5.
7. 9.
f(x) = 2x3 + 5x2 – 4x + p habis dibagi x + 1 f(–1) = 2(–1)3 + 5(–1)2 – 4(–1) + p 0 = 7 + p ⇒ p = –7 Sisa: 6x + 8 f(x) = x4 – 5x3 + 2px2 + x + 1 f(–1) = (–1)4 – 5(–1)3 + 2p(–1)2 + (–1) + 1 ⇒ p = –3 1 2
11. HP = {– , –3, 1} 13. –x4 + 3x3 + x2 + x – p dibagi x – 2 tersisa –19 ⇒ p = 33 15. a. b. c.
−(−4) b = =2 a 2 c −18 = = –9 a 2 −d −36 = = –18 a 2
−
Evaluasi Bab 6 Komposisi Fungsi dan Invers Fungsi I. 1. B 3. C 5. C 7. A 9. C 11. B II. 1. a. Yang merupakan fungsi (a) dan (d) b.
13. C
15. D
fungsi (a) domain = {1, 2, 3, 4}, kodomain = {a, b, c, d}, range = {a, c, d} fungsi (d) domain = {1, 2, 3, 4}, kodomain = {a, b, c, d}, range = {b, d}
3.
5.
a.
2x2 + 3
c.
5
b.
2x2 + 8x + 9
d.
1
a. b.
x −9 6 x −2 6
c. d.
Evaluasi Bab 7 Limit Fungsi I. 1. C 3. D 5. B 17. B 19.A II.
7. E
x −5 3 2 − 3
9. B
11. B
1.
a.
1
b.
3 2
c.
1
3.
a.
4
b.
4
c.
−
5.
a.
3
c.
0
e.
1
d.
1 2
b.
2
13. D
15. D
1 2
Kunci Jawaban
269