 Hydrino Theory—BlackLight Process E  1, p  2, m  1, m '  2, V  1 m3 , N  3 X 1019 , T  675 K

225 (5.98)

into Eq. (5.97) is Pm, m ', p  100 kW

(5.99)

corresponding to 100 mW / cm3 . Next, the power due to a reaction involving a catalyst such as an atom to form hydrinos is considered. In the case that the reaction of hydrogen to lower-energy states occurs by the reaction of a catalytic source of energy holes with hydrogen or hydrino atoms, the reaction rate is dependent on the collision rate between the reactants and the efficiency of resonant energy transfer. The hydrogen-or-hydrino-atom/catalyst-atom collision rate per unit volume, Z  a  , for a gas containing nH hydrogen or H  H  Catalyst  p 

aH and velocity vH and nC catalyst atoms per unit volume, each with radius p rCatalyst and velocity vC is given by the general equation of Levine  for the collision rate per unit volume between atoms of two dissimilar gases.

hydrino atoms per unit volume, each with radius

2

Z

a  H  H  Catalyst  p 

a     H  rCatalyst   vH  p  

2

2  vC  

1/ 2

nH nC

(5.100)

The average velocity, vavg , can be calculated from the temperature, T , . 1 3 2 (5.101) mH vavg  kT 2 2 where k is Boltzmann’s constant. Substitution of Eq. (5.90) into Eq. (5.88) gives the collision rate per unit volume, , in terms of the temperature, T . Z a  H  H  Catalyst  p 

Z

a H H  p

  Catalyst 

a     H  rCatalyst  p  

2

1/2

  1 1   3kT    mH mC   

nH nC

(5.102)

The rate of the catalytic reaction, rm , p , to cause a transition reaction is given by the product of the collision rate per unit volume, Z

a  H  H  Catalyst  p 

, the volume, V , and the efficiency, E , of resonant energy transfer given by Eq. (5.87). 1/2

2

rm , p

 1 a   1   E   H  rCatalyst  3kT     p    mH mC  

N H NC V

(5.103)

The power, Pm , p , is given by the product of the rate of the transition, Eq. (5.103), and the energy of the transition, Eq. (5.9). a  Pm, p  E  H  rCatalyst  p  

2

1/2

  1 1   3kT    mH mC   

N H NC  2mp  m 2   2.2 X 1018 W V 

(5.104)

In the exemplary case that the efficiency is E  104 , the power for the Li catalyst reaction given by Eqs. (5.32-5.34) with the substitution of E  104 , p  1, m  3, V  1 m3 , N H  3 X 1021 , N C  3 X 1019 , mC  1.15 X 1026 kg, rC  1.35 X 1010 m, T  675 K

(5.105)

into Eq. (5.104) is Pm, p  144 kW corresponding to 144 mW / cm3 .

(5.106)

# Volume 1: Chapters 1-10

Classical Physics (CP) model of the structure of the electron and the photon used to solve atoms and their states and the subsequent closed-...

# Volume 1: Chapters 1-10

Classical Physics (CP) model of the structure of the electron and the photon used to solve atoms and their states and the subsequent closed-...