BÀI TOÁN NHÔM VÀ HỢP CHẤT CỦA NHÔM 2020

P CH T C

2020

PH C

PH N II.

P MINH H

PH N III.

THI

PT

PH N I.

LUY N

T

A.H p ch

2O 3

; Al(OH)3 )

n: Al2O3 Al2O3

6H+

+

2OH-

+

Al(OH)3

+ 3H2O

2AlO2-

+ H2O

3H+

+

Al(OH)3

2Al3+

+

OH

-

B.M t s V im TH1:

Al3+

Al3+

+ 3H2O

AlO2-

+ 2H2O

th v 3+

Al2O3 Có tính luõng tính

p ch t ng OHOH- th

k tt

+

3OH-

Al(OH)3 t

3t Al3+

3OH-

+

a Al(OH)3 b TH2:

3a +

Al(OH)3 Có tính luõng tính

OHb

Al(OH)3 a Al[OH]4- (AlO2-.2H2O )

t = a- b

*D

th :

*D

th :

S mol k t t a n S mol k t t a n

(4a a

B

nt OH- =3t

(4a

A

t)

t + x)

a t

nOH- =3t + x

C D

nOH- =4a - t C

x - =4a - t + x nOH

0

0

3t

3a

S mol OH-

4a

th so v

(3t+x)

(3a+ x)

ng h O 2-

V im TH1: +

; Al3+ k tt

V im TH1:

H+ x Al3+

ng OHtr OH th

OHx

+

H2O

3OH-

+

+

OHx

H2O

Al3+ a

+

3OH-

Al(OH)3 a

+

OHb

*D

+

S mol OH-

i tr c t nx ng g p H2SO4 H+ th

+

; ho

)

Al(OH)3 t

H+ + H2O a

+

Al(OH)3 b TH2:

H+ x

3a

H+ + H2O t

+

AlO2-

Al(OH)3 t

3t

Al(OH)3 b TH2:

k tt

AlO2-

-

ng H+

(4a +x)

3H + 3b

Al(OH)3 a

t = a- b

Al3+ + 3 H2O

th :

S mol k t t a n

t = a- b

Al[OH]4- (AlO2-.2H2O ) B a A

C

nt H+ =t

D

nH+ =4a - 3t 0

t

a

(4a -3t)

4a

S mol H+

C cung BC =

cung AB)

-

; AlO2-

ng H+ (

PH N II. ng g p H2SO4

+

) H+ th

k tt

-

+

OH x

+

H x

H2O

AlO2-

+

H+ + H2O t

Al(OH)3 t

OH- + H+ x x AlO2 + H+ + H2O a a Al(OH)3 + 3H + 3b b TH2:

THI

n h p g m Na2 c dung d ch X.Cho t t

-2019).

V im TH1:

*D

P MINH H A

c

nghi Th Kh i c

c ghi

b ng sau: ch HCl (ml) ng k t t a(gam)

bi

:

300 a

2O3

(t l mol t qu

600 a+2,6

ng d n gi i

H2O Al(OH)3 a

t = a- b

4x Na2O 3x Al2O3

H2O

OHAlO2

Al3+ + 3 H2O

HCl

2x -

6x

Al(OH)3 (mol)

th :

S mol k t t a n

B

6x t+ 1 30

C

A t

0

a

2x

0,3

1 ) = (0,6 - 8x)/3 Ta dê có : 8x - (0,3 + 30

B A

0,6

8x

HCl (mol)

x = 0,05

C

t =0,2

a = 15,6 gam m = 27,7 gam

Ch n

t

+

nH =t

O

*

0 nH+ =4a - x3t

B

D

(202-2019). (t+x)

(a+x)

(4a+x -3t)

(4a+x) S mol H+

d

2

t qu

C Th cung

*

A)

c ghi

ch NaOH (ml) ng k t t a(gam)

Kh

nh pg 2O3 trong 200 ml dung ch X .Cho t t dung d ch NaOH 1 M b ng sau: 340 470 2a a- 0,78

c A.4,5.

