2
2
5 ⋅2 2 − 3 ⋅2 ⎛ 5⎞ ⎛ −3 ⎞ x −14 = x −7⋅2 = ( x −7 ) ; x5 = x 2 = ⎜ x 2 ⎟ ; x −3 = x 2 = ⎜ x 2 ⎟ ; ⎝ ⎠ ⎝ ⎠
1 ⋅2
1 ⋅2
1
1
x = x 2 = ( x 0,5 ) ; x 4 = x 8 = ( x 8 ) 2 ; x −1 = x 1
2
1 ⋅2
1
(
x 3 = x 6 = ( x 6 ) 2 ; x −0,9 = x −0,45⋅2 = x −0,45
)
− 1 ⋅2 2 2
;
−1
= ( x 2 )2 ;
3
1 3
x=x =x
1 6
⋅2
( )
= x
1 6
2
3
7
⋅3 3 3 ⎛ 7⎞ 598. y 6 = y 2⋅3 = y 2 ; y −21 = y −7⋅3 = y −7 ; y 7 = y 3 = ⎜ y 3 ⎟ ; ⎝ ⎠
( )
( )
3
1
3
1
3
1
⋅3 ⋅3 − ⋅3 1 ⎛ 1⎞ ⎛ 1⎞ −3 ⎛ −1 ⎞ y = y 3 = ⎜ y 3 ⎟ ; y 2 = y 6 = ⎜ y 6 ⎟ ; y −1,5 = y 2 = y 2 = ⎜ y 2 ⎟ ; ⎝ ⎠ ⎝ ⎠ ⎝ ⎠
y y
−1 3
=y
−2 9
=y
1 − ⋅3 9
−
−1
1
1
1
⋅3
= ( y 9 )3 ; y 0,2 = y 5 = y 15 = ( y 15 )3 ;
2 ⋅3 27
= (y 1
− 2 3 27 ) ;
1
1
1 ⋅3
1
⋅2
1
⋅3
y = y 2 = y 6 = ( y 6 )3 . 1
1 ⋅7
1
599. а) a = a 2 = (a 2 ) 2 ; б) a = a 3 = (a 3 )3 ; в) a = a 7 = (a 7 )7 . 3
1 ⋅3
5
1
600. а) 3 2 = 3 2 = (3 2 )3 ≈ 1,733 ; −1 2
в) 3
⎛ 1 =⎜ 1 ⎜ 2 ⎝3
1 ⋅5
1
б) 3 2 = 3 2 = (3 2 )5 ≈ 1,735 ;
⎞ 1 ⎟≈ ; ⎟ 1,73 ⎠
−5 2
г) 3
1
=
3
5 2
=
1 ⎛ ⎞ ⎜3 ⎟ ⎝ ⎠ 1 2
5
≈
1 . 1, 735
hochy5.ru 1
1
1
1
601. а) 431 2 = ( 4,31 ⋅ 100) 2 = 4,31 2 ⋅ 100 2 = 10α ; 1
1
1
1
б) 43100 2 = ( 4,31 ⋅10000) 2 = 4,31 2 ⋅10000 2 = 100α ; 1
1
1
1
в) 0,0431 2 = ( 4,31 ⋅ 0,01) 2 = 4,31 2 ⋅ 0,01 2 = 0,1α ; 1
1
1
1
г) 0,000431 2 = (4,31 ⋅ 0,0001) 2 = 4,31 2 ⋅ 0,0001 2 = 0,01α . 1
602. а) V = a 3 , следовательно, a = V 3 ; 2
2 ⎛ 1⎞ б) V = a , S = a = ⎜V 3 ⎟ = V 3 ; ⎜ ⎟ ⎝ ⎠ 3
204
2
2
в) P = 6 ⋅ S = 6 ⋅ V 3 .