The Mean Is 40 With A Standard Deviation Of 4 At Least What Fraction
The Mean Is 40 With A Standard Deviation Of 4 At Least What Fraction
The given problem states that the mean of a dataset is 40, and the standard deviation is 4. The question asks: at least what fraction of the data falls between 32 and 48? To answer this, we need to apply concepts from statistics, specifically the empirical rule or Chebyshev's inequality, to determine the proportion of data within a certain number of standard deviations from the mean.
The mean (µ) is 40, and the standard deviation (σ) is 4. The interval in question is from 32 to 48. These bounds are symmetric around the mean: 40 - 8 and 40 + 8, which are 2 standard deviations below and above the mean (since 2×4 = 8). Therefore, these bounds are at µ ± 2σ
According to the empirical rule (also called the 68-95-99.7 rule), for approximately normally distributed data, about 95% of the data falls within two standard deviations of the mean. Even if the distribution is not perfectly normal, Chebyshev's inequality provides a conservative estimate—guaranteeing that at least a certain fraction of the data falls within any number of standard deviations, regardless of the distribution shape.
Applying Chebyshev's Inequality
Chebyshev's inequality states that for any dataset with finite mean and standard deviation, the proportion of data within k standard deviations of the mean is at least 1 - 1/k². Here, k = 2 because our bounds are µ ± 2σ
Calculating this, we get:
Fraction ≥ 1 - 1/(2)^2 = 1 - 1/4 = 3/4
Thus, at least 75% of the data lie between 32 and 48.
Conclusion
Using Chebyshev's inequality, we determine that at least three-fourths or 75% of the data falls within two standard deviations of the mean in this dataset. This estimate provides a conservative bound applicable regardless of the underlying distribution's shape, making it highly valuable for understanding data dispersion in real-world scenarios where normality cannot be assumed.
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