B.1,65.

C.3,3.

D.3,9.

ng d n gi i Al Al2O3

Al3+

HCl

H+ x

0,4 mol

Al

NaOH

Cl0,4

H2SO4 0,2mol

Al3+ SO42-

NaOH

0,2

H+ x H2

H2 0,075 H2O

Al(OH)3 (mol)

Al(OH)3 (mol)

2t + 0,06 2t + 0,02

(2t + 0,02) 2t

t

t - 0,01 0 0

3(t - 0,01 ) + x

x

Ta dê có: 0,4 - 3(t-0,01) - x = 3.( 0,47 - 0,4) 0,34 = x + 6t

B

nAl2O3

0,34 0,4

0,47

NaOH (mol)

nAl

a 1,56 gam

0,05mol

A.

0,48

NaOH (mol)

0,1mol

3

nh pg

l t qu

c dung d ch X.Cho t t

ch X .Cho t t dung d c ghi b ng sau: ch NaOH (ml) 140 ng k t t a(gam) 2a + 1,56

a 0,2 mol H2SO4 t qu

2

Kh c

; nAl

0,4

x= 0,1 t = 0,02

Ch n D (206-2019).

0,05mol

Ch n D (203-2019). nghi Th

0,28

x + 3t

Ta dê có: 0,4 - (x+3t) = 3.( 0,48 - 0,4) 0,28 = x +3(2t + 0,02)

x= 0,1 t = 0,04

0, 025mol ; nAl

x

.

C. 2 . ng d n gi i

240 a

c ghi b ng sau: Th ch HCl (ml) Kh ng k t t a(gam) c a m A.6,69.

B.11,15.

5x 4x

Na Al

Na+

H2O

OHAlO2-

5x x

210 a

ng m

430 a+1,56

C.6,15. ng d n gi i

D.9,80.

HCl

4x

Al(OH)3 (mol)

4x t t - 0,02

0

x

0,21

Ta dê có : 5x -(0,21 - 0,02) = (0,43 - 5x)/3

0,43

5x x = 0,05

HCl (mol)

t =0,16 m = 11,15 gam

Ch n B

A.0,5.

B.1,5.

x =0,1 y = 0,1 t = 0,05

x =0,1 x + 3t = 0,25 x + 4y - t =0,45

5.(201 -2017): nh m Al2O3 trong 200ml dung d ch HCl n a mol/lit c dung d ch X.Cho t t dung d ch NaOH ng k t t a Al(OH)3 (m gam ) ph thu c bi u V di n b th 0 c

100

C.1,0.

250

: a = 2 ch n D

450

6(202 -2017): X g m Al2O3 2 Y.Cho t t dung d Al(OH)3 (m gam ) ph thu c bi u di n b c

D.2,0.

ng d n gi i

nh p c dung d ch m ng k t t a ch

V

th 0

150 350

750

H 2O HCl 0,2.a

Al

H+ x mol NaOH Al3+ y mol Cl- 0,2.a

Al2O3 H2

*D

A.14,40.

B.19,95.

C.29,25.

ng d n gi i

X

th

D.24,60.

Na2O

c:

H 2O

Al2O3

-x

mol

OH AlO2- y mol

H+

X

*D

th

c:

S mol k t t a n

B

S mol k t t a n y t

C A O*

(4y

0

y t

nOH- =3t + x 0

x

nOH- =4a - t + x

(3t+x)

(3y+ x)

(4y +x)

D

t + x) x

(t+x)

(y+x)

(4y+x) S mol H+

(4y+x -3t)

C

S mol OH-

*

Ta di n t

0

th v d ng s mol quen thu

0,1 th so v

s mol OH 0,45

0,25

di n bi

th v d ng s mol quen thu Ta di n t bi n cho NaOH : th so v c

-

A)

di n n V

c 0 .

