Физика 9кл_Перышкин_Гутник_2001_Ответы и решения

Page 67

<uqbke_gby. t = 0,5 c â‹… 3 = 1,5 c; a =

2 â‹… 0,9 f

(1,5 k )2

f k2; v f k2 â‹… k f k

EZ[hjZlhjgZy jZ[hlZ ‹

Baf_j_gb_ mkdhj_gby k\h[h^gh]h iZ^_gby P_ev jZ[hlu baf_jblv mkdhj_gb_ k\h[h^gh]h iZ^_gby k ihfhsvx ijb[hjZ ^ey bamq_gby ^\b`_gby l_e K\h[h^gh_ iZ^_gb_ l_eZ y\ey_lky jZ\ghmkdhj_gguf ^\b`_gb_f ?keb fu hlimklbf [_a gZqZevghc kdhjhklb dZdhc gb[m^v ]jma gZ mklZgh\d_ hk\h[h`^Z_f aZ`bf b baf_jbf ijhc^_ggh_ bf jZkklhygb_ s b \j_fy t aZ dhlhjh_ [ueh ijhc^_gh wlh jZkklhygb_ lh fu fh`_f 2s jZkkqblZlv mkdhj_gb_ k\h[h^gh]h iZ^_gby ih nhjfme_ g = 2 . t Ijbf_j \uiheg_gby jZ[hlu. <j_fy ^\b`_gby t = nT, c 0,28

<uqbke_gby.

Imlv s ff

Imlv s f

400

0,4

n = 14; t = 14 â‹… 0,02 c = 0,28 c; gwdki =

2 â‹… 0,4 f

(0,28 k )2

Mkdhj_gb_ k\h[h^gh]h iZ^_gby g = 2s/t2 f k2

≈ f k2.

∆g = |gwdki – gl_hj _ _ f k2 ± f k2_ f k2. ∆g 0,4 f k 2 â‹… 100% = â‹…100% ≈ 4,1 %. g 9,8 f k 2

EZ[hjZlhjgZy jZ[hlZ ‹

Bkke_^h\Zgb_ aZ\bkbfhklb i_jbh^Z b qZklhlu k\h[h^guo dhe_[Zgbc gblygh]h fZylgbdZ hl _]h ^ebgu P_ev jZ[hlu \uykgblv dZd aZ\bkyl i_jbh^ b qZklhlZ k\h[h^guo dhe_[Zgbc gblygh]h fZylgbdZ hl _]h ^ebgu Ijb baf_g_gbb ^ebgu gblygh]h fZylgbdZ f_gy_lky _]h qZklhlZ b i_jbh^ < ^Zgghc jZ[hl_ fu ^he`gu hij_^_eblv wlm aZ\bkbfhklv I_jbh^ b qZklhlm hij_^_ey_f ke_^mxsbf h[jZahf Hldehgbf rZjbd fZylgbdZ hl iheh`_gby jZ\gh\_kby gZ g_[hevrmx Zfieblm^m b aZk_q_f \j_fy t \ l_q_gb_ dhlhjh]h fZylgbd kh\_jrbl N . dhe_[Zgbc Lh]^Z i_jbh^ b Zfieblm^m fh`gh ihkqblZlv ih nhjfmeZf

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