1110 ws ec2

Page 137

Detailing of reinforcement J. Arrieta As ,max  0,04 Ac

where Ac is the transverse area of the column. For transverse reinforcement (9.5.3) the minimum diameter ϕt,min and the maximum spacing st,max are:  

1 4

 

t ,min  max  6 mm ; long  st ,max  min  20 long ; bmin ; 400 mm 

The maximum spacing is reduced by a factor 0,60 in zones near a beam or a slab, and in lapped joints if the diameter of bars is greater than 14 mm. In this case a minimum of 3 bars must be present. No longitudinal compression bar can be at a clear distance greater than 150 mm from a restrained bar; restraining is obtained using transverse reinforcement or splices When there is a change of direction in a longitudinal bar, the lateral forces may be ignored if the slope of the change is less or equal to 1:12, otherwise pushing forces have to be considered. 4.2.4.2

Column B2 - case 2

The column considered corresponds to case 2 - flat solid slab. Geometrical data are in figure 20. The materials used have the following properties: o

Concrete:

fck = 30 N/mm2;

γc = 1,50;

o

Steel:

fyk = 500 N/mm2;

γs = 1,15

fctm  0,30fck 2 / 3  2,90 N/mm 2

Applying the actual values of the column to the previous expressions we obtain: o

Longitudinal reinforcement

min  8 mm As,min  max 0,23NEd ;500 mm2  As,max  10000 mm2 o

Transverse reinforcement

t ,min

6 mm if long  24 mm    long if long  24 mm   4

st ,max  min 20long ;400 mm

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