0,15 0,35

0,75

bao

x =0,1 y = 0,1 t = 0,05

x =0,1 x + 3t = 0,25 x + 4y - t =0,45

Al

Al 0,02 Fe Al2O3 0,045

t0

FexOy

NaOH du

X

toan Al H2 0,03 mol NaAlO2 (Y) 0,11 mol

CO2

Fe (Z) H2SO4

Fe2+

: a = 2 ch n D 7(203 -2017): n ch H2SO4 2 O3 c dung d H2 t dung d ng k t t a Al(OH)3 (m gam ) ph thu c bi u di n b th c

Al(OH)3 0,11 SO2 0,155 mol

h

A.2,34.

B.7,95.

20,76 gam Fe

n

V 0 0,56 C.3,87.

0,24

0,36 D.2,43.

nh pXg m c dung d m t dung d ch HCl 2 ng k t t a Al(OH)3 (m gam ) ph thu c bi u di n b

th

V 0

150 350

750

c

H2 0,022 mol 0,0125.m Al2O3 H O 3 2 x K y Ba m gam

A.10,08.

B.3,36.

C.1,68.

D.5,04.

9 -2018): Th c hi n ph n ng nhi nh pg oxit s c h n h p ch t r c dung d ch Y, ch 2 2 c 8,58 gam k t t a. Cho Z tan h ch H2 SO4 c dung d ch ch a 20,76 gam mu t SO2 n ph m kh 2 6

bi

n ng x B. 8,04. c:

c C. 6,96. ng d n gi i

D. 6,80

+ 96.t = 20,76

Fe = 5, 88 gam m = mFe + mO = 5,88 + 0,045.3.16 = 8,04 gam 10 -2018): H n h p X g m Al2 O3 m 20% kh i ng c c dung d n h t dung d ch g m 0,018 mol H2 SO4 2 . Cho t t c dung d ch Z (ch ch mu h nh pk tt c A. 3,912.

B. 3,600.

C. 3,090.

D. 4,422. ng d n gi i

8(204 -2017): Al2O3

duy nh t c a S A. 7,28.

SO42t mol

Fe3+

Ba2+ AlO2- 0,018 mol H2 SO4 K+ OH0,038 mol HCl

BaSO4

y

Al(OH)3 t mol

2,958 gam

Al3+ SO42K+

Cl- 0,038

Ta d : 233y + 78. t = 2,958 ; 39x + 137 y = 0,575.m x + 2y = 0,044 133,975. m + 4602.t =574,35 (1) n(+) = 0,022.2 + nO. 2 = 0,018.2 + 0,038.1 + 3.t 0,025m 3t = 0,03 (2) T (1)(2) gi i m= 3,6 gam 11 -2018): H n h p X g c dung d n h t dung d ch 2 . Cho t t ch a 0,018 mol H2SO4 c 1,089 gam h n h p k t t dung d ch Z ch ch a 3,335 gam h n h n ng c a kim lo A. 42,33%.

B. 37,78%.

C. 29,87%.

D. 33,12%. ng d n gi i

H2 0,0405 mol

Al Ba

H2O

Na K

Ta d : n(+) = 0,0405.2 = n(-) M nBaSO4 = nBa 29,87 % 12 -2018): Nh t t n ch Ba(OH)2 ch g m Al2 (SO4 )3 3 . S ph thu c c a kh ng k t t mol Ba(OH)2 c bi u di n th ng k t t a c c b c A. 10,11.

C. 11,67.

1,089 gam

Al(OH)3 t mol

Ba2+ AlO2- 0,018 mol H2 SO4 K+ OH0,03 mol HCl Na+

m gam

23

BaSO4

Al3+ SO42K+ Cl- 0,03 Na+

0,03 mol H2SO4 Z ch ch a 7,43 gam h n h A. 2,79.

