Fig. 3-9 The branch currents within the enclosed area cannot be calculated since no values of the resistors are given. However, KCL applies to the network taken as a single node. Thus, 2:0 3:0 4:0 I ¼ 0
I ¼ 5:0 A
Find the equivalent resistance for the circuit shown in Fig. 3-10.
Fig. 3-10 The two 20- resistors in parallel have an equivalent resistance Req ¼ ½ð20Þð20Þ=ð20 þ 20Þ ¼ 10 . This is in series with the 10- resistor so that their sum is 20 . This in turn is in parallel with the other 20-
resistor so that the overall equivalent resistance is 10 .
Determine the equivalent inductance of the three parallel inductances shown in Fig. 3-11.
Published on May 10, 2013