 6⎜ 3 ⎟ y −2 −12 ⎝2 ⎠

3

1

1

5

≈ 0.1079

21. 6 y −2 ( 2 y 4 )

8. 5( −3) = 5( −27) = −135

( −4 )

=

≈ 908.3483

18.

−2

7. 3( −2) − 4( −2) = 3( 4) − 4( −8) = 12 + 32 = 44

12.

(−32)

25

3

()

2

11.

1

16. (102 3 ) = 102 = 100

= 4 18 = 12

6. 3 − 4(3)

10.

=

7 7 = 2 5 25

4. 7(5)

5.

−3

−2 5

3

=

24. ( 4 x 3 ) = 16 x 6 2

1

(2)

3

=

1 8

25.

7 x2 = 7 x 2 + 3 = 7 x5 x −3

26.

x −3 1 = x −3 − (1 2) = x −7 2 = 7 2 x x

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