B. 3,76.

Al Na x BaO

H2 0,085 mol

BaSO4

H2O Ba2+ AlO2- 0,03 mol H2 SO4 Na+OH0,1 mol HCl

y

m gam

m 0,03 Bao toan S BaSO4 0,03 Al(OH)3

AlCl3

0,03

0,08

x

16x + 51t = 4,11 (2) 233x + 78t = 3,11 (3) ( Kh T 14.

-2018): Cho t t n ch Ba(OH)2 ch ch a m gam h n h p Al(NO3 )3 2 (SO4 )3 . S ph thu c c a kh ng k t t mol Ba(OH)2 (x mol) c bi u di n b th c A. 7,68.

B. 5,55.

C. 12,39.

D. 8,55.

m 0,08

AlCl3 0,02

m 6,99 BaSO4 0,03 Al(OH)4-

Bao toan OH

Bao toan OH

V y m = mAl(OH)3 + mBaSO4 = 10,11 gam

3,11 gam

Al3+ SO427,43 gam

ng k t t a ) y 9,33 6,99

0

ng d n gi i

0,01 Al2(SO4)3

Al(OH)3 t mol

Ta d : n(+) = 0,085.2 + 2x = n(-) = 0,03.2 + 0,1 + 3t 2x 3t = - 0,01 (1) : m 16.x + 0,03.96 + 0,1.35,5 + 51.t =3,11 + 7,43 ( kh M

m

ng d n gi i

Ba(OH)2 0,08

x

K+ Cl- 0,1 Na+

0

Ba(OH)2 0,03

2

3,335 gam

B. 6,99.

D. 8,55.

0,01 Al2(SO4)3

nh pXg . Cho t t n h t dung d ch ch a c 3,11 gam h n h p k t t ch c C. 6,50.

D. 3,60. ng d n gi i

-2018): c dung d ch Y

0,01 Al2(SO4)3 Al(NO3)3

0,04

m 9,33

Ba(OH)2

BaSO4 0,03

x

0,01 Al2(SO4)3

ng d n gi i

BaSO4 0,03

Ba(OH)2

*D

Al(OH)3 0,03

Al(NO3)3 0,01

th

S mol k t t a n

B

Bao toan Al

V y m = mAl2(SO4)3 + mAl(NO3)3 = 5,55 gam 15.

-2018): H n h p X g m Al, K, K2 m 10% ng c c dung d kh n h t dung d ch ch a 0,04 mol H2SO4 2 . Cho t t c 4,98 gam h n h p k t t ch Z ch ch a 6,182 gam h n h p c A. 9,592.

B. 5,760.

C. 5,004.

D. 9,596. ng d n gi i Al Na x BaO

H2 0,085 mol

BaSO4

H2O

2

SO4

0

D

0,4

0,55

(4b+0,4 -3.0,15)

*

Ta d thi t l

a = 0,375 b = 0,2 Ch n B

7,43 gam

n h p X g m Ba, ch Y. c 4,302 gam k t t a.

2 c dung d ch Z ch ch a m t ch t tan. M nt t c 3,12 gam k t t c B. 7,09.

C. 2,93.

D. 5,99.

minh h a 2018]: 2O3

H p th L ck tt CO2 A. 6,79.

ng d n gi i ng k t t a )

bi Ba BaO Al Al2O3

nAl(OH)3

H2O

Ba(HCO3) 2 x

H2 0,04 mol CO2 0,054

OHAlO2- 0,04 Ba2+

0,15

CO2

.

B. 0,375..

A)

c:

2.b = 0,4 2.a = 4.b + 0,4 - 3.0,15 17:

AlO2

A. 0,325.

(4b+0,4) S mol H+

C

Al3+ SO42-

Ta d : n(+) = 0,085.2 + 2x = n(-) = 0,03.2 + 0,1 + 3t 2x 3t = - 0,01 (1) M : m 16.x + 0,03.96 + 0,1.35,5 + 51.t =3,11 + 7,43 ( kh

16:

