ГДЗ.+Алгебра+и+начала+анализа.+10-11кл_10+класс_Алимов%2C+Ко

Page 26

1

1

80. 1) a 9 6 a 3 a = a 9 ⋅ 1

1

4

1 2 + 9

a = a 9 ⋅ a 6⋅3 = a 9 5

1

34 5

2) b12 3 b 4 b = b12 ⋅ 3

1

63 4

1

b = b12 ⋅ b 3−4 = b12

1

1

6

2

1

+

1

= a3 ;

5 12

1

1

= b2 ; 1

4

2

4

1

1

1

4

3) ( ab−2 + (ab) 6 ) ab 4 = (a 3 b 3 + a 6 b 6 )a 6 b 6 = (a 6 b 6 + a 6 b 6 )a 6 b 6 = −

1

4

3

3

1

4

1 1 −

1 1 −

1

1

1

1

1

1

= a 6 b 6 (a 6 + b 6 )a 6 b 6 = a 6 6 b 6 6 (a 2 + b 2 ) = a 0b0 (a 2 + b 2 ) = a 2 + b 2 ; 2

2

1

1

1

1

4) ( 3 a + 3 b)(a 3 + b 3 − 3 ab) = (a 2 + b 2 )(a 3 + b 3 ) × 1

1

1

1

1

1

×((a 3 )2 − a 3 b 3 + (b 3 )2 ) = (a 3 )3 + (b 3 )3 = a + b . 1 1 1 1 81. 1) (1 − 2 b + b ) : (a 2 − b 2 )2 = 1 (a − 2 ab + b) : (a 2 − b 2 )2 =

a

a

a

1 1 = ( a − b )2 : ( a − b )2 = ; a a 1

1

1 1 1 1 1 1 2 2 − − a 3b + ) = (a 3 + b 3 ) : (a 3 − b 3 ⋅ (2a 3 b 3 + a 3 + b 3 ) = b a

2) (a 3 − b 3 ) : (2 + 3 1

1

1

1

1

1

1

1

1

1

= (a 3 + b 3 ) ⋅ a 3 ⋅ b 3 : : (a 3 + b 3 )2 = a 3 ⋅ b 3 : (a 3 + b 3 ) ; 1

3)

9

a4 − a4 1 4

5 4

a −a

b

1 2

3

− b2

1 2

b +b

=

1 − 2

1

8

1 4

4 4

a 4 (1 − a 4 )

1

4

b 2 (1 − b 2 )

1 − 2

a (1 − a )

2 2

=

b (b + 1)

1 − a2 − 1− a

2

b − 1 (1 − a )(1 + a ) (1 − b)(1 + b) = − = 1+ a −1+ b = a + b ; 1+ b 1+ a 1+ b −

1

3

1

1

2

1

1

1

2

a − a 2b a2 − a 3b a 2 − a 2b a 3 − a 3b a 2 (a 2 − b) 4) − = − 1 = 1 1 − 1 1 1 1 1 1 − − − 1 − a − 1b 6 a + a 3 b 1 − a 2 b 2 a 6 + a 3 b 2 a − 2 (a 2 − b 2 ) −

1

3

a 3 (a 3 − b)

1

3

a−b

=

1

1

1

1

a 2 + b2

1

1

1

1

=

1

1

1

(a 2 − b 2 )(a 2 + b 2 ) 1

a 2 + b2

1

1

a 2 − b2

1

1

1

1

( mn ) 7

2

3

2+ 3

7 +1

⋅y

( xy )

a 2 + b2

1

7

−b

3

=

= x

(mn ) (mn ) 7

3

2+ 3

⋅y

7

( xy)

7

⋅y

= =

(mn )

3

2

(mn ) (mn ) ( xy) ( xy)

7

⋅y 7

3

=

1 (mn )2

;

= y;

+ b 3 ) = ((a 2 )2 − (b 3 )2 ) = a 2 2 − b2 3 ; 4) (2a −0,5 − 1 b− 3 )( 1 b− 3 + 2a −0,5 ) = (2a −0,5 )2 − (1 b− 3 )2 = 4a −1 − 1 b−2 9 3 3 3

3) (a

1

(a 2 − b 2 )(a 2 + b 2 )

−a 2 + b 2 = 2b 2 = 2 b .

3 82. 1) m n

2) x

1

a 2 − b2

a 3 (a 6 − b 2 )

1

a−b

)(a

2

26

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3

.

=


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