soluciones sistemas ecuaciones

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4º de ESO

MATEMÁTICAS Colegio Teresiano del Pilar

SOLUCIONES SISTEMAS DE ECUACIONES

Ejercicio 8 a. x1 = 2, y1 = - 4 x2 = 8, y2 = 8 b. x1 = -6, y1 = -15 x2 = 15, y2 = 6 x2 = 8, y2 = -6 c. x1=4+ 42 , y1=4- 42 x2=4- 42 , y2=4+ 42 d. x1 = -6, y1 = -8 e. x1=1, y1=3 x2=-1, y2=-3 x3=3, y3=1 x4=-3, y4=-1 f. x1 = -8, y1 = -3 x2 = 8, y2 = 3 g. x1 = 6 17 − 6 y1 = 3 17 − 12 , x 2 = − h. x1 = 2, y1 = 3 x2 = - 2, y2 = -3 j. x1 =1, y1 = 3 x2 = 3, y2 = 1 l. x = 12, y = -2 n. x1 = 1, y1 = 3 x2= 8/3, y2 = 4/3 o. x = 2, y = 1 q. x1 = 4, y1= 2 x2=6, y2 = 8/3 s. x = 1, y = 4 Ejercicio 9 a. x = - 4 ; y = 6 ; z = 1 c. x = 1; y = 2 ; z = 3 1 1 e. x = ; y = ; z = 5 2 4 14 12 27 g. x = − ; y = − ; z = 5 5 5 i. x = 6 ; y = 4 ; z = -3 Ejercicio 10 a. x = 3 ; y =2 (cambio de variable) c. x = 2; y = 3 (cambio de variable) x = 3; y = 2 10 1 e. x = ; y = (No existen log de 3 3 números negativos)

6 17 − 6 y 2 = − 3 17 − 12 i. x1 = 1, y1 = 3 x2 = 3, y2 = 1 k. x1 = 2, y1 = -1 x2 = -2, y2 = 1 m. x1 = 2, y1 = -2 x2 = 3, y2 = 0 ñ. x1 = -2, y1 = 8 x2 = 3, y2=3 p. x = 1, y = -1 r. x1 = 3, y1 = 1 x2 = -18/13, y2 = -25/13 t. x = 5, y = 4

b. x = 1 ; y = 1 ; z = 1 5 9 d. x = ; y = − ; z = 3 7 5 1 3 f. x = ; y = − ; z = 1 2 2 h. x = 5 ; y = -6 ; z = 4

b. x = 4 ; y = 2 50 5 d. x = ; y = 3 3 f. x = 625; y = ±

15625 4


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