C A O*

3,11 gam

K+ Cl- 0,1 Na+

16x + 51t = 4,11 (2) 233x + 78t = 3,11 (3) ( Kh T

b 0,15

x

Al(OH)3 t mol

Ba2+ AlO2- 0,03 mol H2 SO4 Na+OH0,1 mol HCl

m gam

c:

0 C. 0,400.

0,2

a D. 0,350..

du

nH2SO4

BaCO3

y

Al(OH)3 0,04 4,302 gam Al(OH)3 0,04 mol 3,12 gam

Ta d

c y =0,006 mol ;

B OH

B

H2O

= 0,05 mol ; B

-

= 0,02 mol ng m =5,99 Ch n D

8(MH -2018): dung

n

A. 1,56. (

0,2 V

A. 1,2 0

A. 0,30..

.

B.0,30

.

150 .

C.

c m gam k t t B. 0,39.

- 2007)

D. 1,17 3

B .1,8. :(

750 D.

c C. 0,78.

-

C .2.

- KA 2008

D.2,4.

A. 0,05 B .0,25 : Cho 3,42 gam Al

C .0,35.

D.0,45.

A. 0,6

C .2,4.

D.3,6.

ng d n gi i th

*D

c:

B .1,2. :

S mol k t t a n

: B y 0,2

C A O* 0

x= 0,15

D 0,55

(4y+0,15 -3.0,2)=0,75

(4y+0,15) S mol H+

C *

Ta d thi t l

c : x = 0,15 ; y = 0,3

PH N III.

A)

Ch n D

PT

: Cho 500 ml dung d ch Ba(OH)2 ch Al2(SO4)3 0,1M; n ng k c 12,045 gam k t t c A. 300.

B. 75.

C. 200.

D. 150 2: Dung d ch X ch a 0,15 mol H2SO4 Al2(SO4)3 . Cho V ml dung d c m gam k t t p 450ml dung d n ng x c 0,5m gam k tt c A. 550,0 ml B. 500,0 ml C. 450,0 ml D. 600,0 m (MH 2018): A. 15,6.

B. 7,8 C. 3,9.

D. 19,5 (THPTQG 2016): t 0,54 gam Al trong 70 ml dung d ch HCl 1M, thu c dung d ch X. Cho 75 mldung d n ng x y ra

tr l n nh t c t : k tt

- KA n khi ph n c kh i l ng k t

tc : l ng k t t a tr ng A: 200 ml B: 120 ml : n khi ph n c l ng k t t

ch ch a 0,1M c 7,8 gam k t t

ng v i 300 ml dung d ch AlCl3 1 M, l ng t ng v i 150 ml dung d ch Al(NO3)3 0,2 M, tc C: 240 ml D: 180 ml. ch ch c 7,8 gam k t t l n nh t c a V

: Cho 500 ml dung d c m gam ch c B: 1,56 gam C: 2,34 gam D: 1,17 gam.

14: dung d ng v ch AlCl3 0,1 M, l ng k tt n nh : c 15,6 gam k t t n nh tr : Cho 200ml dung d ca gam k t t c A: 7,8 gam B: 1,56 gam C: 2,34 gam D: 1,17 gam.

17 -2007): Nh t t ch AlCl3.

Hi ng x t t a keo tr t t a tan.

B. ch t t a keo tr ng. t t a keo tr tt k tt

-2007): Tr n dung d ch ch a a mol AlCl3 v i dung d ch ch a b mol NaOH. ck tt l A. a : b = 1 : 4.

B. a : b < 1 : 4.

C. a : b = 1 : 5.

D. a : b > 1 : 4.

-2007): Cho 200 ml dung d ch AlCl3 ng v ch ng k t t l n nh t c A. 1,2.

B. 1,8.

C. 2,4.

D. 2.

-2007): H n h p X g ch NaOH n ph ng c u ki n, 2 -2008): nh pg ch c a mol h n h ch X. S ch ng k t t c A. 0,40.

B. 0,45.

C. 0,55.

D. 0,60.

2 -2008): ch ch a 0,1 mol n khi ph n c 7,8 gam k t t tr l n nh t c ng k t t A. 0,05.

