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Esercizio 6

Dati: Determinare: IT=? E= 12V R1= 1 KΩ R2=R3=R4= 680 Ω R5= 330 Ω

R6=R7= 1 KΩ R8= 720 Ω R9= 1.2 KΩ R10= 330 Ω

Rp= (R6*R7)/(R6+R7)= (1000*1000)/(1000+1000)= 500 Ω Rs= R5+Rp+R8+R9= 330+500+720+1.200= 2750 Ω Rp2= 680/3= 226.6 Ω Rp3= (Rp2*Rs)/(Rp2+Rs)= (226.6*2750)/(226.6+1750)= 209.3 Ω RT= R1+Rp3+R10= 1000+209.3+330=1539.3 Ω IT= VE/RT= 12/1539.3= 7.79 mA


Esercizio di Tecnica Professionale 3