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Free Mathematics Examination Questions and Answers for SS3 blog.teststreams.com/free-mathematics-examination-questions-and-answers-for-ss3/ TestStreamsBlog

September 30, 2019

These Mathematics questions and answers were pulled from our book (Mathematics questions for SS3); Compiled to serve as a reference material to help teachers draw up test and exam questions faster. It could also help students assess their level of exam preparation. Each sample question includes correct answers. The Questions are based on the current NERDC curriculum (UBE compliant)

Sample Mathematics Exam Questions and Answers ARITHMETIC AND GEOMETRIC PROGRESSION 1. Johnbull bought an electronic gadget worth ₦208,000. He pays half the worth and agrees to pay the remaining in five instalments with a compound interest of 6% per annum, calculate the annual instalment to the nearest naira. A. ₦ 26,300 B. ₦ 25.428 C. ₦ 14,380 D. ₦ 24,700 See the Answer The correct answer is D Explanation: Worth of item = ₦ 208,000. Amount paid = ₦ half the worth = 208,000  1/2 = 104,000. Balance = 104,000  [1 + (6/100)]5 = [a  (1.065 – 1)]/[1.06 – 1]; 104,000  [1.06]5 = [a  (1.065 – 1)]/0.06, therefore, a = [104,000  (1.06)5  0.06]/[1.065 – 1] = ₦ 24,700

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2. Calculate the amount arising from annuity of ₦ 750 annually payable in 10 years, if the compund interest payable is at 7% per annum. A. ₦ 10,363 B. ₦ 9,384 C. ₦ 40,040 D. ₦ 25,313 See the Answer The correct answer is A Explanation: Annual annuity = ₦ 750, time payable = 10 years, rate = 7% = 0.07 + 1 = 1.07 Amount = [₦ 750(1.0710 – 1)] [1.07 – 1] = ₦ 10,362.9  ₦ 10,363 3. Find the amount an annuity of ₦200 payable for 11years at 10% per annum interest. A. ₦ 7065 B. ₦ 6053 C. ₦ 3706 D. ₦ 1200 See the Answer The correct answer is C Explanation: Using the equation S = [a  (rn – 1)]/[r – 1], where a = ₦ 200, r = 1.1, n = 11. CHANGE OF SUBJECT FORMULA 1. Make B the subject of formula: A = [2B + C]/[2BC]. A. B = C/[2A2C – 2] B. B = C/[2A2C + 2] C. B = 1/[CA2 + 2] D. B = 1/[2A2C + 2] See the Answer The correct answer is A Explanation: A = [2B + C]/[2BC]; A2 = [2B + C]/[2BC]; 2A2BC = 2B + C; C = 2A2BC – 2B; C = B[2A2C – 2]; B = C/[2A2C – 2] 2/7


2. Given that A = [12/C – B/3], make C the subject of formula. A. C = [3A2 + B]/36 B. C = 36/[3A2 + B] C. C = [36B]/[3A2] D. C = [3A3 – B]/36 See the Answer The correct answer is B Explanation: A = [12/C – B/3]; A2 = 12/C – B/3 = [36 – BC]/3C; 3CA2 = 36 – BC; 36 = 3CA2 + BC; 36 = C[3A2 + B]; C = 36/[3A2 + B] 3. WX + WY + 7/Z = 3, make Y the subject. A. [3Z – 7 – ZWX]/ZW B. [7Z – 3 + ZWX]/ZX C. [ZX – ZWX + 7]/WX D. [WX + 7Z – ZW]/ZX See the Answer The correct answer is A Explanation: WX + WY + 7/Z = 3; [ZWX + ZWY + 7]/Z = 3; ZWX + ZWY +7 = 3Z; ZWY = 3Z – 7 – ZWX; Y = [3Z – 7 – ZWX]/ZW 4. Make P the subject: R = [Q2 – PR]/[Q + P]. A. P = [Q(Q – R)]/2R B. P = [2R(Q2 – Q)]/R C. P = [2R(1 – Q2)]/Q D. P = [2Q(R – Q)]/RQ See the Answer The correct answer is A Explanation: R = [Q – PR]/[Q + P]; R[Q + P] = Q2 – PR; RQ + RP = Q2 – PR; RQ = Q2 – PR – RP; 3/7


RQ = Q2 -2PR; 2PR = Q2 – RQ; P = [Q2 – RQ]/2R = [Q(Q – R)]/2R 5. Make g the subject of formula from the equation t/L = [(42)/g]. A. g = [43L]/t. B. g = [4]/[tL] C. g = [42L2]/t2 D. g = [4L2]/t2 See the Answer The correct answer is C Explanation: t/L = [(42)/g], square both sides of the equation, then, t2/L2 = [42]/g; gt2 = 42L2; g =[42L2]/t2. Click here to get the complete Mathematics questions for SS3 EQUATIONS AND FORMULAE 1. One stick is 9cm longer than another, 25 of the longer stick is equal to 12 of the shorter stick. Find the length of the longer stick. A. 45 cm B. 36 cm C. 27 cm D. 54 cm See the Answer The correct answer is A Explanation: Let the shorter stick be n; 2/5[n + 9] = n/2  2  2[n + 9] = 5n; 4n + 36 = 5n  5n – 4n = 36, therefore, n = 36cm. The longer stick is 36 + 9 = 45cm 2. The result of adding 3 to x and multiplying the answer by 4 is the same as taking 3 from five times x. Find the value of x. A. 27 B. 6 C. 15 D. -15 See the Answer The correct answer is C 4/7


Explanation: 4[x + 3] = 5x – 3; 4x + 12 = 5x – 3  5x – 4x = 12 + 3; x = 15. 3. Somina and Qiana share 191 naira between them so that Qiana get 27 naira less than Somina. Find how much money each gets. A. ₦ 109; ₦ 82 B. ₦ 109; ₦ 136 C. ₦ 136; ₦ 82 D. ₦ 218; ₦ 191 See the Answer The correct answer is A Explanation: Let Somina’s share be represented by x; Qiana receives x – 27; x + x – 27 = 191 2x – 27 = 191; 2x = 191 + 27; 2x = 218. Therefore, x = 218/2 = ₦ 109. Qiana’s share = 109 – 27 = ₦ 82. The answer is ₦ 109 ; ₦ 82 4. The sum of 8 and one-fourth of n is one more than twice n. Find the value of n. A. -12 B. 4 C. -312 D. 8 See the Answer The correct answer is B Explanation: 8 + n/4 = 2n + 1; multiply through by 4; 32 + n = 8n + 4  8n – n = 32 – 4  7n = 28. Therefore, n = 28/7 = 4. 5. A rectangle is one-third as long as it is wide. If its perimeter is 120cm, find the width of the rectangle. A. 15cm B. 20cm C. 30cm D. 45cm See the Answer The correct answer is D 5/7


Explanation: Perimeter of a quadrilateral shape = 2[L + B], where B = Breadth, L = length = B/3, Perimeter = 120  2[B/3 + B] = 120; B/3 + B = 120/2 = 60  B + 3B/3 = 60; B + 3B = 60  3  4B = 180; B = 180/4 = 45cm

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Free Mathematics Examination Questions and Answers for SS3  

These Mathematics questions and answers were pulled from our book (Mathematics questions for SS3); Compiled to serve as a reference material...

Free Mathematics Examination Questions and Answers for SS3  

These Mathematics questions and answers were pulled from our book (Mathematics questions for SS3); Compiled to serve as a reference material...

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