B. 0,45.

C. 0,25.

D. 0,35.

2 -2008): Cho h n h p g l s n ng x gam ch t r c A. 5,4.

B. 7,8.

C. 10,8.

D. 43,2.

-2010): Cho 150 ml dung d ng v i 100 ml dung d ch AlCl3 n c dung d t t a. Lo i b k t t ti p 175 ml dung d c 2,34 gam k t t c A. 1,2.

B. 0,8.

C. 0,9.

D. 1,0 -2010): Dung d ch X ch s mol c a ion Cl ch X ph n ng v i dung d c 2 gam k t t a. Cho 1/2 dung d i ph n ng v i dung d c 3 gam k t t a. M n c n dung d c m gam ch t r c A. 9,21.

B. 9,26.

C. 8,79.

D. 7,47.

-2011) Chia h n h p X g n b ng nhau.

- Cho ph - Cho ph nh p kim lo d Kh a K, Al, Fe trong m i ph n h n h p X l A. 0,39; 0,54; 1,40.

B. 0,78; 1,08; 0,56.

C. 0,39; 0,54; 0,56.

D. 0,78; 0,54; 1,12.

27 -2011) Cho 400 ml dung d ch E g m AlCl3 2(SO4)3 ng v i 612 ml dung d n ng k c 8,424

gam k t t a. M ng v i dung d ch BaCl2 c 33,552 gam k t t a. T l A. 3 : 4.

B. 3 : 2.

C. 4 : 3.

D. 7 : 4.

28 -2012)Cho 500 ml dung d ch Ba(OH)2 ch Al2 (SO4)3 n ng k c 12,045 gam k t t c A. 300.

B. 75.

C. 200.

D. 150.

29 -2012) n h p g m Na2 c thu 2 O3 c dung d ch X trong su t dung d t u xu t hi n k t t a; khi h t 300 ml ho c a gam k t t a. c 30 -2013)H n h p X g ph n ng x gam X b ng dung d c A. 16,4.

B. 29,9.

C. 24,5.

D. 19,1.

31 -2013) H n h p X g m Na, Ba, Na2 Ba(OH)2. H p th tr c A. 15,76.

B. 39,40.

32 -2013)Th

c m gam k t t

C. 21,92.

D. 23,64. ch NaOH 0,25M c ng k t t a l n nh A. 210 ml.

B. 60 ml.

C. 90 ml.

D. 180 ml.

-2014)Cho m gam h n h p g x tr c A. 3,70.

B. 4,85.

C. 4,35.

D. 6,95.

34 -2014): Khi t t dung NaOH dung a mol HCl b mol AlCl3 q m i mol Al(OH)3 0,4 mol N

l 2,0

2,8

ch

n ng

h u:

A. 4 : 3.

B. 2 : 1.

C. 1 : 1.

D. 2 : 3.

35 -2015): Dung d X g m Al2(SO4)3 0,75M v H2SO4 0,75M. Cho V1 ml dung d KOH 1M v 100ml dung d X, thu c 3,9 gam k t a. M kh khi cho V2 ml dung d ch KOH 1M v 100 ml dung d X c ng thu c 3,9 gam k t a. c ph n ng x y ra ho to n. T V2 : V1 A. 4 : 3.

B. 25 : 9.

C. 13 : 9.

D. 7 : 3.

36 (THPTQG-2015): X CaC2 x mol Al4C3 y mol. Cho X thu H2O 2H2, CH4 3 A. 1 : 2.

B. 5 : 6.

(THPTQG-2015): Cho X Ba CuCl2 0,1M.

C. 4 : 3.

Na

200 ml dung

D. 3 : 2.

Y

HCl 0,1M

A. 1,28.

B. 0,64.

C. 1,96.

D. 0,98.

38.(THPTQG-2016): t 0,54 gam Al trong 70 ml dung d ch HCl c dung d ch X. Cho 75 ml dung d ph n ng x c m gam k t t c A. 1,56.

