VI.
¢EœÇkZkbZk Ék#Tkkh 1ålTkRvr#kkTknbkk@Yk~ ¤Åk@g l\kBkP 2åYkkPpXkkakkZk ¤Åk@g l\kBkP
5x3 2x3 3x3
= 15 =6 =9
VII.
¢EœFkPnìZkbZk Ék#Tkkh 1å#\kkvAùg Uo@ZkP 2åUÇk \kvBkTkYk~
3x4 2x4 1x4
= 12 =8 == 4
2x5 1x5 1x5
= 10 =5 =5
VIII. ÉkWkTSkk’YkAùkh Ék#Tkkh 1åÉkWkTSkg l\kBkP 2åCk<XkkCkg UlL’^kk Ék#TkkTkkYk~ ¤Åk@g l\kBkP [ Ck<XkkCkh bk@\k^kk‘Zkwh Xk^kvP~‹ UJFkÉk#Tkkh Ékì^Zkkh ]
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