solution manual for applied petroleum reservoir engineering by craft

Page 112

Δp =

100(3.2)(1500) = 343 psia 0.001127(345)(12 × 300)

for : q = 200 bb1

day

Δp = 686 psia

b)

Vapparent =

q(5.615) 100(5.615) = = 0.156 ft day 3600 A

c) Vactual =

Vapparent

φ (1 − swi )

=

0.156 = 0.587 ft day 0.32(1 − 0.17)

d)

t=

N q

N = Vbφ (1 − S wi ) N = (12 × 300 × 1500)(0.32)(1 − 0.17) = 1434240 ft 3 ÷ 5.615 = 255430.1bb1

t=

25543.1 1year = 2554.3days × ≅ 7 year 100 365days

e)

Δp 343 = = 0.229 psia ft Δx 1500 f) It has no effect. g)

q = qref [1 + c°(Pref − p)] = 100[1 + 65 ×10 −6 (343)] = 102.23 bb1 Δq = 102.23 − 100 = 2.23 bb1

day

h)

Slightly compressib le, q ref = q inlet = 100 bb1

day

107

day


Issuu converts static files into: digital portfolios, online yearbooks, online catalogs, digital photo albums and more. Sign up and create your flipbook.