B. 0,39.

C. 0,78.

D. 1,17.

39.(THI THU QUYNH LUU -2016): Nh t t dung d ch Ba(OH)2 ch A ch a Al2(SO4)3 xM. M i quan h gi a kh ng k t t mol OHc bi u di n b th sau:

N u cho 100ml dung d ch h n h p Ba(OH)2 dung d ch A ng k t t ?

A. 5,44 gam B. 4,66 gam C. 5,70 gam 40. (THI THU BGD -2016): Cho m ng h n h ch h n h Al2(SO4)3 c dung d ch X, m gam k t t c A. 14,77.

B. 17,1.

C. 13,98.

D. 6,22 gam it l n ph n 2 ( D. 13,99.

41: ch HCl 2M thu c dung d ch X. Cho dung d ng v i 320 ml dung d ch NaOH 1M c 4,68 gam k t t c A. 1,89 gam B. 2,7 gam C. 1,62 gam D. 2,16 gam 42.(THI THU DHSPHN -2016): nh pg m c dung d ch ch X b i Yg dung d ch Y, t ng kh c t o ra l A. 12,78g.

B. 14,62g.

C. 13,70g.

D. 18,46g.

43.(THI THU BEN TRE -2016): H n h p X g h nh ng v 2 ch t r nh ng v i dung d ch NaOH c 2 A. 11,36 B. 11,24 C. 10,39 D. 10,64 : Cho 7,65 gam h n h d ch g c dung d 850 ml dung d n ng x c 16,5 gam k t t a g m 2 ch t. M t dung d ch h n h p KOH n khi ng k t t a l n nh t, l c l y k tt n kh c m gam ch t r c a m g n nh t v A. 27,4.

B. 46,3.

C. 38,6.

D. 32,3 .(THI THU BEN TRE -2016): d ch ch c dung d ch Y ch a 2 ch t dung d th sau :

ng v i dung d ch h n h p ch a 0,15b mol FeCl3 mol CuCl2. Sau khi ph n ng k c x gam ch t r c A. 10,874 B. 11,776 C. 12,896 D. 9,864

.(THI THU NGUYEN HUE -2016): 100 ml dung d ch HCl 0,1M, H2SO4 dung d ch NaOH 0,1M; Ba(OH)2 A. 220

2O3

c dung d

trong t ng k t t a l n nh t

2,496

B. 250 12,976 C. 250 14,146 D. 220 12,748 -2018): Th c hi n ph n ng nhi nh pg m gam hai oxit s c h n h p ch t r d c dung d ch Y, ch 2 c 8,58 gam k t t a. Cho Z tan h 2 dung d ch H2 SO4 c dung d ch ch a 20,76 gam mu i sunfat 6

n ph m kh duy nh t c a S

n ng x c A. 7,28.

B. 8,04.

C. 6,96.

D. 6,80 48 -2018): H n h p X g m Al2 O3 m 20% kh ng c c dung d n h t dung d ch g m 0,018 mol 2 . Cho t t H2 SO4 c dung d ch Z (ch ch i mu nh pk tt c A. 3,912.

B. 3,600.

C. 3,090.

D. 4,422. .

-2018): H n h p X g c dung d 2 . Cho t t n h t dung d ch ch a 0,018 mol H2SO4 c 1,089 gam h n h p k t t ch Z ch ch a 3,335 gam h n h mu ng c a kim lo i Ba 2

t SO2

A. 42,33%.

B. 37,78%.

-2018): Nh t t ch Ba(OH)2 d ch g m Al2 (SO4 )3 3 .S ph thu c c a kh ng k t t a (y mol Ba(OH)2 (x mol) c bi u di n b th i ng k t t a c tr c A. 10,11.

B. 6,99.

C. 11,67.

D. 8,55.

C. 29,87%.

D. 33,12%.

y

m

0

0,03

0,08

x