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The Level Of Lead In The Blood Was Determined For A Sample O

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The Level Of Lead In The Blood Was Determined For A Sample Of 152 Male

The level of lead in the blood was determined for a sample of 152 male hazardous-waste workers aged 20-30 and for a sample of 86 female workers, resulting in a mean ± standard error of 5.1 ± 0.3 for the men and 3.4 ± 0.2 for the women. Calculate an estimate of the difference between true average blood lead levels for male and female workers in a way that provides information about reliability and precision. Use a 95% confidence interval. Round your answers to two decimal places. Interpret the interval. The options are:

- We are 95% confident that the true average blood lead level for male workers is greater than that of female workers by an amount outside the confidence interval.

- We are 95% confident that the true average blood lead level for male workers is less than that of female workers by an amount within the confidence interval.

- We are 95% confident that the true average blood lead level for male workers is greater than that of female workers by an amount within the confidence interval.

- We cannot draw a conclusion from the given information.

Paper For Above instruction

The objective of this analysis is to estimate the difference between the true average blood lead levels of male and female hazardous-waste workers aged 20-30 using sample data and to construct a corresponding 95% confidence interval. This interval will provide an estimate of the range within which the true difference likely falls, with a specified level of confidence, thus informing about the reliability and precision of the estimate.

**Step 1: Summarize the sample data**

From the given information:

- Male workers: mean = 5.1 µg/dL, standard error = 0.3 µg/dL, sample size \( n_{male} = 152 \)

- Female workers: mean = 3.4 µg/dL, standard error = 0.2 µg/dL, sample size \( n_{female} = 86 \)

**Step 2: Calculate the difference in sample means**

\[ \text{Difference} = \bar{x}_{male} - \bar{x}_{female} = 5.1 - 3.4 = 1.7~\text{µg/dL} \]

**Step 3: Determine the standard error of the difference**

The standard error (SE) of the difference between two independent means is calculated using:

\[ SE_{difference} = \sqrt{SE_{male}^2 + SE_{female}^2} \]

where:

- \( SE_{male} = 0.3 \)

- \( SE_{female} = 0.2 \)

So,

\[ SE_{difference} = \sqrt{(0.3)^2 + (0.2)^2} = \sqrt{0.09 + 0.04} = \sqrt{0.13} \approx 0.3606 \]

**Step 4: Find the critical value for 95% confidence**

Since sample sizes are large (n > 30), we can use the z-distribution. The critical z-value for 95% confidence is approximately 1.96.

**Step 5: Compute the margin of error**

\[ ME = z \times SE_{difference} = 1.96 \times 0.3606 \approx 0.707 \]

**Step 6: Construct the confidence interval**

\[ \text{Lower bound} = 1.7 - 0.707 = 0.993 \]

\[ \text{Upper bound} = 1.7 + 0.707 = 2.407 \]

Rounded to two decimal places:

\[ \text{95% CI} = (0.99, 2.41) \]

**Step 7: Interpretation**

Since the entire confidence interval is positive, it indicates that we are 95% confident that the true average blood lead level for male workers exceeds that for female workers by an amount between approximately 0.99 and 2.41 µg/dL. This supports the conclusion that male workers have higher blood lead levels than female workers, with the estimate of the difference being within this interval, indicating both the magnitude and precision of the difference.

Therefore, the correct interpretation from the options provided is:

**"We are 95% confident that the true average blood lead level for male workers is greater than that of female workers by an amount within the confidence interval."**

This conclusion underscores the statistical significance of the observed difference and reflects the reliability and precision of the estimate derived from the sample data.

References

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